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Partial derivative command with Deltas in line
How can I put a line above a section heading and prevent a page break between?Partial derivative macroPutting a function into a new command with optional argumentswrapfig with {R} remains left and keeps white space to the rightHow do I center and scale vertical harpoons?String comparisons not working with textgreekPlace something in the middle of a hphantom (more or less)Choppy equations with tex4htBeamer raggedright unintended for complete line instead of part of the lineMake paired delimiter with prefix for Re and Im
I would like to create a new command for partial derivatives. I have something like this in mind:
newcommand{deriv}[2]{frac{partial #1}{partial #2}}
However, the partial commands are unfortunately not horizontally aligned, if I have e.g something like:
deriv{x^alpha}{t},
i.e. if argument #1 has a wider horizontal extent as argument #2. How can I enforce that the partial commands are always horizontally aligned?
math-mode horizontal-alignment
edited Jul 30 '17 at 12:55
Werner
446k699871692
asked Jul 29 '17 at 21:27
DonkeyKongDonkeyKong
587
add a comment |
I would like to create a new command for partial derivatives. I have something like this in mind:
newcommand{deriv}[2]{frac{partial #1}{partial #2}}
However, the partial commands are unfortunately not horizontally aligned, if I have e.g something like:
deriv{x^alpha}{t},
i.e. if argument #1 has a wider horizontal extent as argument #2. How can I enforce that the partial commands are always horizontally aligned?
math-mode horizontal-alignment
edited Jul 30 '17 at 12:55
Werner
446k699871692
asked Jul 29 '17 at 21:27
DonkeyKongDonkeyKong
587
1
I am pretty sure, the usual suspects will show up withesdiffsolutions etc. ;-)
– Christian Hupfer
Jul 29 '17 at 21:49
@egreg I want a horizontal slash, accordingly/does not suit well for me.
– DonkeyKong
Jul 29 '17 at 22:06
2
Like @JohnKormylo, I suspect that, when you say “in line”, you actually mean “vertically aligned” (like what you would get from, say,newcommand*{deriv}[2]{frac{partial #1}{partial #2hfill}}).
– GuM
Jul 29 '17 at 22:41
2
@GuM - You could add another hfill to the top, just in case.
– John Kormylo
Jul 29 '17 at 22:46
add a comment |
I would like to create a new command for partial derivatives. I have something like this in mind:
newcommand{deriv}[2]{frac{partial #1}{partial #2}}
However, the partial commands are unfortunately not horizontally aligned, if I have e.g something like:
deriv{x^alpha}{t},
i.e. if argument #1 has a wider horizontal extent as argument #2. How can I enforce that the partial commands are always horizontally aligned?
math-mode horizontal-alignment
edited Jul 30 '17 at 12:55
Werner
446k699871692
asked Jul 29 '17 at 21:27
DonkeyKongDonkeyKong
587
I would like to create a new command for partial derivatives. I have something like this in mind:
newcommand{deriv}[2]{frac{partial #1}{partial #2}}
However, the partial commands are unfortunately not horizontally aligned, if I have e.g something like:
deriv{x^alpha}{t},
i.e. if argument #1 has a wider horizontal extent as argument #2. How can I enforce that the partial commands are always horizontally aligned?
math-mode horizontal-alignment
math-mode horizontal-alignment
edited Jul 30 '17 at 12:55
Werner
446k699871692
asked Jul 29 '17 at 21:27
DonkeyKongDonkeyKong
587
edited Jul 30 '17 at 12:55
Werner
446k699871692
asked Jul 29 '17 at 21:27
DonkeyKongDonkeyKong
587
edited Jul 30 '17 at 12:55
Werner
446k699871692
edited Jul 30 '17 at 12:55
Werner
446k699871692
edited Jul 30 '17 at 12:55
Werner
446k699871692
446k699871692
asked Jul 29 '17 at 21:27
DonkeyKongDonkeyKong
587
asked Jul 29 '17 at 21:27
DonkeyKongDonkeyKong
587
asked Jul 29 '17 at 21:27
DonkeyKongDonkeyKong
587
587
1
I am pretty sure, the usual suspects will show up withesdiffsolutions etc. ;-)
– Christian Hupfer
Jul 29 '17 at 21:49
@egreg I want a horizontal slash, accordingly/does not suit well for me.
