Why do we call complex numbers “numbers” but we don’t consider 2 vectors numbers?What exactly is a...
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Why do we call complex numbers “numbers” but we don’t consider 2 vectors numbers?
What exactly is a number?Relationship between complex number and vectorsAre there any numbers more fundamental than Complex numbers?Why are complex numbers considered to be numbers?Does it make sense to compare complex numbers in certain circumstances?Usefulness of alternative constructions of the complex numbersComplex numbers?Why are complex numbers so magical?What can complex numbers do that linear algebra cannot?complex numbers and rotation matricesIf there is anything else introduced into equations like the complex numbers.
$begingroup$
We refer to complex numbers as numbers. However we refer to vectors as arrays of numbers. There doesn’t seem to be anything that makes one more numeric than the other. Is this just a quirk of history and naming or is there something more fundamental?
matrices complex-numbers philosophy
$endgroup$
|
show 1 more comment
$begingroup$
We refer to complex numbers as numbers. However we refer to vectors as arrays of numbers. There doesn’t seem to be anything that makes one more numeric than the other. Is this just a quirk of history and naming or is there something more fundamental?
matrices complex-numbers philosophy
$endgroup$
6
$begingroup$
Usually, the difference would be whether you're in a context where complex multiplication would be interesting. It's kind of like the question: is $mathbb{Z}$ a group or a ring? It depends on which operations are of interest for the question you're studying.
$endgroup$
– Nate Eldredge
2 hours ago
3
$begingroup$
What's a "number" anyway?
$endgroup$
– Asaf Karagila♦
2 hours ago
$begingroup$
I would say that $mathbb{Z}$ is not a ring or a group as you have to have an operator in order to be a magma. However that would be over pedantic so I get where you are coming from.
$endgroup$
– Q the Platypus
1 hour ago
4
$begingroup$
@QthePlatypus: No, that's exactly the point. The question of whether the set $mathbb{R}^2$ of pairs of real numbers should be considered as the set of complex numbers, or as a set of vectors, depends on which operations you wish to equip that set with.
$endgroup$
– Nate Eldredge
1 hour ago
1
$begingroup$
I think the correct question were: is there a rigorous definition of the object "number" (without further characteristics such as "integer", "real", "complex" etc.)?
$endgroup$
– user
1 hour ago
|
show 1 more comment
$begingroup$
We refer to complex numbers as numbers. However we refer to vectors as arrays of numbers. There doesn’t seem to be anything that makes one more numeric than the other. Is this just a quirk of history and naming or is there something more fundamental?
matrices complex-numbers philosophy
$endgroup$
We refer to complex numbers as numbers. However we refer to vectors as arrays of numbers. There doesn’t seem to be anything that makes one more numeric than the other. Is this just a quirk of history and naming or is there something more fundamental?
matrices complex-numbers philosophy
matrices complex-numbers philosophy
edited 1 hour ago
Bernard
122k740116
122k740116
asked 2 hours ago
Q the PlatypusQ the Platypus
2,787933
2,787933
6
$begingroup$
Usually, the difference would be whether you're in a context where complex multiplication would be interesting. It's kind of like the question: is $mathbb{Z}$ a group or a ring? It depends on which operations are of interest for the question you're studying.
$endgroup$
– Nate Eldredge
2 hours ago
3
$begingroup$
What's a "number" anyway?
$endgroup$
– Asaf Karagila♦
2 hours ago
$begingroup$
I would say that $mathbb{Z}$ is not a ring or a group as you have to have an operator in order to be a magma. However that would be over pedantic so I get where you are coming from.
$endgroup$
– Q the Platypus
1 hour ago
4
$begingroup$
@QthePlatypus: No, that's exactly the point. The question of whether the set $mathbb{R}^2$ of pairs of real numbers should be considered as the set of complex numbers, or as a set of vectors, depends on which operations you wish to equip that set with.
$endgroup$
– Nate Eldredge
1 hour ago
1
$begingroup$
I think the correct question were: is there a rigorous definition of the object "number" (without further characteristics such as "integer", "real", "complex" etc.)?
