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Exempt portion of equation line from aligning?
Aligning plain `align` and `cases`?Alignment across nested aligned environmentsHow to match left alignment of equations in math mode outside and inside an array?How to modify eqnarray?Alignment of two equations on LaTeXHow center align two equations separated by a lineequation custom horizontal alignment & numbering each rowFlushed-left and flushed-right text in align or alignat environmentHow can I align this equation in the center?breqn not aligning first two lines
I am using an array environment to get aligned portions of a series of equations to center (instead of left-justify), as shown below:
usepackage{array,amsmath}
[
begin{array}{>{displaystyle}c @{{}={}} >{displaystyle}c @{{}+{}} >{displaystyle}c @{{}+{}} >{displaystyle}c}
sumlimits_{r=0}^{n+1} binom{n+1}{r} & binom{n+1}{0} & binom{n+1}{1} + ldots + binom{n+1}{n} & binom{n+1}{n+1} \
& 1 & sumlimits_{r=1}^n binom{n+1}{r} & 1 \
end{array}
]
The array environment (I believe) is necessary here to get each of the columns to center instead of justifying left.
Now my problem is that these two lines are part of a greater series of equations, where the others do not follow this pattern to be aligned. However, I need the equals signs to line up across all lines.
My current approach is follow the array with a normal align environment, having one equation line mirroring the longest line above but enclosed in phantom{} to get the align spacing right. But this leaves a single empty line with an equals in it.
...
begin{align*}
&= 2 + sum_{r=1}^nleft[binom{n}{r} + binom{n}{r-1}right] \
phantom{sumlimits_{r=0}^{n+1} binom{n+1}{r}} &= phantom{ binom{n+1}{0} + binom{n+1}{1} + ldots + binom{n+1}{n} + binom{n+1}{n+1}}
end{align*}
How can I get this result, but without the extraneous equals line at the end? Preferable a more elegant one, as this idea relies on several iffy factors such as none of the following equations exceeding the size of the one governing the special alignment.
math-mode horizontal-alignment align arrays
asked 11 mins ago
PGmathPGmath
1011
New contributor
PGmath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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I am using an array environment to get aligned portions of a series of equations to center (instead of left-justify), as shown below:
usepackage{array,amsmath}
[
begin{array}{>{displaystyle}c @{{}={}} >{displaystyle}c @{{}+{}} >{displaystyle}c @{{}+{}} >{displaystyle}c}
sumlimits_{r=0}^{n+1} binom{n+1}{r} & binom{n+1}{0} & binom{n+1}{1} + ldots + binom{n+1}{n} & binom{n+1}{n+1} \
& 1 & sumlimits_{r=1}^n binom{n+1}{r} & 1 \
end{array}
]
The array environment (I believe) is necessary here to get each of the columns to center instead of justifying left.
Now my problem is that these two lines are part of a greater series of equations, where the others do not follow this pattern to be aligned. However, I need the equals signs to line up across all lines.
My current approach is follow the array with a normal align environment, having one equation line mirroring the longest line above but enclosed in phantom{} to get the align spacing right. But this leaves a single empty line with an equals in it.
...
begin{align*}
&= 2 + sum_{r=1}^nleft[binom{n}{r} + binom{n}{r-1}right] \
phantom{sumlimits_{r=0}^{n+1} binom{n+1}{r}} &= phantom{ binom{n+1}{0} + binom{n+1}{1} + ldots + binom{n+1}{n} + binom{n+1}{n+1}}
end{align*}
How can I get this result, but without the extraneous equals line at the end? Preferable a more elegant one, as this idea relies on several iffy factors such as none of the following equations exceeding the size of the one governing the special alignment.
math-mode horizontal-alignment align arrays
asked 11 mins ago
PGmathPGmath
1011
New contributor
PGmath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I am using an array environment to get aligned portions of a series of equations to center (instead of left-justify), as shown below:
usepackage{array,amsmath}
[
begin{array}{>{displaystyle}c @{{}={}} >{displaystyle}c @{{}+{}} >{displaystyle}c @{{}+{}} >{displaystyle}c}
sumlimits_{r=0}^{n+1} binom{n+1}{r} & binom{n+1}{0} & binom{n+1}{1} + ldots + binom{n+1}{n} & binom{n+1}{n+1} \
& 1 & sumlimits_{r=1}^n binom{n+1}{r} & 1 \
end{array}
]
The array environment (I believe) is necessary here to get each of the columns to center instead of justifying left.
