Is there such a thing in math the inverse of a sequence?Is the sequence...
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Is there such a thing in math the inverse of a sequence?
Is the sequence $u_{n}=sum_{p=0}^{n}(arctanfrac{x}{2^p})^2$ convergent?Does there exist a convergent sequence ${a_n}$ such that $n d(a_{n+1},a_n)$ is not bounded?Show that the sequence $left(frac{2^n}{n!}right)$ has a limit.Which is the function that this sequence of functions convergesA convergent / divergent sequence of positive numbers such that $lim frac{s_{n+1}}{s_n}=1$Proof that every bounded sequence in the real numbers has a convergent subsequenceSuch thing as inverse/undo “search” or “filter” operatorConfusion arising from the 'infiniteness' of a sequence.Every sequence of the real numbers has a monotone subsequence.Showing the difference of an unbounded sequence and a convergent sequence is unbounded
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Such as can I construct a sequence by reversing the order of the approximating sequence of $frac{1}{3}$? So such inverse would look like $left{….,0.333333333,0.3333333,0.333333,...0.3right}$.
I had this question when I was constructing a sequence that is bounded between 0 and 1/2 and not convergent to 0 for a homework question.
real-analysis sequences-and-series inverse
asked 4 hours ago
user917099user917099
1495
$endgroup$
add a comment |
$begingroup$
Such as can I construct a sequence by reversing the order of the approximating sequence of $frac{1}{3}$? So such inverse would look like $left{….,0.333333333,0.3333333,0.333333,...0.3right}$.
I had this question when I was constructing a sequence that is bounded between 0 and 1/2 and not convergent to 0 for a homework question.
real-analysis sequences-and-series inverse
asked 4 hours ago
user917099user917099
1495
$endgroup$
$begingroup$
You can't, imagine if the first element has $n$ three's but in the original sequence the element with $n+1$ three's come after the one with $n$ three's hence in the new sequence it should be before the first element, a contradiction.
$endgroup$
– kingW3
4 hours ago
1
$begingroup$
And no, there is a difference between stupid and bad questions, in your case the votes have matchedvso your question divides opinion. Giving enough context helps when you are asking a "stupid" question, i.e. mentioning that you heard it in class or in conversation with a friend or online on some webpage helps. Also mention what was the broad topic if the conversation, so that others will be able to address concerns relating to that in the answer as well.
$endgroup$
– астон вілла олоф мэллбэрг
2 hours ago
$begingroup$
This is a good question. In several cases, a sequence makes sense for negative values of the index. For example, the Fibonacci numbers ${0,1,1,2,3,5,dots}$ can be exteneded to negative indices as ${dots,5,-3,2,-1,1}$. I encounter this kind of thing in the OEIS many time.
$endgroup$
– Somos
48 mins ago
add a comment |
$begingroup$
Such as can I construct a sequence by reversing the order of the approximating sequence of $frac{1}{3}$? So such inverse would look like $left{….,0.333333333,0.3333333,0.333333,...0.3right}$.
I had this question when I was constructing a sequence that is bounded between 0 and 1/2 and not convergent to 0 for a homework question.
real-analysis sequences-and-series inverse
asked 4 hours ago
user917099user917099
1495
$endgroup$
Such as can I construct a sequence by reversing the order of the approximating sequence of $frac{1}{3}$? So such inverse would look like $left{….,0.333333333,0.3333333,0.333333,...0.3right}$.
I had this question when I was constructing a sequence that is bounded between 0 and 1/2 and not convergent to 0 for a homework question.
real-analysis sequences-and-series inverse
real-analysis sequences-and-series inverse
asked 4 hours ago
user917099user917099
1495
asked 4 hours ago
user917099user917099
1495
edited 46 mins ago
user917099
asked 4 hours ago
user917099user917099
1495
asked 4 hours ago
user917099user917099
1495
asked 4 hours ago
user917099user917099
1495
1495
$begingroup$
You can't, imagine if the first element has $n$ three's but in the original sequence the element with $n+1$ three's come after the one with $n$ three's hence in the new sequence it should be before the first element, a contradiction.
$endgroup$
– kingW3
4 hours ago
1
$begingroup$
And no, there is a difference between stupid and bad questions, in your case the votes have matchedvso your question divides opinion. Giving enough context helps when you are asking a "stupid" question, i.e. mentioning that you heard it in class or in conversation with a friend or online on some webpage helps. Also mention what was the broad topic if the conversation, so that others will be able to address concerns relating to that in the answer as well.
$endgroup$
– астон вілла олоф мэллбэрг
2 hours ago
$begingroup$
This is a good question. In several cases, a sequence makes sense for negative values of the index. For example, the Fibonacci numbers ${0,1,1,2,3,5,dots}$ can be exteneded to negative indices as ${dots,5,-3,2,-1,1}$. I encounter this kind of thing in the OEIS many time.
$endgroup$
– Somos
48 mins ago
add a comment |
$begingroup$
You can't, imagine if the first element has $n$ three's but in the original sequence the element with $n+1$ three's come after the one with $n$ three's hence in the new sequence it should be before the first element, a contradiction.
$endgroup$
– kingW3
4 hours ago
1
$begingroup$
And no, there is a difference between stupid and bad questions, in your case the votes have matchedvso your question divides opinion. Giving enough context helps when you are asking a "stupid" question, i.e. mentioning that you heard it in class or in conversation with a friend or online on some webpage helps. Also mention what was the broad topic if the conversation, so that others will be able to address concerns relating to that in the answer as well.