$endgroup$
– user
1 hour ago
|
show 1 more comment
6
$begingroup$
Usually, the difference would be whether you're in a context where complex multiplication would be interesting. It's kind of like the question: is $mathbb{Z}$ a group or a ring? It depends on which operations are of interest for the question you're studying.
$endgroup$
– Nate Eldredge
2 hours ago
3
$begingroup$
What's a "number" anyway?
$endgroup$
– Asaf Karagila♦
2 hours ago
$begingroup$
I would say that $mathbb{Z}$ is not a ring or a group as you have to have an operator in order to be a magma. However that would be over pedantic so I get where you are coming from.
$endgroup$
– Q the Platypus
1 hour ago
4
$begingroup$
@QthePlatypus: No, that's exactly the point. The question of whether the set $mathbb{R}^2$ of pairs of real numbers should be considered as the set of complex numbers, or as a set of vectors, depends on which operations you wish to equip that set with.
$endgroup$
– Nate Eldredge
1 hour ago
1
$begingroup$
I think the correct question were: is there a rigorous definition of the object "number" (without further characteristics such as "integer", "real", "complex" etc.)?
$endgroup$
– user
1 hour ago
6
6
$begingroup$
Usually, the difference would be whether you're in a context where complex multiplication would be interesting. It's kind of like the question: is $mathbb{Z}$ a group or a ring? It depends on which operations are of interest for the question you're studying.
$endgroup$
– Nate Eldredge
2 hours ago
$begingroup$
Usually, the difference would be whether you're in a context where complex multiplication would be interesting. It's kind of like the question: is $mathbb{Z}$ a group or a ring? It depends on which operations are of interest for the question you're studying.
$endgroup$
– Nate Eldredge
2 hours ago
3
3
$begingroup$
What's a "number" anyway?
$endgroup$
– Asaf Karagila♦
2 hours ago
$begingroup$
What's a "number" anyway?
$endgroup$
– Asaf Karagila♦
2 hours ago
$begingroup$
I would say that $mathbb{Z}$ is not a ring or a group as you have to have an operator in order to be a magma. However that would be over pedantic so I get where you are coming from.
$endgroup$
– Q the Platypus
1 hour ago
$begingroup$
I would say that $mathbb{Z}$ is not a ring or a group as you have to have an operator in order to be a magma. However that would be over pedantic so I get where you are coming from.
$endgroup$
– Q the Platypus
1 hour ago
4
4
$begingroup$
@QthePlatypus: No, that's exactly the point. The question of whether the set $mathbb{R}^2$ of pairs of real numbers should be considered as the set of complex numbers, or as a set of vectors, depends on which operations you wish to equip that set with.
$endgroup$
– Nate Eldredge
1 hour ago
$begingroup$
@QthePlatypus: No, that's exactly the point. The question of whether the set $mathbb{R}^2$ of pairs of real numbers should be considered as the set of complex numbers, or as a set of vectors, depends on which operations you wish to equip that set with.
$endgroup$
– Nate Eldredge
1 hour ago
1
1
$begingroup$
I think the correct question were: is there a rigorous definition of the object "number" (without further characteristics such as "integer", "real", "complex" etc.)?
$endgroup$
– user
1 hour ago
$begingroup$
I think the correct question were: is there a rigorous definition of the object "number" (without further characteristics such as "integer", "real", "complex" etc.)?
$endgroup$
– user
1 hour ago
|
show 1 more comment
4 Answers
4
active
oldest
votes
$begingroup$
The two fundamental operations for numbers are "addition" and "multiplication" which obey very nice "laws" of arithmetic. Taking powers is also important. You can do all of those things with complex numbers. You can add two vectors but the "dot" product of two vectors is not a vector and the "cross" product of two vectors does not satisfy the "nice laws". Neither the dot product nor the cross product of vectors can be used to define powers.
$endgroup$
$begingroup$
So Quaternions which have Non commutativity multiplication would also be considered as non numbers?
