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I have two classes; Salary
that is intended to hold information and calculations regarding the salary of an employee and Employee
that has an object of type class Salary
and some members like name and address of the employee...
What I want to do is to prevent
class Salary
from being instantiated and onlyclass Employee
can instantiate it. So I declared the constructors ofSalary
private and madeEmployee
friend ofSalary
. But I get errors:
class Employee;
class Salary {
public:
private:
Salary() : revenue_{}, cost_{} {}
Salary(int x, int y) : revenue_{ x },
cost_{ y } {
}
int revenue_, cost_;
friend class Employee;
};
class Employee {
public:
std::string name_;
Salary sal;
};
int main(){
Employee emp{}; // "Salary::Salary()" is inaccessible
}
The problem raised for me if I forward declare
main
:
int main(int, char*[]);
And make
main
friend ofclass Salary
so in Salary:
class Salary {
//...
friend int main(int argc, char* argv[]);
};
Now the program compiles correctly!
*** Another thing in main if I declare an object this way:
Employee emp; // ok
Employee emp{}; // error?
c++ constructor friend-class
add a comment |
I have two classes; Salary
that is intended to hold information and calculations regarding the salary of an employee and Employee
that has an object of type class Salary
and some members like name and address of the employee...
What I want to do is to prevent
class Salary
from being instantiated and onlyclass Employee
can instantiate it. So I declared the constructors ofSalary
private and madeEmployee
friend ofSalary
. But I get errors:
class Employee;
class Salary {
public:
private:
Salary() : revenue_{}, cost_{} {}
Salary(int x, int y) : revenue_{ x },
cost_{ y } {
}
int revenue_, cost_;
friend class Employee;
};
class Employee {
public:
std::string name_;
Salary sal;
};
int main(){
Employee emp{}; // "Salary::Salary()" is inaccessible
}
The problem raised for me if I forward declare
main
:
int main(int, char*[]);
And make
main
friend ofclass Salary
so in Salary:
class Salary {
//...
friend int main(int argc, char* argv[]);
};
Now the program compiles correctly!
*** Another thing in main if I declare an object this way:
Employee emp; // ok
Employee emp{}; // error?
c++ constructor friend-class
Why are you makingSalary
's constructor private? It seems like there are contexts when you'd want to useSalary
outside ofEmployee
– J. Antonio Perez
7 mins ago
add a comment |
I have two classes; Salary
that is intended to hold information and calculations regarding the salary of an employee and Employee
that has an object of type class Salary
and some members like name and address of the employee...
What I want to do is to prevent
class Salary
from being instantiated and onlyclass Employee
can instantiate it. So I declared the constructors ofSalary
private and madeEmployee
friend ofSalary
. But I get errors:
class Employee;
class Salary {
public:
private:
Salary() : revenue_{}, cost_{} {}
Salary(int x, int y) : revenue_{ x },
cost_{ y } {
}
int revenue_, cost_;
friend class Employee;
};
class Employee {
public:
std::string name_;
Salary sal;
};
int main(){
Employee emp{}; // "Salary::Salary()" is inaccessible
}
The problem raised for me if I forward declare
main
:
int main(int, char*[]);
And make
main
friend ofclass Salary
so in Salary:
class Salary {
//...
friend int main(int argc, char* argv[]);
};
Now the program compiles correctly!
*** Another thing in main if I declare an object this way:
Employee emp; // ok
Employee emp{}; // error?
c++ constructor friend-class
I have two classes; Salary
that is intended to hold information and calculations regarding the salary of an employee and Employee
that has an object of type class Salary
and some members like name and address of the employee...
What I want to do is to prevent
class Salary
from being instantiated and onlyclass Employee
can instantiate it. So I declared the constructors ofSalary
private and madeEmployee
friend ofSalary
. But I get errors:
class Employee;
class Salary {
public:
private:
Salary() : revenue_{}, cost_{} {}
Salary(int x, int y) : revenue_{ x },
cost_{ y } {
}
int revenue_, cost_;
friend class Employee;
};
class Employee {
public:
std::string name_;
Salary sal;
};
int main(){
Employee emp{}; // "Salary::Salary()" is inaccessible
}
The problem raised for me if I forward declare
main
:
int main(int, char*[]);
And make
main
friend ofclass Salary
so in Salary:
class Salary {
//...
friend int main(int argc, char* argv[]);
};
Now the program compiles correctly!
