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Greatest common substring


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4












$begingroup$


Create a program or function which takes a list of strings as input, and outputs the longest string that is a substring of all input strings. If there are several substrings of equal length, and no longer substring, output any one of them.




  • This may mean outputting the empty string.

  • If there are several valid outputs, you may output any one of them. You are not required to give consistent outpput for a given input so long as the output is always valid.

  • There will always be at least one string in the input, but there might not be a non-empty string.

  • You may take input or produce output by any of the default methods.


  • Standard loopholes aren't allowed.

  • This is code-golf - the fewer bytes of code, the better.


Test cases:



[Inputs] -> [Valid outputs (choose one)]



["hello", "'ello"] -> ["ello"]
["very", "much", "different"] -> [""]
["empty", "", "STRING"] -> [""]
["identical", "identical"] -> ["identical"]
["string", "stRIng"] -> ["st", "ng"]
["this one", "is a substring of this one"] -> ["this one"]
["just one"] -> ["just one"]
["", "", ""] -> [""]
["many outputs", "stuptuo ynam"] -> ["m", "a", "n", "y", " ", "o", "u", "t", "p", "s"]
["many inputs", "any inputs", "ny iii", "yanny"] -> ["ny"]









share|improve this question









$endgroup$












  • $begingroup$
    Possible duplicate
    $endgroup$
    – Adám
    1 hour ago










  • $begingroup$
    @Adám That question asks for the longest common subsequence, not substring.
    $endgroup$
    – Doorknob
    1 hour ago










  • $begingroup$
    Will the strings be only alphanumeric, or alphabetic, or only printable-ascii?
    $endgroup$
    – Embodiment of Ignorance
    7 mins ago
















4












$begingroup$


Create a program or function which takes a list of strings as input, and outputs the longest string that is a substring of all input strings. If there are several substrings of equal length, and no longer substring, output any one of them.




  • This may mean outputting the empty string.

  • If there are several valid outputs, you may output any one of them. You are not required to give consistent outpput for a given input so long as the output is always valid.

  • There will always be at least one string in the input, but there might not be a non-empty string.

  • You may take input or produce output by any of the default methods.


  • Standard loopholes aren't allowed.

  • This is code-golf - the fewer bytes of code, the better.


Test cases:



[Inputs] -> [Valid outputs (choose one)]



["hello", "'ello"] -> ["ello"]
["very", "much", "different"] -> [""]
["empty", "", "STRING"] -> [""]
["identical", "identical"] -> ["identical"]
["string", "stRIng"] -> ["st", "ng"]
["this one", "is a substring of this one"] -> ["this one"]
["just one"] -> ["just one"]
["", "", ""] -> [""]
["many outputs", "stuptuo ynam"] -> ["m", "a", "n", "y", " ", "o", "u", "t", "p", "s"]
["many inputs", "any inputs", "ny iii", "yanny"] -> ["ny"]









share|improve this question









$endgroup$












  • $begingroup$
    Possible duplicate
    $endgroup$
    – Adám
    1 hour ago










  • $begingroup$
    @Adám That question asks for the longest common subsequence, not substring.
    $endgroup$
    – Doorknob
    1 hour ago










  • $begingroup$
    Will the strings be only alphanumeric, or alphabetic, or only printable-ascii?
    $endgroup$
    – Embodiment of Ignorance
    7 mins ago














4












4








4





$begingroup$


Create a program or function which takes a list of strings as input, and outputs the longest string that is a substring of all input strings. If there are several substrings of equal length, and no longer substring, output any one of them.




  • This may mean outputting the empty string.

  • If there are several valid outputs, you may output any one of them. You are not required to give consistent outpput for a given input so long as the output is always valid.

  • There will always be at least one string in the input, but there might not be a non-empty string.

  • You may take input or produce output by any of the default methods.


  • Standard loopholes aren't allowed.

  • This is code-golf - the fewer bytes of code, the better.