$endgroup$
– Q the Platypus
2 hours ago
3
$begingroup$
That's a good point- though I have never liked quaternions! Multiplication of quaternions is not commutative but it is associative which allows powers. That's what I was really thinking of.
$endgroup$
– user247327
1 hour ago
add a comment |
$begingroup$
They're called "numbers" for historical reasons, since the motivation in the development of the complex numbers was solving polynomial equations. They were viewed as natural extensions of the real numbers. It's somehow quite natural and satisfying to say "every polynomial equation can be solved by some (complex) number". Is it more natural to regard $i$ as being a number which, when squared, is equal to $-1$, or is it more natural to regard $i$ as being some non-number thingamajig which when squared is equal to $-1$? Clearly the former.
"Higher" number system, like quaternions, aren't really called numbers very often, for the simple fact that they are not as intimately connected with number theory and analysis in the same way that complex numbers are.
Beyond these social conventions, I can't see any other reason. The word "number" doesn't have a strict or absolute definition in pure mathematics. $mathbb{N}$, $mathbb{Z}$, $mathbb{Q}$, $mathbb{R}$ and $mathbb{C}$ are technically just sets with a certain algebraic structure.
I partially disagree with the other answers which claim that complex numbers are numbers simply by virtue of the fact that you can add and multiply them. Well, if that's the rationale, is every ring also a set of numbers?
$endgroup$
add a comment |
$begingroup$
Complex numbers do not have the same properties as vectors but they have similar properties (see dot product). We can represent complex numbers as vectors, but that is just a representation.
Complex numbers are also called imaginary numbers because the first appearance of them was quite confusing. They appeared in the solution of the cubic equation for the case of three distinct real roots. It took quite a time until people understood that they could calculate with complex numbers like with normal numbers but will some additional rules e.g. $i^2=-1$.
Complex numbers also do not have a comparison operator like $<$ or $>$. For example, assume
$i<0$ then $icdot i > 0 implies -1>0$ which is wrong. $i=0$ makes no sense. And $i>0$ then $icdot i >0 implies -1 >0$ which is wrong.
Hence, the name makes sense as these numbers have some imaginary or complex behavior which normal numbers do not show.
$endgroup$
2
$begingroup$
I’m not asking why complex numbers are call complex. I am asking why they are called numbers. BTW they are not called complex numbers because they are difficult but because complex can mean “made up of parts” like a “shopping complex”.
$endgroup$
– Q the Platypus
2 hours ago
add a comment |
$begingroup$
Numbers appeared first when we started to count things. $1$ tree, $2$ trees, $3$ trees, and so forth. That make up the set of non-zero natural numbers: $mathbb{N}$. Afterwards, people started to "count backwards" to get $mathbb{Z}$ (I'm just kidding, you can do some research on how negative numbers appeared historically). With the urge to divide things without remainders, the set of rational numbers $mathbb{Q}$ made its way to the world. A certain idea of geometric continuity gives us $mathbb{R}$. Finally we want all equations to have a root, that's how $mathbb{C}$ comes into play.
I guess what is considered "numbers" is rather a social question. The use of $mathbb{C}$
in physics and its $2$-D representation must have given a good intuition for a large set of people to accept it's intuitive enough to be considered "numbers".
I think it's not that natural to think of $mathbb{C}$ as a $mathbb{R}$-vector space of dimension $2$, not more natural than to think of $mathbb{R}$ as an infinite-dimensional $mathbb{Q}$-vector space, nor of $mathbb{Q}$ as a non-infinitely-generated $mathbb{Z}$-module.
$endgroup$
2
$begingroup$
People do think of complex numbers as points on the number plane.
$endgroup$
– Q the Platypus
1 hour ago
1
$begingroup$
Thank you. I'm sorry, that final part is just a personal opinion. edited.
$endgroup$
– Leaning
1 hour ago
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
The two fundamental operations for numbers are "addition" and "multiplication" which obey very nice "laws" of arithmetic. Taking powers is also important. You can do all of those things with complex numbers. You can add two vectors but the "dot" product of two vectors is not a vector and the "cross" product of two vectors does not satisfy the "nice laws". Neither the dot product nor the cross product of vectors can be used to define powers.
