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0

1

I am facing problems with the following diagram given into image:

How may I code for it in overleaf code? by using tikz package

begin{tikzpicture} 

draw[black, thick] (0,0) rectangle (3,2) node[pos=.5] {text};

end{tikzpicture}

tikz-pgf

share|improve this question

edited 2 mins ago

LianTze Lim

8,69323066

asked 8 hours ago

SANJAY GUPTASANJAY GUPTA

232

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Maybe some starting point: tex.stackexchange.com/questions/350513/…
  
  – samcarter
  7 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  ok, thank you very much.
  
  – SANJAY GUPTA
  7 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The next time you can probably edit your previous question in place to create a new one that is an "edit" of the first one ;)
  
  – Kpym
  6 hours ago
  

  
  
  
  

add a comment | 

0

1

I am facing problems with the following diagram given into image:

How may I code for it in overleaf code? by using tikz package

begin{tikzpicture} 

draw[black, thick] (0,0) rectangle (3,2) node[pos=.5] {text};

end{tikzpicture}

tikz-pgf

share|improve this question

edited 2 mins ago

LianTze Lim

8,69323066

asked 8 hours ago

SANJAY GUPTASANJAY GUPTA

232

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Maybe some starting point: tex.stackexchange.com/questions/350513/…
  
  – samcarter
  7 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  ok, thank you very much.
  
  – SANJAY GUPTA
  7 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The next time you can probably edit your previous question in place to create a new one that is an "edit" of the first one ;)
  
  – Kpym
  6 hours ago
  

  
  
  
  

add a comment | 

I am facing problems with the following diagram given into image:

How may I code for it in overleaf code? by using tikz package

begin{tikzpicture} 

draw[black, thick] (0,0) rectangle (3,2) node[pos=.5] {text};

end{tikzpicture}

tikz-pgf

share|improve this question

edited 2 mins ago

LianTze Lim

8,69323066

asked 8 hours ago

SANJAY GUPTASANJAY GUPTA

232

begin{tikzpicture} 

draw[black, thick] (0,0) rectangle (3,2) node[pos=.5] {text};

end{tikzpicture}

share|improve this question

edited 2 mins ago

LianTze Lim

8,69323066

asked 8 hours ago

SANJAY GUPTASANJAY GUPTA

232

share|improve this question

edited 2 mins ago

LianTze Lim

8,69323066

asked 8 hours ago

SANJAY GUPTASANJAY GUPTA

232

edited 2 mins ago

LianTze Lim

8,69323066

edited 2 mins ago

LianTze Lim

8,69323066

asked 8 hours ago

SANJAY GUPTASANJAY GUPTA

232

asked 8 hours ago

SANJAY GUPTASANJAY GUPTA

232

1 Answer
1

active

oldest

votes

1

This is to give you a start. For each of the features you will find many posts on this site, perhaps not yet in precisely this combination.

documentclass[border=3.14mm,tikz]{standalone}

usetikzlibrary{chains,positioning,calc,shapes.geometric}

begin{document}

begin{tikzpicture}[font=sffamily,boxed/.style={minimum width=3cm,minimum height=2cm,draw,thick}] 

 begin{scope}[local bounding box=upper]

  begin{scope}[start chain=1 going below,every join/.style={-latex,thick},frm/.style={boxed,on chain=1,join}]

   node[on chain=1](n0) {Training data set};

   node[frm](n1) {abc};

   node[frm](n2) {abc};

   node[frm](n3) {abc};

   node[frm](n4) {abc};

  end{scope} 

  node[boxed,right=3cm of n1] (n5) {abc}; 

  node[boxed,right=3mm of n2] (n6) {abc}; 

  node at (n0-|n6) (n7) {Testing data set};

  node[boxed,right=1cm of n3] (n8) {abc}; 

  end{scope}

  draw let p1=($(upper.east)-(upper.west)$) in 

   node[boxed,below=5mm of upper,minimum width=x1] (n9) {abc};

  node[below=3mm of n9,

    trapezium,trapezium left angle=60,trapezium right angle=120,

    minimum width=3cm,minimum height=1cm,draw,thick] (n10) {abc};

  begin{scope}[every edge/.style={draw,-latex,thick}]  

   path (n7) edge (n6) (n6.-140) edge (n9.north-|n6.-140) 