*** Another thing in main if I declare an object this way:
Employee emp; // ok
Employee emp{}; // error?
c++ constructor friend-class
c++ constructor friend-class
edited 43 mins ago
Syfu_H
asked 50 mins ago
Syfu_HSyfu_H
35518
35518
Why are you makingSalary
's constructor private? It seems like there are contexts when you'd want to useSalary
outside ofEmployee
– J. Antonio Perez
7 mins ago
add a comment |
Why are you makingSalary
's constructor private? It seems like there are contexts when you'd want to useSalary
outside ofEmployee
– J. Antonio Perez
7 mins ago
Why are you making
Salary
's constructor private? It seems like there are contexts when you'd want to use Salary
outside of Employee
– J. Antonio Perez
7 mins ago
Why are you making
Salary
's constructor private? It seems like there are contexts when you'd want to use Salary
outside of Employee
– J. Antonio Perez
7 mins ago
add a comment |
4 Answers
4
active
oldest
votes
Because you don't provide a constructor for Employee
the braces in your initialization Employee emp{};
will perform an aggregate initialization, which essentially means that each member is initialized one-by-one using the default rules, in the context of main()
. Since main()
doesn't have access to the Salary
constructor, it fails.
As others have pointed out, adding an Employee
default constructor will resolve your problem:
class Employee {
public:
Employee() = default;
std::string name_;
Salary sal;
};
1
I'm trying on MSVS and onlyEmployee() {};
allowsEmployee emp{};
to compile. Clang seems to acceptEmployee() = default;
, but then again, Clang seems to accept having no default constructor here.
– wally
14 mins ago
GCC does the same as Clang, and doesn't need a default constructor to compile in this case. Have you tried this answer on any specific compiler?
– wally
3 mins ago
add a comment |
You have to explicitly declare the default constructor of class Employee
thus you can initialize an abject via uniform initialization
:
class Employee {
public:
Employee(){} // add it
std::string name_;
Salary sal;
};
int main(){
Employee emp{}; // now this should compile
}
add a comment |
You need Employee
's ctor to call the ctor of Salary
. The ctor of Salary
is not accessible from main
.
eg:
class Employee {
public:
Employee() : sal() {}
public:
std::string name_;
Salary sal;
};
add a comment |
If you erase the "{}" after "Employee emp" in your main() function it compiles just fine (gcc 7.3.1 on Fedora 27).
1
I recommend explaining why.
– user4581301
41 mins ago
Yes. Not onyl GCC but also MSVC14 also compilesEmployee emp;
but why?
– Syfu_H
39 mins ago
@Syfu_H Value Initialization. And I could be mistaken here (been caught on this in the past), but the Value Initialization is being replaced by Aggregate Initialization
– user4581301
31 mins ago
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
Because you don't provide a constructor for Employee
the braces in your initialization Employee emp{};
will perform an aggregate initialization, which essentially means that each member is initialized one-by-one using the default rules, in the context of main()
. Since main()
doesn't have access to the Salary
constructor, it fails.
As others have pointed out, adding an Employee
default constructor will resolve your problem:
class Employee {
public:
Employee() = default;
std::string name_;
Salary sal;
};
1
I'm trying on MSVS and onlyEmployee() {};
allowsEmployee emp{};
to compile. Clang seems to acceptEmployee() = default;
, but then again, Clang seems to accept having no default constructor here.
– wally
14 mins ago
GCC does the same as Clang, and doesn't need a default constructor to compile in this case. Have you tried this answer on any specific compiler?
– wally
3 mins ago
add a comment |
Because you don't provide a constructor for Employee
the braces in your initialization Employee emp{};
will perform an aggregate initialization, which essentially means that each member is initialized one-by-one using the default rules, in the context of main()
. Since main()
doesn't have access to the Salary
constructor, it fails.