$endgroup$
– астон вілла олоф мэллбэрг
2 hours ago
$begingroup$
This is a good question. In several cases, a sequence makes sense for negative values of the index. For example, the Fibonacci numbers ${0,1,1,2,3,5,dots}$ can be exteneded to negative indices as ${dots,5,-3,2,-1,1}$. I encounter this kind of thing in the OEIS many time.
$endgroup$
– Somos
48 mins ago
$begingroup$
You can't, imagine if the first element has $n$ three's but in the original sequence the element with $n+1$ three's come after the one with $n$ three's hence in the new sequence it should be before the first element, a contradiction.
$endgroup$
– kingW3
4 hours ago
$begingroup$
You can't, imagine if the first element has $n$ three's but in the original sequence the element with $n+1$ three's come after the one with $n$ three's hence in the new sequence it should be before the first element, a contradiction.
$endgroup$
– kingW3
4 hours ago
1
1
$begingroup$
And no, there is a difference between stupid and bad questions, in your case the votes have matchedvso your question divides opinion. Giving enough context helps when you are asking a "stupid" question, i.e. mentioning that you heard it in class or in conversation with a friend or online on some webpage helps. Also mention what was the broad topic if the conversation, so that others will be able to address concerns relating to that in the answer as well.
$endgroup$
– астон вілла олоф мэллбэрг
2 hours ago
$begingroup$
And no, there is a difference between stupid and bad questions, in your case the votes have matchedvso your question divides opinion. Giving enough context helps when you are asking a "stupid" question, i.e. mentioning that you heard it in class or in conversation with a friend or online on some webpage helps. Also mention what was the broad topic if the conversation, so that others will be able to address concerns relating to that in the answer as well.
$endgroup$
– астон вілла олоф мэллбэрг
2 hours ago
$begingroup$
This is a good question. In several cases, a sequence makes sense for negative values of the index. For example, the Fibonacci numbers ${0,1,1,2,3,5,dots}$ can be exteneded to negative indices as ${dots,5,-3,2,-1,1}$. I encounter this kind of thing in the OEIS many time.
$endgroup$
– Somos
48 mins ago
$begingroup$
This is a good question. In several cases, a sequence makes sense for negative values of the index. For example, the Fibonacci numbers ${0,1,1,2,3,5,dots}$ can be exteneded to negative indices as ${dots,5,-3,2,-1,1}$. I encounter this kind of thing in the OEIS many time.
$endgroup$
– Somos
48 mins ago
add a comment |
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$begingroup$
A sequence is ultimately a map whose domain is $mathbb N$, but the object that you describe (a) has no first term, and (b) terminates.
If you want, I suppose you could define an object whose indices run from $-infty$ to $0$, but that's not appreciably different from looking at the original sequence while standing on your head.
answered 4 hours ago
J. MurrayJ. Murray
53017
$endgroup$
add a comment |
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$begingroup$
A sequence is ultimately a map whose domain is $mathbb N$, but the object that you describe (a) has no first term, and (b) terminates.
If you want, I suppose you could define an object whose indices run from $-infty$ to $0$, but that's not appreciably different from looking at the original sequence while standing on your head.
answered 4 hours ago
J. MurrayJ. Murray
53017
$endgroup$
add a comment |
$begingroup$
A sequence is ultimately a map whose domain is $mathbb N$, but the object that you describe (a) has no first term, and (b) terminates.
If you want, I suppose you could define an object whose indices run from $-infty$ to $0$, but that's not appreciably different from looking at the original sequence while standing on your head.
answered 4 hours ago
J. MurrayJ. Murray
53017
$endgroup$
add a comment |
$begingroup$
A sequence is ultimately a map whose domain is $mathbb N$, but the object that you describe (a) has no first term, and (b) terminates.
If you want, I suppose you could define an object whose indices run from $-infty$ to $0$, but that's not appreciably different from looking at the original sequence while standing on your head.
answered 4 hours ago
J. MurrayJ. Murray
53017
$endgroup$
A sequence is ultimately a map whose domain is $mathbb N$, but the object that you describe (a) has no first term, and (b) terminates.
If you want, I suppose you could define an object whose indices run from $-infty$ to $0$, but that's not appreciably different from looking at the original sequence while standing on your head.
answered 4 hours ago
J. MurrayJ. Murray
53017
edited 3 hours ago
answered 4 hours ago
J. MurrayJ. Murray
53017
answered 4 hours ago
J. MurrayJ. Murray
53017
answered 4 hours ago
J. MurrayJ. Murray
53017
53017
add a comment |
add a comment |
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$begingroup$
You can't, imagine if the first element has $n$ three's but in the original sequence the element with $n+1$ three's come after the one with $n$ three's hence in the new sequence it should be before the first element, a contradiction.
$endgroup$
– kingW3
4 hours ago
1
$begingroup$
And no, there is a difference between stupid and bad questions, in your case the votes have matchedvso your question divides opinion. Giving enough context helps when you are asking a "stupid" question, i.e. mentioning that you heard it in class or in conversation with a friend or online on some webpage helps. Also mention what was the broad topic if the conversation, so that others will be able to address concerns relating to that in the answer as well.
$endgroup$
– астон вілла олоф мэллбэрг
2 hours ago
$begingroup$
This is a good question. In several cases, a sequence makes sense for negative values of the index. For example, the Fibonacci numbers ${0,1,1,2,3,5,dots}$ can be exteneded to negative indices as ${dots,5,-3,2,-1,1}$. I encounter this kind of thing in the OEIS many time.
$endgroup$
– Somos
48 mins ago