   (n1) edge (n5) (n5) edge (n9.north-|n5.south)

   (n6.south-|n8) edge (n8) (n8) edge (n9.north-|n8.south)

   (n4) edge (n9.north-|n4) (n9) edge (n10);

  end{scope}

end{tikzpicture}

end{document}

share|improve this answer

answered 6 hours ago

marmotmarmot

112k5144270

add a comment | 

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1

This is to give you a start. For each of the features you will find many posts on this site, perhaps not yet in precisely this combination.

documentclass[border=3.14mm,tikz]{standalone}

usetikzlibrary{chains,positioning,calc,shapes.geometric}

begin{document}

begin{tikzpicture}[font=sffamily,boxed/.style={minimum width=3cm,minimum height=2cm,draw,thick}] 

 begin{scope}[local bounding box=upper]

  begin{scope}[start chain=1 going below,every join/.style={-latex,thick},frm/.style={boxed,on chain=1,join}]

   node[on chain=1](n0) {Training data set};

   node[frm](n1) {abc};

   node[frm](n2) {abc};

   node[frm](n3) {abc};

   node[frm](n4) {abc};

  end{scope} 

  node[boxed,right=3cm of n1] (n5) {abc}; 

  node[boxed,right=3mm of n2] (n6) {abc}; 

  node at (n0-|n6) (n7) {Testing data set};

  node[boxed,right=1cm of n3] (n8) {abc}; 

  end{scope}

  draw let p1=($(upper.east)-(upper.west)$) in 

   node[boxed,below=5mm of upper,minimum width=x1] (n9) {abc};

  node[below=3mm of n9,

    trapezium,trapezium left angle=60,trapezium right angle=120,

    minimum width=3cm,minimum height=1cm,draw,thick] (n10) {abc};

  begin{scope}[every edge/.style={draw,-latex,thick}]  

   path (n7) edge (n6) (n6.-140) edge (n9.north-|n6.-140) 

   (n1) edge (n5) (n5) edge (n9.north-|n5.south)

   (n6.south-|n8) edge (n8) (n8) edge (n9.north-|n8.south)

   (n4) edge (n9.north-|n4) (n9) edge (n10);

  end{scope}

end{tikzpicture}

end{document}

share|improve this answer

answered 6 hours ago

marmotmarmot

112k5144270

add a comment | 

1

This is to give you a start. For each of the features you will find many posts on this site, perhaps not yet in precisely this combination.

documentclass[border=3.14mm,tikz]{standalone}

usetikzlibrary{chains,positioning,calc,shapes.geometric}

begin{document}

begin{tikzpicture}[font=sffamily,boxed/.style={minimum width=3cm,minimum height=2cm,draw,thick}] 

 begin{scope}[local bounding box=upper]

  begin{scope}[start chain=1 going below,every join/.style={-latex,thick},frm/.style={boxed,on chain=1,join}]

   node[on chain=1](n0) {Training data set};

   node[frm](n1) {abc};

   node[frm](n2) {abc};

   node[frm](n3) {abc};

   node[frm](n4) {abc};

  end{scope} 

  node[boxed,right=3cm of n1] (n5) {abc}; 

  node[boxed,right=3mm of n2] (n6) {abc}; 

  node at (n0-|n6) (n7) {Testing data set};

  node[boxed,right=1cm of n3] (n8) {abc}; 

  end{scope}

  draw let p1=($(upper.east)-(upper.west)$) in 

   node[boxed,below=5mm of upper,minimum width=x1] (n9) {abc};

  node[below=3mm of n9,

    trapezium,trapezium left angle=60,trapezium right angle=120,

    minimum width=3cm,minimum height=1cm,draw,thick] (n10) {abc};

  begin{scope}[every edge/.style={draw,-latex,thick}]  

   path (n7) edge (n6) (n6.-140) edge (n9.north-|n6.-140) 

   (n1) edge (n5) (n5) edge (n9.north-|n5.south)