$endgroup$
$begingroup$
So Quaternions which have Non commutativity multiplication would also be considered as non numbers?
$endgroup$
– Q the Platypus
2 hours ago
3
$begingroup$
That's a good point- though I have never liked quaternions! Multiplication of quaternions is not commutative but it is associative which allows powers. That's what I was really thinking of.
$endgroup$
– user247327
1 hour ago
add a comment |
$begingroup$
The two fundamental operations for numbers are "addition" and "multiplication" which obey very nice "laws" of arithmetic. Taking powers is also important. You can do all of those things with complex numbers. You can add two vectors but the "dot" product of two vectors is not a vector and the "cross" product of two vectors does not satisfy the "nice laws". Neither the dot product nor the cross product of vectors can be used to define powers.
$endgroup$
$begingroup$
So Quaternions which have Non commutativity multiplication would also be considered as non numbers?
$endgroup$
– Q the Platypus
2 hours ago
3
$begingroup$
That's a good point- though I have never liked quaternions! Multiplication of quaternions is not commutative but it is associative which allows powers. That's what I was really thinking of.
$endgroup$
– user247327
1 hour ago
add a comment |
$begingroup$
The two fundamental operations for numbers are "addition" and "multiplication" which obey very nice "laws" of arithmetic. Taking powers is also important. You can do all of those things with complex numbers. You can add two vectors but the "dot" product of two vectors is not a vector and the "cross" product of two vectors does not satisfy the "nice laws". Neither the dot product nor the cross product of vectors can be used to define powers.
$endgroup$
The two fundamental operations for numbers are "addition" and "multiplication" which obey very nice "laws" of arithmetic. Taking powers is also important. You can do all of those things with complex numbers. You can add two vectors but the "dot" product of two vectors is not a vector and the "cross" product of two vectors does not satisfy the "nice laws". Neither the dot product nor the cross product of vectors can be used to define powers.
answered 2 hours ago
user247327user247327
11.3k1515
11.3k1515
$begingroup$
So Quaternions which have Non commutativity multiplication would also be considered as non numbers?
$endgroup$
– Q the Platypus
2 hours ago
3
$begingroup$
That's a good point- though I have never liked quaternions! Multiplication of quaternions is not commutative but it is associative which allows powers. That's what I was really thinking of.
$endgroup$
– user247327
1 hour ago
add a comment |
$begingroup$
So Quaternions which have Non commutativity multiplication would also be considered as non numbers?
$endgroup$
– Q the Platypus
2 hours ago
3
$begingroup$
That's a good point- though I have never liked quaternions! Multiplication of quaternions is not commutative but it is associative which allows powers. That's what I was really thinking of.
$endgroup$
– user247327
1 hour ago
$begingroup$
So Quaternions which have Non commutativity multiplication would also be considered as non numbers?
$endgroup$
– Q the Platypus
2 hours ago
$begingroup$
So Quaternions which have Non commutativity multiplication would also be considered as non numbers?
$endgroup$
– Q the Platypus
2 hours ago
3
3
$begingroup$
That's a good point- though I have never liked quaternions! Multiplication of quaternions is not commutative but it is associative which allows powers. That's what I was really thinking of.
$endgroup$
– user247327
1 hour ago
$begingroup$
That's a good point- though I have never liked quaternions! Multiplication of quaternions is not commutative but it is associative which allows powers. That's what I was really thinking of.
$endgroup$
– user247327
1 hour ago
add a comment |
$begingroup$
They're called "numbers" for historical reasons, since the motivation in the development of the complex numbers was solving polynomial equations. They were viewed as natural extensions of the real numbers. It's somehow quite natural and satisfying to say "every polynomial equation can be solved by some (complex) number". Is it more natural to regard $i$ as being a number which, when squared, is equal to $-1$, or is it more natural to regard $i$ as being some non-number thingamajig which when squared is equal to $-1$? Clearly the former.