– DonkeyKong
Jul 29 '17 at 22:06
2
Like @JohnKormylo, I suspect that, when you say “in line”, you actually mean “vertically aligned” (like what you would get from, say,newcommand*{deriv}[2]{frac{partial #1}{partial #2hfill}}).
– GuM
Jul 29 '17 at 22:41
2
@GuM - You could add another hfill to the top, just in case.
– John Kormylo
Jul 29 '17 at 22:46
add a comment |
1
I am pretty sure, the usual suspects will show up withesdiffsolutions etc. ;-)
– Christian Hupfer
Jul 29 '17 at 21:49
@egreg I want a horizontal slash, accordingly/does not suit well for me.
– DonkeyKong
Jul 29 '17 at 22:06
2
Like @JohnKormylo, I suspect that, when you say “in line”, you actually mean “vertically aligned” (like what you would get from, say,newcommand*{deriv}[2]{frac{partial #1}{partial #2hfill}}).
– GuM
Jul 29 '17 at 22:41
2
@GuM - You could add another hfill to the top, just in case.
– John Kormylo
Jul 29 '17 at 22:46
1
1
I am pretty sure, the usual suspects will show up with
esdiff solutions etc. ;-)– Christian Hupfer
Jul 29 '17 at 21:49
I am pretty sure, the usual suspects will show up with
esdiff solutions etc. ;-)– Christian Hupfer
Jul 29 '17 at 21:49
@egreg I want a horizontal slash, accordingly
/ does not suit well for me.– DonkeyKong
Jul 29 '17 at 22:06
@egreg I want a horizontal slash, accordingly
/ does not suit well for me.– DonkeyKong
Jul 29 '17 at 22:06
2
2
Like @JohnKormylo, I suspect that, when you say “in line”, you actually mean “vertically aligned” (like what you would get from, say,
newcommand*{deriv}[2]{frac{partial #1}{partial #2hfill}}).– GuM
Jul 29 '17 at 22:41
Like @JohnKormylo, I suspect that, when you say “in line”, you actually mean “vertically aligned” (like what you would get from, say,
newcommand*{deriv}[2]{frac{partial #1}{partial #2hfill}}).– GuM
Jul 29 '17 at 22:41
2
2
@GuM - You could add another hfill to the top, just in case.
– John Kormylo
Jul 29 '17 at 22:46
@GuM - You could add another hfill to the top, just in case.
– John Kormylo
Jul 29 '17 at 22:46
add a comment |
2 Answers
2
active
oldest
votes
Set the numerator and denominator in a box of similar width and ensure they are both [l]eft-aligned. This is easily done using eqparbox and automated below to allow for any number of derivs (using a counter).
documentclass{article}
usepackage{eqparbox}
newcounter{derivcnt}
newcommand{deriv}[2]{%
stepcounter{derivcnt}%
frac
{eqmakebox[deriv-thederivcnt][l]{$partial #1$}}
{eqmakebox[deriv-thederivcnt][l]{$partial #2$}}}
begin{document}
[
deriv{a}{b} + deriv{abc}{d} - deriv{a}{bcd}
]
end{document}
Since this approach uses the .aux files to store the lengths of the boxes, multiple compilations are required with every change in the deriv content.
answered Jul 30 '17 at 13:00
WernerWerner
446k699871692
add a comment |
You can check the diffcoeff package. It has many ready to use commands for a variety of differential operators
documentclass[]{article}
usepackage{amsmath}
usepackage{diffcoeff}
begin{document}
[ diff{y}{x} , diffp[2]{f}{t} , diffp{f}{x,y} ]
end{document}
edited 7 mins ago
quark67
19615
answered Jul 30 '17 at 13:00
macmac
695716
I don't know this package, but I think it's not correctly made. For 2nd partial on should use different spacing like $partial^2!f$
– Jan Filip
Jul 30 '17 at 13:14
You are right I know what you mean. I don't think it will work like this.
