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How to plot this group bar plot?
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$begingroup$

I want to generate a barplot with the following characteristics.
There are 5 users in the system. Each user has a demand.
There are 2 suppliers.
Each supplier tries to meet user demand as closely as possible.
One supplier may perform better than the other supplier.
I want a grouped barplot.
There will be two bars for each user (demand and supply)
The supply bar should combine the supplies from two supplies in such a way that the
For example,
Demand = {10, 15, 20, 17, 9};
Supply1 = {8, 13, 18, 14, 11};
Supply2 = {9, 14, 19, 16, 10};
I just want to combine Supply1 and Supply2 in one bar. So, there will only five supply bars. The demand bars and the supply bars are then grouped as shown in the attached figure.
It is like putting one supply bar above another but both should be visible. The shorter one will always on top so that both are visible.
But the problem I have with this plot is that for the last group, I cannot see the red bar, which is somehow hidden below the purple bar.
This one I obtained with MATLAB. I hope Mathematica can help me with what I need.
plotting graphics charts
$endgroup$
|
show 1 more comment
$begingroup$

I want to generate a barplot with the following characteristics.
There are 5 users in the system. Each user has a demand.
There are 2 suppliers.
Each supplier tries to meet user demand as closely as possible.
One supplier may perform better than the other supplier.
I want a grouped barplot.
There will be two bars for each user (demand and supply)
The supply bar should combine the supplies from two supplies in such a way that the
For example,
Demand = {10, 15, 20, 17, 9};
Supply1 = {8, 13, 18, 14, 11};
Supply2 = {9, 14, 19, 16, 10};
I just want to combine Supply1 and Supply2 in one bar. So, there will only five supply bars. The demand bars and the supply bars are then grouped as shown in the attached figure.
It is like putting one supply bar above another but both should be visible. The shorter one will always on top so that both are visible.
But the problem I have with this plot is that for the last group, I cannot see the red bar, which is somehow hidden below the purple bar.
This one I obtained with MATLAB. I hope Mathematica can help me with what I need.
plotting graphics charts
$endgroup$
$begingroup$
What have you tried so far usingBarChart?
$endgroup$
– MarcoB
3 hours ago
$begingroup$
@kglr, this is not what I want. I have revised my question...
$endgroup$
– dipak narayanan
2 hours ago
$begingroup$
try adding the optionChartBaseStyle -> Opacity[.5]?
$endgroup$
– kglr
2 hours ago
$begingroup$
@kglr, but the attached figure I obtained with MATLAB. So, then the first question is how to obtain such a plot in Mathematica? Also, I want it without Opacity feature.
$endgroup$
– dipak narayanan
2 hours ago
1
$begingroup$
I'm voting to close this question as off-topic because the OP is asking for the impossible, despite reasonable suggestions. Furthermore, any solution will be extremely localized to their problem only.
$endgroup$
– MarcoB
1 hour ago
|
show 1 more comment
$begingroup$

I want to generate a barplot with the following characteristics.
There are 5 users in the system. Each user has a demand.
There are 2 suppliers.
Each supplier tries to meet user demand as closely as possible.
One supplier may perform better than the other supplier.
I want a grouped barplot.
There will be two bars for each user (demand and supply)
The supply bar should combine the supplies from two supplies in such a way that the
For example,
Demand = {10, 15, 20, 17, 9};
Supply1 = {8, 13, 18, 14, 11};
Supply2 = {9, 14, 19, 16, 10};
I just want to combine Supply1 and Supply2 in one bar. So, there will only five supply bars. The demand bars and the supply bars are then grouped as shown in the attached figure.
It is like putting one supply bar above another but both should be visible. The shorter one will always on top so that both are visible.
But the problem I have with this plot is that for the last group, I cannot see the red bar, which is somehow hidden below the purple bar.
This one I obtained with MATLAB. I hope Mathematica can help me with what I need.
plotting graphics charts
$endgroup$