"Higher" number system, like quaternions, aren't really called numbers very often, for the simple fact that they are not as intimately connected with number theory and analysis in the same way that complex numbers are.
Beyond these social conventions, I can't see any other reason. The word "number" doesn't have a strict or absolute definition in pure mathematics. $mathbb{N}$, $mathbb{Z}$, $mathbb{Q}$, $mathbb{R}$ and $mathbb{C}$ are technically just sets with a certain algebraic structure.
I partially disagree with the other answers which claim that complex numbers are numbers simply by virtue of the fact that you can add and multiply them. Well, if that's the rationale, is every ring also a set of numbers?
$endgroup$
add a comment |
$begingroup$
They're called "numbers" for historical reasons, since the motivation in the development of the complex numbers was solving polynomial equations. They were viewed as natural extensions of the real numbers. It's somehow quite natural and satisfying to say "every polynomial equation can be solved by some (complex) number". Is it more natural to regard $i$ as being a number which, when squared, is equal to $-1$, or is it more natural to regard $i$ as being some non-number thingamajig which when squared is equal to $-1$? Clearly the former.
"Higher" number system, like quaternions, aren't really called numbers very often, for the simple fact that they are not as intimately connected with number theory and analysis in the same way that complex numbers are.
Beyond these social conventions, I can't see any other reason. The word "number" doesn't have a strict or absolute definition in pure mathematics. $mathbb{N}$, $mathbb{Z}$, $mathbb{Q}$, $mathbb{R}$ and $mathbb{C}$ are technically just sets with a certain algebraic structure.
I partially disagree with the other answers which claim that complex numbers are numbers simply by virtue of the fact that you can add and multiply them. Well, if that's the rationale, is every ring also a set of numbers?
$endgroup$
add a comment |
$begingroup$
They're called "numbers" for historical reasons, since the motivation in the development of the complex numbers was solving polynomial equations. They were viewed as natural extensions of the real numbers. It's somehow quite natural and satisfying to say "every polynomial equation can be solved by some (complex) number". Is it more natural to regard $i$ as being a number which, when squared, is equal to $-1$, or is it more natural to regard $i$ as being some non-number thingamajig which when squared is equal to $-1$? Clearly the former.
"Higher" number system, like quaternions, aren't really called numbers very often, for the simple fact that they are not as intimately connected with number theory and analysis in the same way that complex numbers are.
Beyond these social conventions, I can't see any other reason. The word "number" doesn't have a strict or absolute definition in pure mathematics. $mathbb{N}$, $mathbb{Z}$, $mathbb{Q}$, $mathbb{R}$ and $mathbb{C}$ are technically just sets with a certain algebraic structure.
I partially disagree with the other answers which claim that complex numbers are numbers simply by virtue of the fact that you can add and multiply them. Well, if that's the rationale, is every ring also a set of numbers?
$endgroup$
They're called "numbers" for historical reasons, since the motivation in the development of the complex numbers was solving polynomial equations. They were viewed as natural extensions of the real numbers. It's somehow quite natural and satisfying to say "every polynomial equation can be solved by some (complex) number". Is it more natural to regard $i$ as being a number which, when squared, is equal to $-1$, or is it more natural to regard $i$ as being some non-number thingamajig which when squared is equal to $-1$? Clearly the former.
"Higher" number system, like quaternions, aren't really called numbers very often, for the simple fact that they are not as intimately connected with number theory and analysis in the same way that complex numbers are.
Beyond these social conventions, I can't see any other reason. The word "number" doesn't have a strict or absolute definition in pure mathematics. $mathbb{N}$, $mathbb{Z}$, $mathbb{Q}$, $mathbb{R}$ and $mathbb{C}$ are technically just sets with a certain algebraic structure.
I partially disagree with the other answers which claim that complex numbers are numbers simply by virtue of the fact that you can add and multiply them. Well, if that's the rationale, is every ring also a set of numbers?
answered 1 hour ago
MathematicsStudent1122MathematicsStudent1122
8,70122467
8,70122467
add a comment |
add a comment |
$begingroup$
Complex numbers do not have the same properties as vectors but they have similar properties (see dot product). We can represent complex numbers as vectors, but that is just a representation.