Test cases:



[Inputs] -> [Valid outputs (choose one)]



["hello", "'ello"] -> ["ello"]
["very", "much", "different"] -> [""]
["empty", "", "STRING"] -> [""]
["identical", "identical"] -> ["identical"]
["string", "stRIng"] -> ["st", "ng"]
["this one", "is a substring of this one"] -> ["this one"]
["just one"] -> ["just one"]
["", "", ""] -> [""]
["many outputs", "stuptuo ynam"] -> ["m", "a", "n", "y", " ", "o", "u", "t", "p", "s"]
["many inputs", "any inputs", "ny iii", "yanny"] -> ["ny"]









share|improve this question









$endgroup$




Create a program or function which takes a list of strings as input, and outputs the longest string that is a substring of all input strings. If there are several substrings of equal length, and no longer substring, output any one of them.




  • This may mean outputting the empty string.

  • If there are several valid outputs, you may output any one of them. You are not required to give consistent outpput for a given input so long as the output is always valid.

  • There will always be at least one string in the input, but there might not be a non-empty string.

  • You may take input or produce output by any of the default methods.


  • Standard loopholes aren't allowed.

  • This is code-golf - the fewer bytes of code, the better.


Test cases:



[Inputs] -> [Valid outputs (choose one)]



["hello", "'ello"] -> ["ello"]
["very", "much", "different"] -> [""]
["empty", "", "STRING"] -> [""]
["identical", "identical"] -> ["identical"]
["string", "stRIng"] -> ["st", "ng"]
["this one", "is a substring of this one"] -> ["this one"]
["just one"] -> ["just one"]
["", "", ""] -> [""]
["many outputs", "stuptuo ynam"] -> ["m", "a", "n", "y", " ", "o", "u", "t", "p", "s"]
["many inputs", "any inputs", "ny iii", "yanny"] -> ["ny"]






code-golf string subsequence






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 1 hour ago









Sara JSara J

1715




1715












  • $begingroup$
    Possible duplicate
    $endgroup$
    – Adám
    1 hour ago










  • $begingroup$
    @Adám That question asks for the longest common subsequence, not substring.
    $endgroup$
    – Doorknob
    1 hour ago










  • $begingroup$
    Will the strings be only alphanumeric, or alphabetic, or only printable-ascii?
    $endgroup$
    – Embodiment of Ignorance
    7 mins ago


















  • $begingroup$
    Possible duplicate
    $endgroup$
    – Adám
    1 hour ago










  • $begingroup$
    @Adám That question asks for the longest common subsequence, not substring.
    $endgroup$
    – Doorknob
    1 hour ago










  • $begingroup$
    Will the strings be only alphanumeric, or alphabetic, or only printable-ascii?
    $endgroup$
    – Embodiment of Ignorance
    7 mins ago
















$begingroup$
Possible duplicate
$endgroup$
– Adám
1 hour ago




$begingroup$
Possible duplicate
$endgroup$
– Adám
1 hour ago












$begingroup$
@Adám That question asks for the longest common subsequence, not substring.
$endgroup$
– Doorknob
1 hour ago




$begingroup$
@Adám That question asks for the longest common subsequence, not substring.
$endgroup$
– Doorknob
1 hour ago












$begingroup$
Will the strings be only alphanumeric, or alphabetic, or only printable-ascii?
$endgroup$
– Embodiment of Ignorance
7 mins ago




$begingroup$
Will the strings be only alphanumeric, or alphabetic, or only printable-ascii?
$endgroup$
– Embodiment of Ignorance
7 mins ago










4 Answers
4






active

oldest

votes


















0












$begingroup$


Jelly, 12 bytes



Ẇ€œ&/LÐṀḢ¹L?


Try it online!



