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Pattern match does not work in bash script

How can I use inverse or negative wildcards when pattern matching in a unix/linux shell?List all files that do not match pattern using lsWhy would I not leave extglob enabled in bash?Get the source directory of a Bash script from within the script itselfHow to check if a string contains a substring in BashHow to check if a program exists from a Bash script?How do I tell if a regular file does not exist in Bash?How do I split a string on a delimiter in Bash?Extract filename and extension in BashHow to concatenate string variables in BashReliable way for a Bash script to get the full path to itselfPassing parameters to a Bash functionEcho newline in Bash prints literal n

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12

1

Using the pattern match !("file1") does not work within a bash script but will work on the command line.

For example:

ls  !("file1"|"file2")

This will list all files in directory except file1 and file2.

When that line is executed in a script this error is displayed:

./script.sh: line 1: syntax error near unexpected token `('

./script.sh: line 1: ` ls  !("file1"|"file2") ' 

Regardless what is used rm -v !("file1"). The same error takes place. What is going on here why does this not work in a script?

linux bash glob extglob

share|improve this question

edited 16 hours ago

James Brown

20.5k42037

asked 17 hours ago

OgdenOgden

634

New contributor

Ogden is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Possible duplicate of How can I use inverse or negative wildcards when pattern matching in a unix/linux shell?, List all files that do not match pattern using ls, etc. And related is Why would I not leave extglob enabled in bash?
  
  – jww
  10 hours ago
  
  
  

  
  
  
  

add a comment | 

12

1

Using the pattern match !("file1") does not work within a bash script but will work on the command line.

For example:

ls  !("file1"|"file2")

This will list all files in directory except file1 and file2.

When that line is executed in a script this error is displayed:

./script.sh: line 1: syntax error near unexpected token `('

./script.sh: line 1: ` ls  !("file1"|"file2") ' 

Regardless what is used rm -v !("file1"). The same error takes place. What is going on here why does this not work in a script?

linux bash glob extglob

share|improve this question

edited 16 hours ago

James Brown

20.5k42037

asked 17 hours ago

OgdenOgden

634

New contributor

Ogden is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Possible duplicate of How can I use inverse or negative wildcards when pattern matching in a unix/linux shell?, List all files that do not match pattern using ls, etc. And related is Why would I not leave extglob enabled in bash?
  
  – jww
  10 hours ago
  
  
  

  
  
  
  

add a comment | 

Using the pattern match !("file1") does not work within a bash script but will work on the command line.

For example:

ls  !("file1"|"file2")

This will list all files in directory except file1 and file2.

When that line is executed in a script this error is displayed:

./script.sh: line 1: syntax error near unexpected token `('

./script.sh: line 1: ` ls  !("file1"|"file2") ' 

Regardless what is used rm -v !("file1"). The same error takes place. What is going on here why does this not work in a script?

linux bash glob extglob

share|improve this question

edited 16 hours ago

James Brown

20.5k42037

asked 17 hours ago

OgdenOgden

634

New contributor

Ogden is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

ls  !("file1"|"file2")

./script.sh: line 1: syntax error near unexpected token `('

./script.sh: line 1: ` ls  !("file1"|"file2") ' 

share|improve this question

edited 16 hours ago

James Brown

20.5k42037

asked 17 hours ago

OgdenOgden

634

New contributor

Ogden is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited 16 hours ago

James Brown

20.5k42037

asked 17 hours ago

OgdenOgden

634

New contributor

Ogden is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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edited 16 hours ago

James Brown

20.5k42037

edited 16 hours ago

James Brown

20.5k42037

asked 17 hours ago

OgdenOgden

634

New contributor

Ogden is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 17 hours ago

OgdenOgden

634

3 Answers
3

active

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votes

12

The extended glob syntax you are trying to use is turned off by default; you have to enable it separately in each script where you want to use it.

shopt -s extglob

Scripts should not use ls though I imagine you were using it merely as a placeholder here.