Complex numbers are also called imaginary numbers because the first appearance of them was quite confusing. They appeared in the solution of the cubic equation for the case of three distinct real roots. It took quite a time until people understood that they could calculate with complex numbers like with normal numbers but will some additional rules e.g. $i^2=-1$.
Complex numbers also do not have a comparison operator like $<$ or $>$. For example, assume
$i<0$ then $icdot i > 0 implies -1>0$ which is wrong. $i=0$ makes no sense. And $i>0$ then $icdot i >0 implies -1 >0$ which is wrong.
Hence, the name makes sense as these numbers have some imaginary or complex behavior which normal numbers do not show.
$endgroup$
2
$begingroup$
I’m not asking why complex numbers are call complex. I am asking why they are called numbers. BTW they are not called complex numbers because they are difficult but because complex can mean “made up of parts” like a “shopping complex”.
$endgroup$
– Q the Platypus
2 hours ago
add a comment |
$begingroup$
Complex numbers do not have the same properties as vectors but they have similar properties (see dot product). We can represent complex numbers as vectors, but that is just a representation.
Complex numbers are also called imaginary numbers because the first appearance of them was quite confusing. They appeared in the solution of the cubic equation for the case of three distinct real roots. It took quite a time until people understood that they could calculate with complex numbers like with normal numbers but will some additional rules e.g. $i^2=-1$.
Complex numbers also do not have a comparison operator like $<$ or $>$. For example, assume
$i<0$ then $icdot i > 0 implies -1>0$ which is wrong. $i=0$ makes no sense. And $i>0$ then $icdot i >0 implies -1 >0$ which is wrong.
Hence, the name makes sense as these numbers have some imaginary or complex behavior which normal numbers do not show.
$endgroup$
2
$begingroup$
I’m not asking why complex numbers are call complex. I am asking why they are called numbers. BTW they are not called complex numbers because they are difficult but because complex can mean “made up of parts” like a “shopping complex”.
$endgroup$
– Q the Platypus
2 hours ago
add a comment |
$begingroup$
Complex numbers do not have the same properties as vectors but they have similar properties (see dot product). We can represent complex numbers as vectors, but that is just a representation.
Complex numbers are also called imaginary numbers because the first appearance of them was quite confusing. They appeared in the solution of the cubic equation for the case of three distinct real roots. It took quite a time until people understood that they could calculate with complex numbers like with normal numbers but will some additional rules e.g. $i^2=-1$.
Complex numbers also do not have a comparison operator like $<$ or $>$. For example, assume
$i<0$ then $icdot i > 0 implies -1>0$ which is wrong. $i=0$ makes no sense. And $i>0$ then $icdot i >0 implies -1 >0$ which is wrong.
Hence, the name makes sense as these numbers have some imaginary or complex behavior which normal numbers do not show.
$endgroup$
Complex numbers do not have the same properties as vectors but they have similar properties (see dot product). We can represent complex numbers as vectors, but that is just a representation.
Complex numbers are also called imaginary numbers because the first appearance of them was quite confusing. They appeared in the solution of the cubic equation for the case of three distinct real roots. It took quite a time until people understood that they could calculate with complex numbers like with normal numbers but will some additional rules e.g. $i^2=-1$.
Complex numbers also do not have a comparison operator like $<$ or $>$. For example, assume
$i<0$ then $icdot i > 0 implies -1>0$ which is wrong. $i=0$ makes no sense. And $i>0$ then $icdot i >0 implies -1 >0$ which is wrong.
Hence, the name makes sense as these numbers have some imaginary or complex behavior which normal numbers do not show.
answered 2 hours ago
MachineLearnerMachineLearner
4977
4977
2
$begingroup$
I’m not asking why complex numbers are call complex. I am asking why they are called numbers. BTW they are not called complex numbers because they are difficult but because complex can mean “made up of parts” like a “shopping complex”.
