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Making a right-angle mark using the `calc` package in `TikZ`

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I have a right triangle and the altitude from the vertex of its right angle drawn. A=(-4,0), B=(0,3), and C=(0,0) are the vertices of the triangle, and F=(-36/25,48/25) is the foot of the altitude on the hypotenuse AB. I use the following commands to draw a right-angle mark.

coordinate (U) at ($(F)!3mm!45:(A)$);

draw ($(A)!(U)!(F)$) -- (U) -- ($(C)!(U)!(F)$);

Why doesn't it look like three sides of a square with edge length 3mm?

documentclass{amsart}

usepackage{amsmath}



usepackage{tikz}

usetikzlibrary{calc,intersections}





begin{document}



begin{tikzpicture}



coordinate (circle_1) at (-8/5, 4/5);

draw[blue, fill=blue=25!] (circle_1) circle (4/5);



coordinate (circle_1) at (-3/5, 9/5);

draw[orange, fill=orange=25!] (circle_1) circle (3/5);





path (-4,0) coordinate (A) (0,3) coordinate (B) (0,0) coordinate (C);

coordinate (F) at (-36/25,48/25);

draw (A) -- (B) -- (C) -- cycle;

draw (F) -- (C);







%A right-angle mark is drawn at F.

coordinate (U) at ($(F)!3mm!45:(A)$);

draw ($(A)!(U)!(F)$) -- (U) -- ($(C)!(U)!(F)$);





%A right-angle mark is drawn at C.

coordinate (U) at ($(C)!3mm!-45:(A)$);

draw ($(A)!(U)!(C)$) -- (U) -- ($(B)!(U)!(C)$);





end{tikzpicture}





end{document}

tikz-pgf

share|improve this question

asked 11 mins ago

A gal named DesireA gal named Desire

6931411

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Nice figure! I may use it to accompany a problem on a test in Geometry.
  
  – user74973
  5 mins ago
  

  
  
  
  

add a comment | 

1

2

I have a right triangle and the altitude from the vertex of its right angle drawn. A=(-4,0), B=(0,3), and C=(0,0) are the vertices of the triangle, and F=(-36/25,48/25) is the foot of the altitude on the hypotenuse AB. I use the following commands to draw a right-angle mark.

coordinate (U) at ($(F)!3mm!45:(A)$);

draw ($(A)!(U)!(F)$) -- (U) -- ($(C)!(U)!(F)$);

Why doesn't it look like three sides of a square with edge length 3mm?

documentclass{amsart}

usepackage{amsmath}



usepackage{tikz}

usetikzlibrary{calc,intersections}





begin{document}



begin{tikzpicture}



coordinate (circle_1) at (-8/5, 4/5);

draw[blue, fill=blue=25!] (circle_1) circle (4/5);



coordinate (circle_1) at (-3/5, 9/5);

draw[orange, fill=orange=25!] (circle_1) circle (3/5);





path (-4,0) coordinate (A) (0,3) coordinate (B) (0,0) coordinate (C);

coordinate (F) at (-36/25,48/25);

draw (A) -- (B) -- (C) -- cycle;

draw (F) -- (C);







%A right-angle mark is drawn at F.

coordinate (U) at ($(F)!3mm!45:(A)$);

draw ($(A)!(U)!(F)$) -- (U) -- ($(C)!(U)!(F)$);





%A right-angle mark is drawn at C.

coordinate (U) at ($(C)!3mm!-45:(A)$);

draw ($(A)!(U)!(C)$) -- (U) -- ($(B)!(U)!(C)$);





end{tikzpicture}





end{document}

tikz-pgf

share|improve this question

asked 11 mins ago

A gal named DesireA gal named Desire

6931411

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Nice figure! I may use it to accompany a problem on a test in Geometry.
  
  – user74973
  5 mins ago
  

  
  
  
  

add a comment | 

I have a right triangle and the altitude from the vertex of its right angle drawn. A=(-4,0), B=(0,3), and C=(0,0) are the vertices of the triangle, and F=(-36/25,48/25) is the foot of the altitude on the hypotenuse AB. I use the following commands to draw a right-angle mark.

coordinate (U) at ($(F)!3mm!45:(A)$);

draw ($(A)!(U)!(F)$) -- (U) -- ($(C)!(U)!(F)$);

Why doesn't it look like three sides of a square with edge length 3mm?

documentclass{amsart}

usepackage{amsmath}



usepackage{tikz}

usetikzlibrary{calc,intersections}





begin{document}



begin{tikzpicture}



coordinate (circle_1) at (-8/5, 4/5);

draw[blue, fill=blue=25!] (circle_1) circle (4/5);



coordinate (circle_1) at (-3/5, 9/5);

draw[orange, fill=orange=25!] (circle_1) circle (3/5);





path (-4,0) coordinate (A) (0,3) coordinate (B) (0,0) coordinate (C);

coordinate (F) at (-36/25,48/25);

draw (A) -- (B) -- (C) -- cycle;

draw (F) -- (C);







%A right-angle mark is drawn at F.

coordinate (U) at ($(F)!3mm!45:(A)$);

draw ($(A)!(U)!(F)$) -- (U) -- ($(C)!(U)!(F)$);





%A right-angle mark is drawn at C.

coordinate (U) at ($(C)!3mm!-45:(A)$);

draw ($(A)!(U)!(C)$) -- (U) -- ($(B)!(U)!(C)$);





end{tikzpicture}





end{document}

tikz-pgf

share|improve this question

asked 11 mins ago

A gal named DesireA gal named Desire

6931411

coordinate (U) at ($(F)!3mm!45:(A)$);

draw ($(A)!(U)!(F)$) -- (U) -- ($(C)!(U)!(F)$);

documentclass{amsart}

usepackage{amsmath}



usepackage{tikz}

usetikzlibrary{calc,intersections}





begin{document}



begin{tikzpicture}



coordinate (circle_1) at (-8/5, 4/5);

draw[blue, fill=blue=25!] (circle_1) circle (4/5);



coordinate (circle_1) at (-3/5, 9/5);

draw[orange, fill=orange=25!] (circle_1) circle (3/5);





path (-4,0) coordinate (A) (0,3) coordinate (B) (0,0) coordinate (C);

coordinate (F) at (-36/25,48/25);

draw (A) -- (B) -- (C) -- cycle;

draw (F) -- (C);







%A right-angle mark is drawn at F.

coordinate (U) at ($(F)!3mm!45:(A)$);

draw ($(A)!(U)!(F)$) -- (U) -- ($(C)!(U)!(F)$);





%A right-angle mark is drawn at C.

coordinate (U) at ($(C)!3mm!-45:(A)$);

draw ($(A)!(U)!(C)$) -- (U) -- ($(B)!(U)!(C)$);





end{tikzpicture}





end{document}

share|improve this question

asked 11 mins ago

A gal named DesireA gal named Desire

6931411

share|improve this question

asked 11 mins ago

A gal named DesireA gal named Desire

6931411

asked 11 mins ago

A gal named DesireA gal named Desire

6931411

asked 11 mins ago

A gal named DesireA gal named Desire

6931411