What expression will give age in years in QGIS? The Next CEO of Stack OverflowQGIS Points to...
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What expression will give age in years in QGIS?
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I have the date at which a pipe was laid. I want to create a field giving the age of the pipe in years. How do I do this in QGIS?
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I have the date at which a pipe was laid. I want to create a field giving the age of the pipe in years. How do I do this in QGIS?
qgis-plugins
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TraineeGIS is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I have the date at which a pipe was laid. I want to create a field giving the age of the pipe in years. How do I do this in QGIS?
qgis-plugins
New contributor
TraineeGIS is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I have the date at which a pipe was laid. I want to create a field giving the age of the pipe in years. How do I do this in QGIS?
qgis-plugins
qgis-plugins
New contributor
TraineeGIS is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
TraineeGIS is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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edited 5 hours ago
Vince
14.8k32849
14.8k32849
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asked 6 hours ago
TraineeGISTraineeGIS
113
113
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TraineeGIS is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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2 Answers
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Or use the age function
year(age(now() ,"yourdatefield"))
Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P
– Gabriel C.
5 hours ago
add a comment |
From the field calculator, this expression could do the trick:
year(now()) - year('the laying date')
Check if the date format will work, but aside from that, it should be pretty easy. The laying date can be replaced by a field value.
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Or use the age function
year(age(now() ,"yourdatefield"))
Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P
– Gabriel C.
5 hours ago
add a comment |
Or use the age function
year(age(now() ,"yourdatefield"))
Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P
– Gabriel C.
5 hours ago
add a comment |
Or use the age function
year(age(now() ,"yourdatefield"))
Or use the age function
year(age(now() ,"yourdatefield"))
answered 5 hours ago
cskcsk
9,4601035
9,4601035
Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P
– Gabriel C.
5 hours ago
add a comment |
Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P
– Gabriel C.
5 hours ago
Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P
– Gabriel C.
5 hours ago
Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P
– Gabriel C.
5 hours ago
add a comment |
From the field calculator, this expression could do the trick:
year(now()) - year('the laying date')
Check if the date format will work, but aside from that, it should be pretty easy. The laying date can be replaced by a field value.
add a comment |
From the field calculator, this expression could do the trick:
year(now()) - year('the laying date')
Check if the date format will work, but aside from that, it should be pretty easy. The laying date can be replaced by a field value.
add a comment |
From the field calculator, this expression could do the trick:
year(now()) - year('the laying date')
Check if the date format will work, but aside from that, it should be pretty easy. The laying date can be replaced by a field value.
From the field calculator, this expression could do the trick:
year(now()) - year('the laying date')
Check if the date format will work, but aside from that, it should be pretty easy. The laying date can be replaced by a field value.
answered 5 hours ago
Gabriel C.Gabriel C.
1,342320
1,342320
add a comment |
add a comment |
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