– mac
Jul 30 '17 at 13:25
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Set the numerator and denominator in a box of similar width and ensure they are both [l]eft-aligned. This is easily done using eqparbox and automated below to allow for any number of derivs (using a counter).
documentclass{article}
usepackage{eqparbox}
newcounter{derivcnt}
newcommand{deriv}[2]{%
stepcounter{derivcnt}%
frac
{eqmakebox[deriv-thederivcnt][l]{$partial #1$}}
{eqmakebox[deriv-thederivcnt][l]{$partial #2$}}}
begin{document}
[
deriv{a}{b} + deriv{abc}{d} - deriv{a}{bcd}
]
end{document}
Since this approach uses the .aux files to store the lengths of the boxes, multiple compilations are required with every change in the deriv content.
answered Jul 30 '17 at 13:00
WernerWerner
446k699871692
add a comment |
Set the numerator and denominator in a box of similar width and ensure they are both [l]eft-aligned. This is easily done using eqparbox and automated below to allow for any number of derivs (using a counter).
documentclass{article}
usepackage{eqparbox}
newcounter{derivcnt}
newcommand{deriv}[2]{%
stepcounter{derivcnt}%
frac
{eqmakebox[deriv-thederivcnt][l]{$partial #1$}}
{eqmakebox[deriv-thederivcnt][l]{$partial #2$}}}
begin{document}
[
deriv{a}{b} + deriv{abc}{d} - deriv{a}{bcd}
]
end{document}
Since this approach uses the .aux files to store the lengths of the boxes, multiple compilations are required with every change in the deriv content.
answered Jul 30 '17 at 13:00
WernerWerner
446k699871692
add a comment |
Set the numerator and denominator in a box of similar width and ensure they are both [l]eft-aligned. This is easily done using eqparbox and automated below to allow for any number of derivs (using a counter).
documentclass{article}
usepackage{eqparbox}
newcounter{derivcnt}
newcommand{deriv}[2]{%
stepcounter{derivcnt}%
frac
{eqmakebox[deriv-thederivcnt][l]{$partial #1$}}
{eqmakebox[deriv-thederivcnt][l]{$partial #2$}}}
begin{document}
[
deriv{a}{b} + deriv{abc}{d} - deriv{a}{bcd}
]
end{document}
Since this approach uses the .aux files to store the lengths of the boxes, multiple compilations are required with every change in the deriv content.
answered Jul 30 '17 at 13:00
WernerWerner
446k699871692
Set the numerator and denominator in a box of similar width and ensure they are both [l]eft-aligned. This is easily done using eqparbox and automated below to allow for any number of derivs (using a counter).
documentclass{article}
usepackage{eqparbox}
newcounter{derivcnt}
newcommand{deriv}[2]{%
stepcounter{derivcnt}%
frac
{eqmakebox[deriv-thederivcnt][l]{$partial #1$}}
{eqmakebox[deriv-thederivcnt][l]{$partial #2$}}}
begin{document}
[
deriv{a}{b} + deriv{abc}{d} - deriv{a}{bcd}
]
end{document}
Since this approach uses the .aux files to store the lengths of the boxes, multiple compilations are required with every change in the deriv content.
answered Jul 30 '17 at 13:00
WernerWerner
446k699871692
answered Jul 30 '17 at 13:00
WernerWerner
446k699871692
answered Jul 30 '17 at 13:00
WernerWerner
446k699871692
answered Jul 30 '17 at 13:00
WernerWerner
446k699871692
446k699871692
add a comment |
add a comment |
You can check the diffcoeff package. It has many ready to use commands for a variety of differential operators
documentclass[]{article}
usepackage{amsmath}
usepackage{diffcoeff}
begin{document}
[ diff{y}{x} , diffp[2]{f}{t} , diffp{f}{x,y} ]
end{document}
edited 7 mins ago
quark67
19615
answered Jul 30 '17 at 13:00
macmac
695716
I don't know this package, but I think it's not correctly made. For 2nd partial on should use different spacing like $partial^2!f$
– Jan Filip
Jul 30 '17 at 13:14
You are right I know what you mean. I don't think it will work like this.