share|improve this answer

edited 16 hours ago

answered 16 hours ago

tripleeetripleee

96k13133190

add a comment | 

5

Globbing doesn't work that way unless you enable extglob shell opt. Instead, I recommend using find:

find . -maxdepth 1 -not -name '<NAME>' -or -name '<NAME>' -delete

before running this command with -delete ensure the output is correct

share|improve this answer

answered 16 hours ago

RafaelRafael

4,962102339

add a comment | 

3

Method with default settings and no external procs:

for f in *; do [[ $f =~ ^file[12]$ ]] || echo "$f"; done

share|improve this answer

edited 5 hours ago

answered 16 hours ago

vintnesvintnes

765

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12

The extended glob syntax you are trying to use is turned off by default; you have to enable it separately in each script where you want to use it.

shopt -s extglob

Scripts should not use ls though I imagine you were using it merely as a placeholder here.

share|improve this answer

edited 16 hours ago

answered 16 hours ago

tripleeetripleee

96k13133190

add a comment | 

12

The extended glob syntax you are trying to use is turned off by default; you have to enable it separately in each script where you want to use it.

shopt -s extglob

Scripts should not use ls though I imagine you were using it merely as a placeholder here.

share|improve this answer

edited 16 hours ago

answered 16 hours ago

tripleeetripleee

96k13133190

add a comment | 

The extended glob syntax you are trying to use is turned off by default; you have to enable it separately in each script where you want to use it.

shopt -s extglob

Scripts should not use ls though I imagine you were using it merely as a placeholder here.

share|improve this answer

edited 16 hours ago

answered 16 hours ago

tripleeetripleee

96k13133190

shopt -s extglob

share|improve this answer

edited 16 hours ago

answered 16 hours ago

tripleeetripleee

96k13133190

answered 16 hours ago

tripleeetripleee

96k13133190

answered 16 hours ago

tripleeetripleee

96k13133190

5

Globbing doesn't work that way unless you enable extglob shell opt. Instead, I recommend using find:

find . -maxdepth 1 -not -name '<NAME>' -or -name '<NAME>' -delete

before running this command with -delete ensure the output is correct

share|improve this answer

answered 16 hours ago

RafaelRafael

4,962102339

add a comment | 

5

Globbing doesn't work that way unless you enable extglob shell opt. Instead, I recommend using find:

find . -maxdepth 1 -not -name '<NAME>' -or -name '<NAME>' -delete

before running this command with -delete ensure the output is correct

share|improve this answer

answered 16 hours ago

RafaelRafael

4,962102339

add a comment | 

Globbing doesn't work that way unless you enable extglob shell opt. Instead, I recommend using find:

find . -maxdepth 1 -not -name '<NAME>' -or -name '<NAME>' -delete

before running this command with -delete ensure the output is correct

share|improve this answer

answered 16 hours ago

RafaelRafael

4,962102339

find . -maxdepth 1 -not -name '<NAME>' -or -name '<NAME>' -delete

share|improve this answer

answered 16 hours ago

RafaelRafael

4,962102339

answered 16 hours ago

RafaelRafael

4,962102339

answered 16 hours ago

RafaelRafael

4,962102339

3

Method with default settings and no external procs:

for f in *; do [[ $f =~ ^file[12]$ ]] || echo "$f"; done

share|improve this answer

edited 5 hours ago

answered 16 hours ago

vintnesvintnes

765

New contributor

vintnes is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

3

Method with default settings and no external procs:

for f in *; do [[ $f =~ ^file[12]$ ]] || echo "$f"; done

share|improve this answer

edited 5 hours ago

answered 16 hours ago

vintnesvintnes

765

New contributor

vintnes is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

Method with default settings and no external procs:

for f in *; do [[ $f =~ ^file[12]$ ]] || echo "$f"; done

share|improve this answer

edited 5 hours ago

answered 16 hours ago

vintnesvintnes

765

New contributor

vintnes is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

for f in *; do [[ $f =~ ^file[12]$ ]] || echo "$f"; done

share|improve this answer

edited 5 hours ago

answered 16 hours ago

vintnesvintnes

765

New contributor

vintnes is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

answered 16 hours ago

vintnesvintnes

765

New contributor

vintnes is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

answered 16 hours ago

vintnesvintnes

765