   (n6.south-|n8) edge (n8) (n8) edge (n9.north-|n8.south)

   (n4) edge (n9.north-|n4) (n9) edge (n10);

  end{scope}

end{tikzpicture}

end{document}

share|improve this answer

answered 6 hours ago

marmotmarmot

112k5144270

add a comment | 

This is to give you a start. For each of the features you will find many posts on this site, perhaps not yet in precisely this combination.

documentclass[border=3.14mm,tikz]{standalone}

usetikzlibrary{chains,positioning,calc,shapes.geometric}

begin{document}

begin{tikzpicture}[font=sffamily,boxed/.style={minimum width=3cm,minimum height=2cm,draw,thick}] 

 begin{scope}[local bounding box=upper]

  begin{scope}[start chain=1 going below,every join/.style={-latex,thick},frm/.style={boxed,on chain=1,join}]

   node[on chain=1](n0) {Training data set};

   node[frm](n1) {abc};

   node[frm](n2) {abc};

   node[frm](n3) {abc};

   node[frm](n4) {abc};

  end{scope} 

  node[boxed,right=3cm of n1] (n5) {abc}; 

  node[boxed,right=3mm of n2] (n6) {abc}; 

  node at (n0-|n6) (n7) {Testing data set};

  node[boxed,right=1cm of n3] (n8) {abc}; 

  end{scope}

  draw let p1=($(upper.east)-(upper.west)$) in 

   node[boxed,below=5mm of upper,minimum width=x1] (n9) {abc};

  node[below=3mm of n9,

    trapezium,trapezium left angle=60,trapezium right angle=120,

    minimum width=3cm,minimum height=1cm,draw,thick] (n10) {abc};

  begin{scope}[every edge/.style={draw,-latex,thick}]  

   path (n7) edge (n6) (n6.-140) edge (n9.north-|n6.-140) 

   (n1) edge (n5) (n5) edge (n9.north-|n5.south)

   (n6.south-|n8) edge (n8) (n8) edge (n9.north-|n8.south)

   (n4) edge (n9.north-|n4) (n9) edge (n10);

  end{scope}

end{tikzpicture}

end{document}

share|improve this answer

answered 6 hours ago

marmotmarmot

112k5144270

documentclass[border=3.14mm,tikz]{standalone}

usetikzlibrary{chains,positioning,calc,shapes.geometric}

begin{document}

begin{tikzpicture}[font=sffamily,boxed/.style={minimum width=3cm,minimum height=2cm,draw,thick}] 

 begin{scope}[local bounding box=upper]

  begin{scope}[start chain=1 going below,every join/.style={-latex,thick},frm/.style={boxed,on chain=1,join}]

   node[on chain=1](n0) {Training data set};

   node[frm](n1) {abc};

   node[frm](n2) {abc};

   node[frm](n3) {abc};

   node[frm](n4) {abc};

  end{scope} 

  node[boxed,right=3cm of n1] (n5) {abc}; 

  node[boxed,right=3mm of n2] (n6) {abc}; 

  node at (n0-|n6) (n7) {Testing data set};

  node[boxed,right=1cm of n3] (n8) {abc}; 

  end{scope}

  draw let p1=($(upper.east)-(upper.west)$) in 

   node[boxed,below=5mm of upper,minimum width=x1] (n9) {abc};

  node[below=3mm of n9,

    trapezium,trapezium left angle=60,trapezium right angle=120,

    minimum width=3cm,minimum height=1cm,draw,thick] (n10) {abc};

  begin{scope}[every edge/.style={draw,-latex,thick}]  

   path (n7) edge (n6) (n6.-140) edge (n9.north-|n6.-140) 

   (n1) edge (n5) (n5) edge (n9.north-|n5.south)

   (n6.south-|n8) edge (n8) (n8) edge (n9.north-|n8.south)

   (n4) edge (n9.north-|n4) (n9) edge (n10);

  end{scope}

end{tikzpicture}

end{document}

share|improve this answer

answered 6 hours ago

marmotmarmot

112k5144270

answered 6 hours ago

marmotmarmot

112k5144270

answered 6 hours ago

marmotmarmot

112k5144270