Why does the Sun have different day lengths, but not the gas giants?Does the Sun rotate?What is the long term...
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Why does the Sun have different day lengths, but not the gas giants?
Does the Sun rotate?What is the long term fate of the gas giants?Why are gas giants colored the way they are?Why don't storms on gas giants move to the poles, like hurricanes on Earth do?Why do the gas giants in the Solar System have comparatively large orbits compared to the inner planets?Why do our clocks not go out of sync with the day over a year?Could binary gas giants have ring and moon systems?Does the Sun have permanent geographical features?Are harmonic relationships among the rotation periods of the planets well known? Are they factors in other planetary phenomena?Modeling planet rotations (time of day, obliqueness, etc.)
$begingroup$
The Sun's rotation period varies from about 25 days at the equator to about 38 days at the poles. As I understand it, this is because the Sun is not solid, and because of the way centripetal force works, the equator must move faster than the poles.
Question: if this works, why do Jupiter/Saturn/Uranus/Neptune have well-defined days? Why don't the equators of these planets rotate faster than the poles as well? For example, Wikipedia's article on Jupiter gives the length of a Jovian day as 9h 55m 30s, which is so precise that it implies Jupiter does not have a rotational period which varies with latitude.
the-sun rotation gas-giants
asked 2 hours ago
AllureAllure
41019
$endgroup$
add a comment |
$begingroup$
The Sun's rotation period varies from about 25 days at the equator to about 38 days at the poles. As I understand it, this is because the Sun is not solid, and because of the way centripetal force works, the equator must move faster than the poles.
Question: if this works, why do Jupiter/Saturn/Uranus/Neptune have well-defined days? Why don't the equators of these planets rotate faster than the poles as well? For example, Wikipedia's article on Jupiter gives the length of a Jovian day as 9h 55m 30s, which is so precise that it implies Jupiter does not have a rotational period which varies with latitude.
the-sun rotation gas-giants
asked 2 hours ago
AllureAllure
41019
$endgroup$
add a comment |
$begingroup$
The Sun's rotation period varies from about 25 days at the equator to about 38 days at the poles. As I understand it, this is because the Sun is not solid, and because of the way centripetal force works, the equator must move faster than the poles.
Question: if this works, why do Jupiter/Saturn/Uranus/Neptune have well-defined days? Why don't the equators of these planets rotate faster than the poles as well? For example, Wikipedia's article on Jupiter gives the length of a Jovian day as 9h 55m 30s, which is so precise that it implies Jupiter does not have a rotational period which varies with latitude.
the-sun rotation gas-giants
asked 2 hours ago
AllureAllure
41019
$endgroup$
The Sun's rotation period varies from about 25 days at the equator to about 38 days at the poles. As I understand it, this is because the Sun is not solid, and because of the way centripetal force works, the equator must move faster than the poles.
Question: if this works, why do Jupiter/Saturn/Uranus/Neptune have well-defined days? Why don't the equators of these planets rotate faster than the poles as well? For example, Wikipedia's article on Jupiter gives the length of a Jovian day as 9h 55m 30s, which is so precise that it implies Jupiter does not have a rotational period which varies with latitude.
the-sun rotation gas-giants
the-sun rotation gas-giants
asked 2 hours ago
AllureAllure
41019
asked 2 hours ago
AllureAllure
41019
asked 2 hours ago
AllureAllure
41019
asked 2 hours ago
AllureAllure
41019
asked 2 hours ago
AllureAllure
41019
41019
add a comment |
add a comment |
1 Answer
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$begingroup$
It's a matter of how "day" is defined.
Wikipedia's article on Jupiter cites this IAU/IAG paper for the length of a Jupiter day. In it, footnote (e) of table I has the following:
The equations for W for Jupiter, Saturn, Uranus and Neptune refer to the rotation of their magnetic fields (System III)
The assumption is that whatever's generating the magnetic field forms a reasonably coherent mass that's rotating at a uniform speed. This produces a periodic variation in the radio emissions of the planet, which is used to measure the rotation speed of that object.
We're reasonably certain the Sun doesn't have a coherent core, so measuring the rotation speed of the magnetic field doesn't provide a useful definition of the Sun's rotation speed.
answered 1 hour ago
MarkMark
1,619619
$endgroup$
add a comment |
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$begingroup$
It's a matter of how "day" is defined.
Wikipedia's article on Jupiter cites this IAU/IAG paper for the length of a Jupiter day. In it, footnote (e) of table I has the following:
The equations for W for Jupiter, Saturn, Uranus and Neptune refer to the rotation of their magnetic fields (System III)
The assumption is that whatever's generating the magnetic field forms a reasonably coherent mass that's rotating at a uniform speed. This produces a periodic variation in the radio emissions of the planet, which is used to measure the rotation speed of that object.
We're reasonably certain the Sun doesn't have a coherent core, so measuring the rotation speed of the magnetic field doesn't provide a useful definition of the Sun's rotation speed.
answered 1 hour ago
MarkMark
1,619619
$endgroup$
add a comment |
$begingroup$
It's a matter of how "day" is defined.
Wikipedia's article on Jupiter cites this IAU/IAG paper for the length of a Jupiter day. In it, footnote (e) of table I has the following:
The equations for W for Jupiter, Saturn, Uranus and Neptune refer to the rotation of their magnetic fields (System III)
The assumption is that whatever's generating the magnetic field forms a reasonably coherent mass that's rotating at a uniform speed. This produces a periodic variation in the radio emissions of the planet, which is used to measure the rotation speed of that object.
We're reasonably certain the Sun doesn't have a coherent core, so measuring the rotation speed of the magnetic field doesn't provide a useful definition of the Sun's rotation speed.
answered 1 hour ago
MarkMark
1,619619
$endgroup$
add a comment |
$begingroup$
It's a matter of how "day" is defined.
Wikipedia's article on Jupiter cites this IAU/IAG paper for the length of a Jupiter day. In it, footnote (e) of table I has the following:
The equations for W for Jupiter, Saturn, Uranus and Neptune refer to the rotation of their magnetic fields (System III)
The assumption is that whatever's generating the magnetic field forms a reasonably coherent mass that's rotating at a uniform speed. This produces a periodic variation in the radio emissions of the planet, which is used to measure the rotation speed of that object.
We're reasonably certain the Sun doesn't have a coherent core, so measuring the rotation speed of the magnetic field doesn't provide a useful definition of the Sun's rotation speed.
answered 1 hour ago
MarkMark
1,619619
$endgroup$
It's a matter of how "day" is defined.
Wikipedia's article on Jupiter cites this IAU/IAG paper for the length of a Jupiter day. In it, footnote (e) of table I has the following:
The equations for W for Jupiter, Saturn, Uranus and Neptune refer to the rotation of their magnetic fields (System III)
The assumption is that whatever's generating the magnetic field forms a reasonably coherent mass that's rotating at a uniform speed. This produces a periodic variation in the radio emissions of the planet, which is used to measure the rotation speed of that object.
We're reasonably certain the Sun doesn't have a coherent core, so measuring the rotation speed of the magnetic field doesn't provide a useful definition of the Sun's rotation speed.
answered 1 hour ago
MarkMark
1,619619
answered 1 hour ago
MarkMark
1,619619
answered 1 hour ago
MarkMark
1,619619
answered 1 hour ago
MarkMark
1,619619
1,619619
add a comment |
add a comment |
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