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Get value of a counter

Programmatically setting a counter to a substringCreate new counter and give it a specific valueCounter too long subfigureHow to change thepage when using alphalph?one counter for multiple theorems?Accessing value in forloopnumberstringnum{counter}: “Missing number” errorextract number from jobname as counterLaTeX problem: addtocounter doesn't work with babel optionConvert string to number

1

Consider this code:

documentclass{report}

newcounter{counterA}

newcounter{counterB}

begin{document}

...

setcounter{counterA}{2}

setcounter{counterB}{3}

addtocounter{counterB}{counterA}

end{document}

When I compile I get the following error:

! Missing number, treated as zero.

<to be read again> 

                   c

l.8 addtocounter{counterB}{counterA}

How to add the value in counterA to counterB?

macros counters

share|improve this question

asked 5 hours ago

ViestursViesturs

1,92141127

• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  
  addtocounter{counterB}{value{counterA}}
  
  – moewe
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  In case that this is related to your page counter problem: due to the asynchronic page building of tex, the page counter is often not reliable in the text body.
  
  – Ulrike Fischer
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  In case Ulrike's hunch is right, you may be interested in texfaq.org/FAQ-wrongpn
  
  – moewe
  5 hours ago
  

  
  
  
  

add a comment | 

1

Consider this code:

documentclass{report}

newcounter{counterA}

newcounter{counterB}

begin{document}

...

setcounter{counterA}{2}

setcounter{counterB}{3}

addtocounter{counterB}{counterA}

end{document}

When I compile I get the following error:

! Missing number, treated as zero.

<to be read again> 

                   c

l.8 addtocounter{counterB}{counterA}

How to add the value in counterA to counterB?

macros counters

share|improve this question

asked 5 hours ago

ViestursViesturs

1,92141127

• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  
  addtocounter{counterB}{value{counterA}}
  
  – moewe
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  In case that this is related to your page counter problem: due to the asynchronic page building of tex, the page counter is often not reliable in the text body.
  
  – Ulrike Fischer
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  In case Ulrike's hunch is right, you may be interested in texfaq.org/FAQ-wrongpn
  
  – moewe
  5 hours ago
  

  
  
  
  

add a comment | 

Consider this code:

documentclass{report}

newcounter{counterA}

newcounter{counterB}

begin{document}

...

setcounter{counterA}{2}

setcounter{counterB}{3}

addtocounter{counterB}{counterA}

end{document}

When I compile I get the following error:

! Missing number, treated as zero.

<to be read again> 

                   c

l.8 addtocounter{counterB}{counterA}

How to add the value in counterA to counterB?

macros counters

share|improve this question

asked 5 hours ago

ViestursViesturs

1,92141127

documentclass{report}

newcounter{counterA}

newcounter{counterB}

begin{document}

...

setcounter{counterA}{2}

setcounter{counterB}{3}

addtocounter{counterB}{counterA}

end{document}

! Missing number, treated as zero.

<to be read again> 

                   c

l.8 addtocounter{counterB}{counterA}

share|improve this question

asked 5 hours ago

ViestursViesturs

1,92141127

share|improve this question

asked 5 hours ago

ViestursViesturs

1,92141127

asked 5 hours ago

ViestursViesturs

1,92141127

asked 5 hours ago

ViestursViesturs

1,92141127

1 Answer
1

active

oldest

votes

6

You can access the value of a counter for arithmetic or other situations where LaTeX expects a number with value{<countername>}, so

addtocounter{counterB}{value{counterA}}

should be what you are looking for.

You would use the<countername> to print (a representation of) the value.

thecounterB

Gives

5

in the example.

In rare situations or when you define the<countername> you may have to use

arabic{<countername>}

roman{<countername>}

Roman{<countername>}

alph{<countername>}

Alph{<countername>}

to force a particular printed representation.

share|improve this answer

edited 4 hours ago

answered 5 hours ago

moewemoewe

96.2k10117360

add a comment | 

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6

You can access the value of a counter for arithmetic or other situations where LaTeX expects a number with value{<countername>}, so

addtocounter{counterB}{value{counterA}}

should be what you are looking for.

You would use the<countername> to print (a representation of) the value.

thecounterB

Gives

5

in the example.

In rare situations or when you define the<countername> you may have to use

arabic{<countername>}

roman{<countername>}

Roman{<countername>}

alph{<countername>}

Alph{<countername>}

to force a particular printed representation.

share|improve this answer

edited 4 hours ago

answered 5 hours ago

moewemoewe

96.2k10117360

add a comment | 

6

You can access the value of a counter for arithmetic or other situations where LaTeX expects a number with value{<countername>}, so

addtocounter{counterB}{value{counterA}}

should be what you are looking for.

You would use the<countername> to print (a representation of) the value.

thecounterB

Gives

5

in the example.

In rare situations or when you define the<countername> you may have to use

arabic{<countername>}

roman{<countername>}

Roman{<countername>}

alph{<countername>}

Alph{<countername>}

to force a particular printed representation.

share|improve this answer

edited 4 hours ago

answered 5 hours ago

moewemoewe

96.2k10117360

add a comment | 

You can access the value of a counter for arithmetic or other situations where LaTeX expects a number with value{<countername>}, so

addtocounter{counterB}{value{counterA}}

should be what you are looking for.

You would use the<countername> to print (a representation of) the value.

thecounterB

Gives

5

in the example.

In rare situations or when you define the<countername> you may have to use

arabic{<countername>}

roman{<countername>}

Roman{<countername>}

alph{<countername>}

Alph{<countername>}

to force a particular printed representation.

share|improve this answer

edited 4 hours ago

answered 5 hours ago

moewemoewe

96.2k10117360

addtocounter{counterB}{value{counterA}}

thecounterB

arabic{<countername>}

roman{<countername>}

Roman{<countername>}

alph{<countername>}

Alph{<countername>}

share|improve this answer

edited 4 hours ago

answered 5 hours ago

moewemoewe

96.2k10117360

answered 5 hours ago

moewemoewe

96.2k10117360

answered 5 hours ago

moewemoewe

96.2k10117360