Now my problem is that these two lines are part of a greater series of equations, where the others do not follow this pattern to be aligned. However, I need the equals signs to line up across all lines.
My current approach is follow the array with a normal align environment, having one equation line mirroring the longest line above but enclosed in phantom{} to get the align spacing right. But this leaves a single empty line with an equals in it.
...
begin{align*}
&= 2 + sum_{r=1}^nleft[binom{n}{r} + binom{n}{r-1}right] \
phantom{sumlimits_{r=0}^{n+1} binom{n+1}{r}} &= phantom{ binom{n+1}{0} + binom{n+1}{1} + ldots + binom{n+1}{n} + binom{n+1}{n+1}}
end{align*}
How can I get this result, but without the extraneous equals line at the end? Preferable a more elegant one, as this idea relies on several iffy factors such as none of the following equations exceeding the size of the one governing the special alignment.
math-mode horizontal-alignment align arrays
asked 11 mins ago
PGmathPGmath
1011
New contributor
PGmath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I am using an array environment to get aligned portions of a series of equations to center (instead of left-justify), as shown below:
usepackage{array,amsmath}
[
begin{array}{>{displaystyle}c @{{}={}} >{displaystyle}c @{{}+{}} >{displaystyle}c @{{}+{}} >{displaystyle}c}
sumlimits_{r=0}^{n+1} binom{n+1}{r} & binom{n+1}{0} & binom{n+1}{1} + ldots + binom{n+1}{n} & binom{n+1}{n+1} \
& 1 & sumlimits_{r=1}^n binom{n+1}{r} & 1 \
end{array}
]
The array environment (I believe) is necessary here to get each of the columns to center instead of justifying left.
Now my problem is that these two lines are part of a greater series of equations, where the others do not follow this pattern to be aligned. However, I need the equals signs to line up across all lines.
My current approach is follow the array with a normal align environment, having one equation line mirroring the longest line above but enclosed in phantom{} to get the align spacing right. But this leaves a single empty line with an equals in it.
...
begin{align*}
&= 2 + sum_{r=1}^nleft[binom{n}{r} + binom{n}{r-1}right] \
phantom{sumlimits_{r=0}^{n+1} binom{n+1}{r}} &= phantom{ binom{n+1}{0} + binom{n+1}{1} + ldots + binom{n+1}{n} + binom{n+1}{n+1}}
end{align*}
How can I get this result, but without the extraneous equals line at the end? Preferable a more elegant one, as this idea relies on several iffy factors such as none of the following equations exceeding the size of the one governing the special alignment.