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– Q the Platypus
2 hours ago
add a comment |
2
$begingroup$
I’m not asking why complex numbers are call complex. I am asking why they are called numbers. BTW they are not called complex numbers because they are difficult but because complex can mean “made up of parts” like a “shopping complex”.
$endgroup$
– Q the Platypus
2 hours ago
2
2
$begingroup$
I’m not asking why complex numbers are call complex. I am asking why they are called numbers. BTW they are not called complex numbers because they are difficult but because complex can mean “made up of parts” like a “shopping complex”.
$endgroup$
– Q the Platypus
2 hours ago
$begingroup$
I’m not asking why complex numbers are call complex. I am asking why they are called numbers. BTW they are not called complex numbers because they are difficult but because complex can mean “made up of parts” like a “shopping complex”.
$endgroup$
– Q the Platypus
2 hours ago
add a comment |
$begingroup$
Numbers appeared first when we started to count things. $1$ tree, $2$ trees, $3$ trees, and so forth. That make up the set of non-zero natural numbers: $mathbb{N}$. Afterwards, people started to "count backwards" to get $mathbb{Z}$ (I'm just kidding, you can do some research on how negative numbers appeared historically). With the urge to divide things without remainders, the set of rational numbers $mathbb{Q}$ made its way to the world. A certain idea of geometric continuity gives us $mathbb{R}$. Finally we want all equations to have a root, that's how $mathbb{C}$ comes into play.
I guess what is considered "numbers" is rather a social question. The use of $mathbb{C}$
in physics and its $2$-D representation must have given a good intuition for a large set of people to accept it's intuitive enough to be considered "numbers".
I think it's not that natural to think of $mathbb{C}$ as a $mathbb{R}$-vector space of dimension $2$, not more natural than to think of $mathbb{R}$ as an infinite-dimensional $mathbb{Q}$-vector space, nor of $mathbb{Q}$ as a non-infinitely-generated $mathbb{Z}$-module.
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2
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People do think of complex numbers as points on the number plane.
$endgroup$
– Q the Platypus
1 hour ago
1
$begingroup$
Thank you. I'm sorry, that final part is just a personal opinion. edited.
$endgroup$
– Leaning
1 hour ago
add a comment |
$begingroup$
Numbers appeared first when we started to count things. $1$ tree, $2$ trees, $3$ trees, and so forth. That make up the set of non-zero natural numbers: $mathbb{N}$. Afterwards, people started to "count backwards" to get $mathbb{Z}$ (I'm just kidding, you can do some research on how negative numbers appeared historically). With the urge to divide things without remainders, the set of rational numbers $mathbb{Q}$ made its way to the world. A certain idea of geometric continuity gives us $mathbb{R}$. Finally we want all equations to have a root, that's how $mathbb{C}$ comes into play.
I guess what is considered "numbers" is rather a social question. The use of $mathbb{C}$
in physics and its $2$-D representation must have given a good intuition for a large set of people to accept it's intuitive enough to be considered "numbers".
I think it's not that natural to think of $mathbb{C}$ as a $mathbb{R}$-vector space of dimension $2$, not more natural than to think of $mathbb{R}$ as an infinite-dimensional $mathbb{Q}$-vector space, nor of $mathbb{Q}$ as a non-infinitely-generated $mathbb{Z}$-module.
$endgroup$
2
$begingroup$
People do think of complex numbers as points on the number plane.
$endgroup$
– Q the Platypus
1 hour ago
1
$begingroup$
Thank you. I'm sorry, that final part is just a personal opinion. edited.
$endgroup$
– Leaning
1 hour ago
add a comment |
$begingroup$
Numbers appeared first when we started to count things. $1$ tree, $2$ trees, $3$ trees, and so forth. That make up the set of non-zero natural numbers: $mathbb{N}$. Afterwards, people started to "count backwards" to get $mathbb{Z}$ (I'm just kidding, you can do some research on how negative numbers appeared historically). With the urge to divide things without remainders, the set of rational numbers $mathbb{Q}$ made its way to the world. A certain idea of geometric continuity gives us $mathbb{R}$. Finally we want all equations to have a root, that's how $mathbb{C}$ comes into play.