As others have pointed out, adding an Employee
default constructor will resolve your problem:
class Employee {
public:
Employee() = default;
std::string name_;
Salary sal;
};
1
I'm trying on MSVS and onlyEmployee() {};
allowsEmployee emp{};
to compile. Clang seems to acceptEmployee() = default;
, but then again, Clang seems to accept having no default constructor here.
– wally
14 mins ago
GCC does the same as Clang, and doesn't need a default constructor to compile in this case. Have you tried this answer on any specific compiler?
– wally
3 mins ago
add a comment |
Because you don't provide a constructor for Employee
the braces in your initialization Employee emp{};
will perform an aggregate initialization, which essentially means that each member is initialized one-by-one using the default rules, in the context of main()
. Since main()
doesn't have access to the Salary
constructor, it fails.
As others have pointed out, adding an Employee
default constructor will resolve your problem:
class Employee {
public:
Employee() = default;
std::string name_;
Salary sal;
};
Because you don't provide a constructor for Employee
the braces in your initialization Employee emp{};
will perform an aggregate initialization, which essentially means that each member is initialized one-by-one using the default rules, in the context of main()
. Since main()
doesn't have access to the Salary
constructor, it fails.
As others have pointed out, adding an Employee
default constructor will resolve your problem:
class Employee {
public:
Employee() = default;
std::string name_;
Salary sal;
};
edited 16 mins ago
answered 31 mins ago
zdanzdan
22.1k34864
22.1k34864
1
I'm trying on MSVS and onlyEmployee() {};
allowsEmployee emp{};
to compile. Clang seems to acceptEmployee() = default;
, but then again, Clang seems to accept having no default constructor here.
– wally
14 mins ago
GCC does the same as Clang, and doesn't need a default constructor to compile in this case. Have you tried this answer on any specific compiler?
– wally
3 mins ago
add a comment |
1
I'm trying on MSVS and onlyEmployee() {};
allowsEmployee emp{};
to compile. Clang seems to acceptEmployee() = default;
, but then again, Clang seems to accept having no default constructor here.
– wally
14 mins ago
GCC does the same as Clang, and doesn't need a default constructor to compile in this case. Have you tried this answer on any specific compiler?
– wally
3 mins ago
1
1
I'm trying on MSVS and only
Employee() {};
allows Employee emp{};
to compile. Clang seems to accept Employee() = default;
, but then again, Clang seems to accept having no default constructor here.– wally
14 mins ago
I'm trying on MSVS and only
Employee() {};
allows Employee emp{};
to compile. Clang seems to accept Employee() = default;
, but then again, Clang seems to accept having no default constructor here.– wally
14 mins ago
GCC does the same as Clang, and doesn't need a default constructor to compile in this case. Have you tried this answer on any specific compiler?
– wally
3 mins ago
GCC does the same as Clang, and doesn't need a default constructor to compile in this case. Have you tried this answer on any specific compiler?
– wally
3 mins ago
add a comment |
You have to explicitly declare the default constructor of class Employee
thus you can initialize an abject via uniform initialization
:
class Employee {
public:
Employee(){} // add it
std::string name_;
Salary sal;
};
int main(){
Employee emp{}; // now this should compile
}
add a comment |
You have to explicitly declare the default constructor of class Employee
thus you can initialize an abject via uniform initialization
:
class Employee {
public:
Employee(){} // add it
std::string name_;
Salary sal;
};
int main(){
Employee emp{}; // now this should compile
}
add a comment |
You have to explicitly declare the default constructor of class Employee
thus you can initialize an abject via uniform initialization
:
class Employee {
public:
Employee(){} // add it
std::string name_;
Salary sal;
};
int main(){
Employee emp{}; // now this should compile
}
You have to explicitly declare the default constructor of class Employee
thus you can initialize an abject via uniform initialization
:
class Employee {
public:
Employee(){} // add it
std::string name_;
Salary sal;
};
int main(){
Employee emp{}; // now this should compile
}
answered 33 mins ago
Raindrop7Raindrop7
3,74531224
3,74531224
add a comment |
add a comment |
You need Employee
's ctor to call the ctor of Salary
. The ctor of Salary
is not accessible from main
.