Last four bytes are there because of the requirement to only output one answer.






share|improve this answer









$endgroup$





















    0












    $begingroup$

    Not golfed it much yet but here's my Python 3 answer at 354 bytes:

    EDIT: Now 238 bytes with one space indents and some one-line iterators:

    EDIT: 193 bytes with max function

    EDIT: 189 bytes removed unnecessary list



    def a(b):
    a=();c=list(sum(list(list(d[f:e]for f in range(e))for e in range(len(d)+1)),[])for d in b)
    for i in c[0]:
    if all(i in j for j in c):
    a+=(i,)
    return max(a,key=len)





    share|improve this answer










    New contributor




    Artemis Fowl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






    $endgroup$













    • $begingroup$
      You may want to use single spaces as indentation instead of 4 that seems to shave more than 100 bytes.
      $endgroup$
      – Shieru Asakoto
      43 mins ago










    • $begingroup$
      @ShieruAsakoto Oops yeah.
      $endgroup$
      – Artemis Fowl
      36 mins ago










    • $begingroup$
      135 bytes by simplifying the c declaration and condensing the for loop. I would recommend adding the title and bytecount to the header, or using TIO's formatter to create the body of your post
      $endgroup$
      – Jo King
      7 mins ago












    • $begingroup$
      102 bytes by using set operators instead
      $endgroup$
      – Jo King
      3 mins ago



















    0












    $begingroup$


    JavaScript (Node.js), 114 105 bytes





    a=>(F=(l,n,w=a[0].substr(n,l))=>l?n<0?F(--l,L-l):a.some(y=>y.search(w)<0)?F(l,n-1):w:"")(L=a[0].length,0)


    Try it online!



    Probably still golfable.
    y.indexOf must be used in place of y.search if the strings may contain special regex characters, at the cost of 1 more byte.






    share|improve this answer











    $endgroup$





















      0












      $begingroup$


      Brachylog, 3 bytes



      sᵛw


      Try it online!



      Full program.





      share











      $endgroup$













        Your Answer





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        4 Answers
        4






        active

        oldest

        votes








        4 Answers
        4






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        0












        $begingroup$


        Jelly, 12 bytes



        Ẇ€œ&/LÐṀḢ¹L?


        Try it online!



        Last four bytes are there because of the requirement to only output one answer.






        share|improve this answer









        $endgroup$


















          0












          $begingroup$


          Jelly, 12 bytes



          Ẇ€œ&/LÐṀḢ¹L?


          Try it online!



          Last four bytes are there because of the requirement to only output one answer.






          share|improve this answer









          $endgroup$
















            0












            0








            0





            $begingroup$


            Jelly, 12 bytes



            Ẇ€œ&/LÐṀḢ¹L?


            Try it online!



            Last four bytes are there because of the requirement to only output one answer.






            share|improve this answer









            $endgroup$




            Jelly, 12 bytes



            Ẇ€œ&/LÐṀḢ¹L?


            Try it online!



            Last four bytes are there because of the requirement to only output one answer.







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 54 mins ago









            Nick KennedyNick Kennedy

            92147




            92147























                0












                $begingroup$

                Not golfed it much yet but here's my Python 3 answer at 354 bytes:

                EDIT: Now 238 bytes with one space indents and some one-line iterators:

                EDIT: 193 bytes with max function

                EDIT: 189 bytes removed unnecessary list



                def a(b):
                a=();c=list(sum(list(list(d[f:e]for f in range(e))for e in range(len(d)+1)),[])for d in b)
                for i in c[0]:
                if all(i in j for j in c):
                a+=(i,)
                return max(a,key=len)





                share|improve this answer










                New contributor




                Artemis Fowl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.






                $endgroup$













                • $begingroup$
                  You may want to use single spaces as indentation instead of 4 that seems to shave more than 100 bytes.
                  $endgroup$
                  – Shieru Asakoto
                  43 mins ago










                • $begingroup$
                  @ShieruAsakoto Oops yeah.
                  $endgroup$
                  – Artemis Fowl
                  36 mins ago










                • $begingroup$
                  135 bytes by simplifying the c declaration and condensing the for loop. I would recommend adding the title and bytecount to the header, or using TIO's formatter to create the body of your post
                  $endgroup$
                  – Jo King
                  7 mins ago












                • $begingroup$
                  102 bytes by using set operators instead
                  $endgroup$
                  – Jo King
                  3 mins ago
















                0












                $begingroup$

                Not golfed it much yet but here's my Python 3 answer at 354 bytes:

                EDIT: Now 238 bytes with one space indents and some one-line iterators:

                EDIT: 193 bytes with max function

                EDIT: 189 bytes removed unnecessary list



                def a(b):
                a=();c=list(sum(list(list(d[f:e]for f in range(e))for e in range(len(d)+1)),[])for d in b)
                for i in c[0]:
                if all(i in j for j in c):
                a+=(i,)
                return max(a,key=len)





                share|improve this answer










                New contributor




                Artemis Fowl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.






