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how to sum variables from file in bash

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how to sum variables from file in bash

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1

Hello I need to sum numbers from a file line by line.

The file:

1.0

0.46

0.67

I want to sum, then divide 3.

I currently have:

while IFS= read -r var

do

   x=$(($var + $x)) | bc -l

done < "file.txt"

echo "$x / 3"

My error:

-bash: 1.0 + 0: syntax error: invalid arithmetic operator (error token is ".0 + 0")

bash arithmetic

share|improve this question

edited 2 hours ago

Jesse_b

14.7k33574

asked 2 hours ago

AhmetMelihBaşbuğAhmetMelihBaşbuğ

1175

add a comment | 

1

Hello I need to sum numbers from a file line by line.

The file:

1.0

0.46

0.67

I want to sum, then divide 3.

I currently have:

while IFS= read -r var

do

   x=$(($var + $x)) | bc -l

done < "file.txt"

echo "$x / 3"

My error:

-bash: 1.0 + 0: syntax error: invalid arithmetic operator (error token is ".0 + 0")

bash arithmetic

share|improve this question

edited 2 hours ago

Jesse_b

14.7k33574

asked 2 hours ago

AhmetMelihBaşbuğAhmetMelihBaşbuğ

1175

add a comment | 

Hello I need to sum numbers from a file line by line.

The file:

1.0

0.46

0.67

I want to sum, then divide 3.

I currently have:

while IFS= read -r var

do

   x=$(($var + $x)) | bc -l

done < "file.txt"

echo "$x / 3"

My error:

-bash: 1.0 + 0: syntax error: invalid arithmetic operator (error token is ".0 + 0")

bash arithmetic

share|improve this question

edited 2 hours ago

Jesse_b

14.7k33574

asked 2 hours ago

AhmetMelihBaşbuğAhmetMelihBaşbuğ

1175

1.0

0.46

0.67

while IFS= read -r var

do

   x=$(($var + $x)) | bc -l

done < "file.txt"

echo "$x / 3"

-bash: 1.0 + 0: syntax error: invalid arithmetic operator (error token is ".0 + 0")

share|improve this question

edited 2 hours ago

Jesse_b

14.7k33574

asked 2 hours ago

AhmetMelihBaşbuğAhmetMelihBaşbuğ

1175

share|improve this question

edited 2 hours ago

Jesse_b

14.7k33574

asked 2 hours ago

AhmetMelihBaşbuğAhmetMelihBaşbuğ

1175

edited 2 hours ago

Jesse_b

14.7k33574

edited 2 hours ago

Jesse_b

14.7k33574

asked 2 hours ago

AhmetMelihBaşbuğAhmetMelihBaşbuğ

1175

asked 2 hours ago

AhmetMelihBaşbuğAhmetMelihBaşbuğ

1175

3 Answers
3

active

oldest

votes

3

bash/shell arithmetic can't handle floating point arithmetic. You can accomplish your task using awk:

awk '{sum= sum+$1} END {print sum/3}' file

This will read through your file and add each line to sum then after it completes reading the file it will print sum divided by 3.

share|improve this answer

answered 2 hours ago

Jesse_bJesse_b

14.7k33574

add a comment | 

1

Just for fun

$ paste -sd+ file | dc -e2k0 -f- -e+3/p

.71

share|improve this answer

answered 1 hour ago

steeldriversteeldriver

38.2k45489

add a comment | 

0

Try this:

x=0

while IFS= read -r var; do

    x="$(echo "$var + $x" | bc -l)"

done < "file.txt"

echo "$x / 3" | bc -l

1. 
   x was not defined.


2. You need an echo for bc to work (not mixed bash arithmetic).

share|improve this answer

answered 2 hours ago

FreddyFreddy

2,241210

add a comment | 

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3

bash/shell arithmetic can't handle floating point arithmetic. You can accomplish your task using awk:

awk '{sum= sum+$1} END {print sum/3}' file

This will read through your file and add each line to sum then after it completes reading the file it will print sum divided by 3.

share|improve this answer

answered 2 hours ago

Jesse_bJesse_b

14.7k33574

add a comment | 

3

bash/shell arithmetic can't handle floating point arithmetic. You can accomplish your task using awk:

awk '{sum= sum+$1} END {print sum/3}' file

This will read through your file and add each line to sum then after it completes reading the file it will print sum divided by 3.

share|improve this answer

answered 2 hours ago

Jesse_bJesse_b

14.7k33574

add a comment | 

bash/shell arithmetic can't handle floating point arithmetic. You can accomplish your task using awk:

awk '{sum= sum+$1} END {print sum/3}' file

This will read through your file and add each line to sum then after it completes reading the file it will print sum divided by 3.

share|improve this answer

answered 2 hours ago

Jesse_bJesse_b

14.7k33574

awk '{sum= sum+$1} END {print sum/3}' file

share|improve this answer

answered 2 hours ago

Jesse_bJesse_b

14.7k33574

answered 2 hours ago

Jesse_bJesse_b

14.7k33574

answered 2 hours ago

Jesse_bJesse_b

14.7k33574

1

Just for fun

$ paste -sd+ file | dc -e2k0 -f- -e+3/p

.71

share|improve this answer

answered 1 hour ago

steeldriversteeldriver

38.2k45489

add a comment | 

1

Just for fun

$ paste -sd+ file | dc -e2k0 -f- -e+3/p

.71

share|improve this answer

answered 1 hour ago

steeldriversteeldriver

38.2k45489

add a comment | 

Just for fun

$ paste -sd+ file | dc -e2k0 -f- -e+3/p

.71

share|improve this answer

answered 1 hour ago

steeldriversteeldriver

38.2k45489

$ paste -sd+ file | dc -e2k0 -f- -e+3/p

.71

share|improve this answer

answered 1 hour ago

steeldriversteeldriver

38.2k45489

answered 1 hour ago

steeldriversteeldriver

38.2k45489

answered 1 hour ago

steeldriversteeldriver

38.2k45489

0

Try this:

x=0

while IFS= read -r var; do

    x="$(echo "$var + $x" | bc -l)"

done < "file.txt"

echo "$x / 3" | bc -l

1. 
   x was not defined.


2. You need an echo for bc to work (not mixed bash arithmetic).

share|improve this answer

answered 2 hours ago

FreddyFreddy

2,241210

add a comment | 

0

Try this:

x=0

while IFS= read -r var; do

    x="$(echo "$var + $x" | bc -l)"

done < "file.txt"

echo "$x / 3" | bc -l

1. 
   x was not defined.


2. You need an echo for bc to work (not mixed bash arithmetic).

share|improve this answer

answered 2 hours ago

FreddyFreddy

2,241210

add a comment | 

Try this:

x=0

while IFS= read -r var; do

    x="$(echo "$var + $x" | bc -l)"

done < "file.txt"

echo "$x / 3" | bc -l

1. 
   x was not defined.


2. You need an echo for bc to work (not mixed bash arithmetic).

share|improve this answer

answered 2 hours ago

FreddyFreddy

2,241210

x=0

while IFS= read -r var; do

    x="$(echo "$var + $x" | bc -l)"

done < "file.txt"

echo "$x / 3" | bc -l

share|improve this answer

answered 2 hours ago

FreddyFreddy

2,241210

answered 2 hours ago

FreddyFreddy

2,241210

answered 2 hours ago

FreddyFreddy

2,241210