– mac
Jul 30 '17 at 13:25
add a comment |
You can check the diffcoeff package. It has many ready to use commands for a variety of differential operators
documentclass[]{article}
usepackage{amsmath}
usepackage{diffcoeff}
begin{document}
[ diff{y}{x} , diffp[2]{f}{t} , diffp{f}{x,y} ]
end{document}
edited 7 mins ago
quark67
19615
answered Jul 30 '17 at 13:00
macmac
695716
I don't know this package, but I think it's not correctly made. For 2nd partial on should use different spacing like $partial^2!f$
– Jan Filip
Jul 30 '17 at 13:14
You are right I know what you mean. I don't think it will work like this.
– mac
Jul 30 '17 at 13:25
add a comment |
You can check the diffcoeff package. It has many ready to use commands for a variety of differential operators
documentclass[]{article}
usepackage{amsmath}
usepackage{diffcoeff}
begin{document}
[ diff{y}{x} , diffp[2]{f}{t} , diffp{f}{x,y} ]
end{document}
edited 7 mins ago
quark67
19615
answered Jul 30 '17 at 13:00
macmac
695716
You can check the diffcoeff package. It has many ready to use commands for a variety of differential operators
documentclass[]{article}
usepackage{amsmath}
usepackage{diffcoeff}
begin{document}
[ diff{y}{x} , diffp[2]{f}{t} , diffp{f}{x,y} ]
end{document}
edited 7 mins ago
quark67
19615
answered Jul 30 '17 at 13:00
macmac
695716
edited 7 mins ago
quark67
19615
edited 7 mins ago
quark67
19615
edited 7 mins ago
quark67
19615
19615
answered Jul 30 '17 at 13:00
macmac
695716
answered Jul 30 '17 at 13:00
macmac
695716
answered Jul 30 '17 at 13:00
macmac
695716
695716
I don't know this package, but I think it's not correctly made. For 2nd partial on should use different spacing like $partial^2!f$
– Jan Filip
Jul 30 '17 at 13:14
You are right I know what you mean. I don't think it will work like this.
– mac
Jul 30 '17 at 13:25
add a comment |
I don't know this package, but I think it's not correctly made. For 2nd partial on should use different spacing like $partial^2!f$
– Jan Filip
Jul 30 '17 at 13:14
You are right I know what you mean. I don't think it will work like this.
– mac
Jul 30 '17 at 13:25
I don't know this package, but I think it's not correctly made. For 2nd partial on should use different spacing like $partial^2!f$
– Jan Filip
Jul 30 '17 at 13:14
I don't know this package, but I think it's not correctly made. For 2nd partial on should use different spacing like $partial^2!f$
– Jan Filip
Jul 30 '17 at 13:14
You are right I know what you mean. I don't think it will work like this.
– mac
Jul 30 '17 at 13:25
You are right I know what you mean. I don't think it will work like this.
– mac
Jul 30 '17 at 13:25
add a comment |
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1
I am pretty sure, the usual suspects will show up with
esdiffsolutions etc. ;-)– Christian Hupfer
Jul 29 '17 at 21:49
@egreg I want a horizontal slash, accordingly
/does not suit well for me.– DonkeyKong
Jul 29 '17 at 22:06
2
Like @JohnKormylo, I suspect that, when you say “in line”, you actually mean “vertically aligned” (like what you would get from, say,
newcommand*{deriv}[2]{frac{partial #1}{partial #2hfill}}).– GuM
Jul 29 '17 at 22:41
2
@GuM - You could add another hfill to the top, just in case.
– John Kormylo
Jul 29 '17 at 22:46