                $endgroup$













                • $begingroup$
                  You may want to use single spaces as indentation instead of 4 that seems to shave more than 100 bytes.
                  $endgroup$
                  – Shieru Asakoto
                  43 mins ago










                • $begingroup$
                  @ShieruAsakoto Oops yeah.
                  $endgroup$
                  – Artemis Fowl
                  36 mins ago










                • $begingroup$
                  135 bytes by simplifying the c declaration and condensing the for loop. I would recommend adding the title and bytecount to the header, or using TIO's formatter to create the body of your post
                  $endgroup$
                  – Jo King
                  7 mins ago












                • $begingroup$
                  102 bytes by using set operators instead
                  $endgroup$
                  – Jo King
                  3 mins ago














                0












                0








                0





                $begingroup$

                Not golfed it much yet but here's my Python 3 answer at 354 bytes:

                EDIT: Now 238 bytes with one space indents and some one-line iterators:

                EDIT: 193 bytes with max function

                EDIT: 189 bytes removed unnecessary list



                def a(b):
                a=();c=list(sum(list(list(d[f:e]for f in range(e))for e in range(len(d)+1)),[])for d in b)
                for i in c[0]:
                if all(i in j for j in c):
                a+=(i,)
                return max(a,key=len)





                share|improve this answer










                New contributor




                Artemis Fowl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.






                $endgroup$



                Not golfed it much yet but here's my Python 3 answer at 354 bytes:

                EDIT: Now 238 bytes with one space indents and some one-line iterators:

                EDIT: 193 bytes with max function

                EDIT: 189 bytes removed unnecessary list



                def a(b):
                a=();c=list(sum(list(list(d[f:e]for f in range(e))for e in range(len(d)+1)),[])for d in b)
                for i in c[0]:
                if all(i in j for j in c):
                a+=(i,)
                return max(a,key=len)






                share|improve this answer










                New contributor




                Artemis Fowl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.









                share|improve this answer



                share|improve this answer








                edited 11 mins ago





















                New contributor




                Artemis Fowl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.









                answered 47 mins ago









                Artemis FowlArtemis Fowl

                1013




                1013




                New contributor




                Artemis Fowl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.





                New contributor





                Artemis Fowl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.






                Artemis Fowl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.












                • $begingroup$
                  You may want to use single spaces as indentation instead of 4 that seems to shave more than 100 bytes.
                  $endgroup$
                  – Shieru Asakoto
                  43 mins ago










                • $begingroup$
                  @ShieruAsakoto Oops yeah.
                  $endgroup$
                  – Artemis Fowl
                  36 mins ago










                • $begingroup$
                  135 bytes by simplifying the c declaration and condensing the for loop. I would recommend adding the title and bytecount to the header, or using TIO's formatter to create the body of your post
                  $endgroup$
                  – Jo King
                  7 mins ago












                • $begingroup$
                  102 bytes by using set operators instead
                  $endgroup$
                  – Jo King
                  3 mins ago


















                • $begingroup$
                  You may want to use single spaces as indentation instead of 4 that seems to shave more than 100 bytes.
                  $endgroup$
                  – Shieru Asakoto
                  43 mins ago










                • $begingroup$
                  @ShieruAsakoto Oops yeah.
                  $endgroup$
                  – Artemis Fowl
                  36 mins ago










                • $begingroup$
                  135 bytes by simplifying the c declaration and condensing the for loop. I would recommend adding the title and bytecount to the header, or using TIO's formatter to create the body of your post
                  $endgroup$
                  – Jo King
                  7 mins ago












                • $begingroup$
                  102 bytes by using set operators instead
                  $endgroup$
                  – Jo King
                  3 mins ago
