eg:
class Employee {
public:
Employee() : sal() {}
public:
std::string name_;
Salary sal;
};
add a comment |
You need Employee
's ctor to call the ctor of Salary
. The ctor of Salary
is not accessible from main
.
eg:
class Employee {
public:
Employee() : sal() {}
public:
std::string name_;
Salary sal;
};
add a comment |
You need Employee
's ctor to call the ctor of Salary
. The ctor of Salary
is not accessible from main
.
eg:
class Employee {
public:
Employee() : sal() {}
public:
std::string name_;
Salary sal;
};
You need Employee
's ctor to call the ctor of Salary
. The ctor of Salary
is not accessible from main
.
eg:
class Employee {
public:
Employee() : sal() {}
public:
std::string name_;
Salary sal;
};
edited 22 mins ago
Pavan Manjunath
20.1k1181108
20.1k1181108
answered 43 mins ago
schuessschuess
536416
536416
add a comment |
add a comment |
If you erase the "{}" after "Employee emp" in your main() function it compiles just fine (gcc 7.3.1 on Fedora 27).
1
I recommend explaining why.
– user4581301
41 mins ago
Yes. Not onyl GCC but also MSVC14 also compilesEmployee emp;
but why?
– Syfu_H
39 mins ago
@Syfu_H Value Initialization. And I could be mistaken here (been caught on this in the past), but the Value Initialization is being replaced by Aggregate Initialization
– user4581301
31 mins ago
add a comment |
If you erase the "{}" after "Employee emp" in your main() function it compiles just fine (gcc 7.3.1 on Fedora 27).
1
I recommend explaining why.
– user4581301
41 mins ago
Yes. Not onyl GCC but also MSVC14 also compilesEmployee emp;
but why?
– Syfu_H
39 mins ago
@Syfu_H Value Initialization. And I could be mistaken here (been caught on this in the past), but the Value Initialization is being replaced by Aggregate Initialization
– user4581301
31 mins ago
add a comment |
If you erase the "{}" after "Employee emp" in your main() function it compiles just fine (gcc 7.3.1 on Fedora 27).
If you erase the "{}" after "Employee emp" in your main() function it compiles just fine (gcc 7.3.1 on Fedora 27).
answered 43 mins ago
Eric SokolowskyEric Sokolowsky
514
514
1
I recommend explaining why.
– user4581301
41 mins ago
Yes. Not onyl GCC but also MSVC14 also compilesEmployee emp;
but why?
– Syfu_H
39 mins ago
@Syfu_H Value Initialization. And I could be mistaken here (been caught on this in the past), but the Value Initialization is being replaced by Aggregate Initialization
– user4581301
31 mins ago
add a comment |
1
I recommend explaining why.
– user4581301
41 mins ago
Yes. Not onyl GCC but also MSVC14 also compilesEmployee emp;
but why?
– Syfu_H
39 mins ago
@Syfu_H Value Initialization. And I could be mistaken here (been caught on this in the past), but the Value Initialization is being replaced by Aggregate Initialization
– user4581301
31 mins ago
1
1
I recommend explaining why.
– user4581301
41 mins ago
I recommend explaining why.
– user4581301
41 mins ago
Yes. Not onyl GCC but also MSVC14 also compiles
Employee emp;
but why?– Syfu_H
39 mins ago
Yes. Not onyl GCC but also MSVC14 also compiles
Employee emp;
but why?– Syfu_H
39 mins ago
@Syfu_H Value Initialization. And I could be mistaken here (been caught on this in the past), but the Value Initialization is being replaced by Aggregate Initialization
– user4581301
31 mins ago
@Syfu_H Value Initialization. And I could be mistaken here (been caught on this in the past), but the Value Initialization is being replaced by Aggregate Initialization
– user4581301
31 mins ago
add a comment |
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Why are you making
Salary
's constructor private? It seems like there are contexts when you'd want to useSalary
outside ofEmployee
– J. Antonio Perez
7 mins ago