math-mode horizontal-alignment align arrays
math-mode horizontal-alignment align arrays
asked 11 mins ago
PGmathPGmath
1011
New contributor
PGmath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 11 mins ago
PGmathPGmath
1011
New contributor
PGmath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 11 mins ago
PGmathPGmath
1011
New contributor
PGmath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 11 mins ago
PGmathPGmath
1011
asked 11 mins ago
PGmathPGmath
1011
1011
New contributor
PGmath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
PGmath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
PGmath is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
1 Answer
1
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oldest
votes
try
documentclass{article}
usepackage{array,amsmath}
begin{document}
[
begin{array}{>{displaystyle}c @{{}={}} >{displaystyle}c @{{}+{}} >{displaystyle}c @{{}+{}} >{displaystyle}c}
sum_{r=0}^{n+1} binom{n+1}{r}
& binom{n+1}{0} & binom{n+1}{1} + ldots + binom{n+1}{n} & binom{n+1}{n+1} \
& 1 & sumlimits_{r=1}^n binom{n+1}{r} & 1 \
& multicolumn{3}{>{displaystyle}l}{
2 + sum_{r=1}^nleft[binom{n}{r} + binom{n}{r-1}right]
}
end{array}
]
end{document}
answered 33 secs ago
ZarkoZarko
126k868165
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
try
documentclass{article}
usepackage{array,amsmath}
begin{document}
[
begin{array}{>{displaystyle}c @{{}={}} >{displaystyle}c @{{}+{}} >{displaystyle}c @{{}+{}} >{displaystyle}c}
sum_{r=0}^{n+1} binom{n+1}{r}
& binom{n+1}{0} & binom{n+1}{1} + ldots + binom{n+1}{n} & binom{n+1}{n+1} \
& 1 & sumlimits_{r=1}^n binom{n+1}{r} & 1 \
& multicolumn{3}{>{displaystyle}l}{
2 + sum_{r=1}^nleft[binom{n}{r} + binom{n}{r-1}right]
}
end{array}
]
end{document}
answered 33 secs ago
ZarkoZarko
126k868165
add a comment |
try
documentclass{article}
usepackage{array,amsmath}
begin{document}
[
begin{array}{>{displaystyle}c @{{}={}} >{displaystyle}c @{{}+{}} >{displaystyle}c @{{}+{}} >{displaystyle}c}
sum_{r=0}^{n+1} binom{n+1}{r}
& binom{n+1}{0} & binom{n+1}{1} + ldots + binom{n+1}{n} & binom{n+1}{n+1} \
& 1 & sumlimits_{r=1}^n binom{n+1}{r} & 1 \
& multicolumn{3}{>{displaystyle}l}{
2 + sum_{r=1}^nleft[binom{n}{r} + binom{n}{r-1}right]
}
end{array}
]
end{document}
answered 33 secs ago
ZarkoZarko
126k868165
add a comment |
try
documentclass{article}
usepackage{array,amsmath}
begin{document}
[
begin{array}{>{displaystyle}c @{{}={}} >{displaystyle}c @{{}+{}} >{displaystyle}c @{{}+{}} >{displaystyle}c}
sum_{r=0}^{n+1} binom{n+1}{r}
& binom{n+1}{0} & binom{n+1}{1} + ldots + binom{n+1}{n} & binom{n+1}{n+1} \
& 1 & sumlimits_{r=1}^n binom{n+1}{r} & 1 \
& multicolumn{3}{>{displaystyle}l}{
2 + sum_{r=1}^nleft[binom{n}{r} + binom{n}{r-1}right]
}
end{array}
]
end{document}
answered 33 secs ago
ZarkoZarko
126k868165
try
documentclass{article}
usepackage{array,amsmath}
begin{document}
[
begin{array}{>{displaystyle}c @{{}={}} >{displaystyle}c @{{}+{}} >{displaystyle}c @{{}+{}} >{displaystyle}c}
sum_{r=0}^{n+1} binom{n+1}{r}
& binom{n+1}{0} & binom{n+1}{1} + ldots + binom{n+1}{n} & binom{n+1}{n+1} \
& 1 & sumlimits_{r=1}^n binom{n+1}{r} & 1 \
& multicolumn{3}{>{displaystyle}l}{
2 + sum_{r=1}^nleft[binom{n}{r} + binom{n}{r-1}right]
}
end{array}
]
end{document}
answered 33 secs ago
ZarkoZarko
126k868165
answered 33 secs ago
ZarkoZarko
126k868165
answered 33 secs ago
ZarkoZarko
126k868165
answered 33 secs ago
ZarkoZarko
126k868165
126k868165
add a comment |
add a comment |
PGmath is a new contributor. Be nice, and check out our Code of Conduct.
PGmath is a new contributor. Be nice, and check out our Code of Conduct.
PGmath is a new contributor. Be nice, and check out our Code of Conduct.
PGmath is a new contributor. Be nice, and check out our Code of Conduct.
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