                $begingroup$
                You may want to use single spaces as indentation instead of 4 that seems to shave more than 100 bytes.
                $endgroup$
                – Shieru Asakoto
                43 mins ago




                $begingroup$
                You may want to use single spaces as indentation instead of 4 that seems to shave more than 100 bytes.
                $endgroup$
                – Shieru Asakoto
                43 mins ago












                $begingroup$
                @ShieruAsakoto Oops yeah.
                $endgroup$
                – Artemis Fowl
                36 mins ago




                $begingroup$
                @ShieruAsakoto Oops yeah.
                $endgroup$
                – Artemis Fowl
                36 mins ago












                $begingroup$
                135 bytes by simplifying the c declaration and condensing the for loop. I would recommend adding the title and bytecount to the header, or using TIO's formatter to create the body of your post
                $endgroup$
                – Jo King
                7 mins ago






                $begingroup$
                135 bytes by simplifying the c declaration and condensing the for loop. I would recommend adding the title and bytecount to the header, or using TIO's formatter to create the body of your post
                $endgroup$
                – Jo King
                7 mins ago














                $begingroup$
                102 bytes by using set operators instead
                $endgroup$
                – Jo King
                3 mins ago




                $begingroup$
                102 bytes by using set operators instead
                $endgroup$
                – Jo King
                3 mins ago











                0












                $begingroup$


                JavaScript (Node.js), 114 105 bytes





                a=>(F=(l,n,w=a[0].substr(n,l))=>l?n<0?F(--l,L-l):a.some(y=>y.search(w)<0)?F(l,n-1):w:"")(L=a[0].length,0)


                Try it online!



                Probably still golfable.
                y.indexOf must be used in place of y.search if the strings may contain special regex characters, at the cost of 1 more byte.






                share|improve this answer











                $endgroup$


















                  0












                  $begingroup$


                  JavaScript (Node.js), 114 105 bytes





                  a=>(F=(l,n,w=a[0].substr(n,l))=>l?n<0?F(--l,L-l):a.some(y=>y.search(w)<0)?F(l,n-1):w:"")(L=a[0].length,0)


                  Try it online!



                  Probably still golfable.
                  y.indexOf must be used in place of y.search if the strings may contain special regex characters, at the cost of 1 more byte.






                  share|improve this answer











                  $endgroup$
















                    0












                    0








                    0





                    $begingroup$


                    JavaScript (Node.js), 114 105 bytes





                    a=>(F=(l,n,w=a[0].substr(n,l))=>l?n<0?F(--l,L-l):a.some(y=>y.search(w)<0)?F(l,n-1):w:"")(L=a[0].length,0)


                    Try it online!



                    Probably still golfable.
                    y.indexOf must be used in place of y.search if the strings may contain special regex characters, at the cost of 1 more byte.






                    share|improve this answer











                    $endgroup$




                    JavaScript (Node.js), 114 105 bytes





                    a=>(F=(l,n,w=a[0].substr(n,l))=>l?n<0?F(--l,L-l):a.some(y=>y.search(w)<0)?F(l,n-1):w:"")(L=a[0].length,0)


                    Try it online!



                    Probably still golfable.
                    y.indexOf must be used in place of y.search if the strings may contain special regex characters, at the cost of 1 more byte.







                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited 6 mins ago

























                    answered 16 mins ago









                    Shieru AsakotoShieru Asakoto

                    2,750317




                    2,750317























                        0












                        $begingroup$


                        Brachylog, 3 bytes



                        sᵛw


                        Try it online!



                        Full program.





                        share











                        $endgroup$


















                          0












                          $begingroup$


                          Brachylog, 3 bytes



                          sᵛw


                          Try it online!



                          Full program.





                          share











                          $endgroup$
















                            0












                            0








                            0





                            $begingroup$


                            Brachylog, 3 bytes



                            sᵛw


                            Try it online!



                            Full program.





                            share











                            $endgroup$




                            Brachylog, 3 bytes



                            sᵛw


                            Try it online!



                            Full program.






                            share













                            share


                            share








                            answered 3 mins ago


























                            community wiki





                            ais523































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