I guess what is considered "numbers" is rather a social question. The use of $mathbb{C}$
in physics and its $2$-D representation must have given a good intuition for a large set of people to accept it's intuitive enough to be considered "numbers".
I think it's not that natural to think of $mathbb{C}$ as a $mathbb{R}$-vector space of dimension $2$, not more natural than to think of $mathbb{R}$ as an infinite-dimensional $mathbb{Q}$-vector space, nor of $mathbb{Q}$ as a non-infinitely-generated $mathbb{Z}$-module.
$endgroup$
Numbers appeared first when we started to count things. $1$ tree, $2$ trees, $3$ trees, and so forth. That make up the set of non-zero natural numbers: $mathbb{N}$. Afterwards, people started to "count backwards" to get $mathbb{Z}$ (I'm just kidding, you can do some research on how negative numbers appeared historically). With the urge to divide things without remainders, the set of rational numbers $mathbb{Q}$ made its way to the world. A certain idea of geometric continuity gives us $mathbb{R}$. Finally we want all equations to have a root, that's how $mathbb{C}$ comes into play.
I guess what is considered "numbers" is rather a social question. The use of $mathbb{C}$
in physics and its $2$-D representation must have given a good intuition for a large set of people to accept it's intuitive enough to be considered "numbers".
I think it's not that natural to think of $mathbb{C}$ as a $mathbb{R}$-vector space of dimension $2$, not more natural than to think of $mathbb{R}$ as an infinite-dimensional $mathbb{Q}$-vector space, nor of $mathbb{Q}$ as a non-infinitely-generated $mathbb{Z}$-module.
edited 1 hour ago
answered 1 hour ago
LeaningLeaning
1,221718
1,221718
2
$begingroup$
People do think of complex numbers as points on the number plane.
$endgroup$
– Q the Platypus
1 hour ago
1
$begingroup$
Thank you. I'm sorry, that final part is just a personal opinion. edited.
$endgroup$
– Leaning
1 hour ago
add a comment |
2
$begingroup$
People do think of complex numbers as points on the number plane.
$endgroup$
– Q the Platypus
1 hour ago
1
$begingroup$
Thank you. I'm sorry, that final part is just a personal opinion. edited.
$endgroup$
– Leaning
1 hour ago
2
2
$begingroup$
People do think of complex numbers as points on the number plane.
$endgroup$
– Q the Platypus
1 hour ago
$begingroup$
People do think of complex numbers as points on the number plane.
$endgroup$
– Q the Platypus
1 hour ago
1
1
$begingroup$
Thank you. I'm sorry, that final part is just a personal opinion. edited.
$endgroup$
– Leaning
1 hour ago
$begingroup$
Thank you. I'm sorry, that final part is just a personal opinion. edited.
$endgroup$
– Leaning
1 hour ago
add a comment |
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6
$begingroup$
Usually, the difference would be whether you're in a context where complex multiplication would be interesting. It's kind of like the question: is $mathbb{Z}$ a group or a ring? It depends on which operations are of interest for the question you're studying.
$endgroup$
– Nate Eldredge
2 hours ago
3
$begingroup$
What's a "number" anyway?
$endgroup$
– Asaf Karagila♦
2 hours ago
$begingroup$
I would say that $mathbb{Z}$ is not a ring or a group as you have to have an operator in order to be a magma. However that would be over pedantic so I get where you are coming from.
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– Q the Platypus
1 hour ago
4
$begingroup$
@QthePlatypus: No, that's exactly the point. The question of whether the set $mathbb{R}^2$ of pairs of real numbers should be considered as the set of complex numbers, or as a set of vectors, depends on which operations you wish to equip that set with.
$endgroup$
– Nate Eldredge
1 hour ago
1
$begingroup$
I think the correct question were: is there a rigorous definition of the object "number" (without further characteristics such as "integer", "real", "complex" etc.)?
$endgroup$
– user
1 hour ago