I want to generate a barplot with the following characteristics.
There are 5 users in the system. Each user has a demand.
There are 2 suppliers.
Each supplier tries to meet user demand as closely as possible.
One supplier may perform better than the other supplier.
I want a grouped barplot.
There will be two bars for each user (demand and supply)
The supply bar should combine the supplies from two supplies in such a way that the
For example,
Demand = {10, 15, 20, 17, 9};
Supply1 = {8, 13, 18, 14, 11};
Supply2 = {9, 14, 19, 16, 10};
I just want to combine Supply1 and Supply2 in one bar. So, there will only five supply bars. The demand bars and the supply bars are then grouped as shown in the attached figure.
It is like putting one supply bar above another but both should be visible. The shorter one will always on top so that both are visible.
But the problem I have with this plot is that for the last group, I cannot see the red bar, which is somehow hidden below the purple bar.
This one I obtained with MATLAB. I hope Mathematica can help me with what I need.
plotting graphics charts
plotting graphics charts
edited 1 hour ago
MarcoB
37k556113
37k556113
asked 3 hours ago
dipak narayanandipak narayanan
1216
1216
$begingroup$
What have you tried so far usingBarChart?
$endgroup$
– MarcoB
3 hours ago
$begingroup$
@kglr, this is not what I want. I have revised my question...
$endgroup$
– dipak narayanan
2 hours ago
$begingroup$
try adding the optionChartBaseStyle -> Opacity[.5]?
$endgroup$
– kglr
2 hours ago
$begingroup$
@kglr, but the attached figure I obtained with MATLAB. So, then the first question is how to obtain such a plot in Mathematica? Also, I want it without Opacity feature.
$endgroup$
– dipak narayanan
2 hours ago
1
$begingroup$
I'm voting to close this question as off-topic because the OP is asking for the impossible, despite reasonable suggestions. Furthermore, any solution will be extremely localized to their problem only.
$endgroup$
– MarcoB
1 hour ago
|
show 1 more comment
$begingroup$
What have you tried so far usingBarChart?
$endgroup$
– MarcoB
3 hours ago
$begingroup$
@kglr, this is not what I want. I have revised my question...
$endgroup$
– dipak narayanan
2 hours ago
$begingroup$
try adding the optionChartBaseStyle -> Opacity[.5]?
$endgroup$
– kglr
2 hours ago
$begingroup$
@kglr, but the attached figure I obtained with MATLAB. So, then the first question is how to obtain such a plot in Mathematica? Also, I want it without Opacity feature.
$endgroup$
– dipak narayanan
2 hours ago
1
$begingroup$
I'm voting to close this question as off-topic because the OP is asking for the impossible, despite reasonable suggestions. Furthermore, any solution will be extremely localized to their problem only.
$endgroup$
– MarcoB
1 hour ago
$begingroup$
What have you tried so far using
BarChart?$endgroup$
– MarcoB
3 hours ago
$begingroup$
What have you tried so far using
BarChart?$endgroup$
– MarcoB
3 hours ago
$begingroup$
@kglr, this is not what I want. I have revised my question...
$endgroup$
– dipak narayanan
2 hours ago
$begingroup$
@kglr, this is not what I want. I have revised my question...
$endgroup$
– dipak narayanan
2 hours ago
$begingroup$
try adding the option
ChartBaseStyle -> Opacity[.5]?$endgroup$
– kglr
2 hours ago
$begingroup$
try adding the option
ChartBaseStyle -> Opacity[.5]?$endgroup$
– kglr
2 hours ago
$begingroup$
@kglr, but the attached figure I obtained with MATLAB. So, then the first question is how to obtain such a plot in Mathematica? Also, I want it without Opacity feature.
$endgroup$
– dipak narayanan
2 hours ago
$begingroup$
@kglr, but the attached figure I obtained with MATLAB. So, then the first question is how to obtain such a plot in Mathematica? Also, I want it without Opacity feature.
$endgroup$
– dipak narayanan
2 hours ago
1
1
$begingroup$
I'm voting to close this question as off-topic because the OP is asking for the impossible, despite reasonable suggestions. Furthermore, any solution will be extremely localized to their problem only.
$endgroup$
– MarcoB
1 hour ago
$begingroup$
I'm voting to close this question as off-topic because the OP is asking for the impossible, despite reasonable suggestions. Furthermore, any solution will be extremely localized to their problem only.
$endgroup$
– MarcoB
1 hour ago
|
show 1 more comment
2 Answers
2
active
oldest
votes
$begingroup$
BarChart does not support mixed layouts (it does not allow combining Grouped and Overlapped layouts). So, we cheat by inserting fake data sets with 0 height betweeen groups to separate the five groups:
demand = {10, 15, 20, 17, 9};
supply1 = {8, 13, 18, 14, 11};
supply2 = {9, 14, 19, 16, 10};
s = Transpose[{Style[#, Blue] & /@ supply1, Style[#, Yellow] & /@ supply2}];
d = Thread[{Style[#, Red] & /@ demand, Style[0, Opacity[0]]}];
data = Join @@ Thread[{0, 0, 0, 0, 0, d, s}];
bc = BarChart[data,
ChartLayout -> "Overlapped",
ChartLegends -> SwatchLegend[{Red, Blue, Yellow}, {"D", "S1", "S2"}],
BarSpacing -> {0, .1}, PerformanceGoal -> "Speed"];

To make all rectangles visible, we post-process to re-order the yellow and blue rectangles based on their heights (I added PerformanceGoal -> "Speed" above to make this post-processing easier):
bc /. pattern : {{_, Rectangle[{_, _}, {_, h1_}, ___]}, {_,
Rectangle[{_, _}, {_, h2_}, ___]}} :> If[h2 <= h1, pattern, Reverse[pattern]]

Fixing ticks and labels is an altogether different challenge.
Update: An alternative, more convenient and better, approach is to pre-process data to reorder based on heights:
sb = If[#[[1]] <= #[[2]],
{Style[#[[2]], Yellow], Style[#[[1]], Blue]},
{Style[#[[1]], Blue], Style[#[[2]], Yellow]}] & /@
Transpose[{supply1, supply2}];
datab = Join @@ Thread[{0, 0, 0, 0, 0, d, sb}];
bcb = BarChart[datab, ChartLayout -> "Overlapped",
ChartLegends -> SwatchLegend[{Red, Blue, Yellow}, {"D", "S1", "S2"}],
BarSpacing -> {0, .1}]

With this approach we don't need to add PerformanceGoal -> "Speed", thus we retain all the tool-tips and and dynamic highlighting.
Update 2: Better approach to pre-processing inspired by m_goldberg's answer:
b1 = BarChart[Transpose[{Style[#, Red] & /@ demand,
If[#[[1]] <= #[[2]], Style[#[[2]], Yellow],
Style[#[[1]], Blue]] & /@ Transpose[{supply1, supply2}]}],
ChartLabels -> {Placed["Group " <> ToString[#] & /@ Range[5], Axis],
Placed[{"D", "S"}, Axis]},
ChartLegends -> SwatchLegend[{Red, Blue, Yellow}, {"D", "S1", "S2"}]];
b2 = BarChart[Transpose[{Style[#, Red] & /@ demand,
If[#[[1]] <= #[[2]], Style[#[[1]], Blue],
Style[#[[2]], Yellow]] & /@ Transpose[{supply1, supply2}]}]];
Show[b1, b2]

$endgroup$
$begingroup$
Yep, this is the kind of heroic effort that I was hinting at in my comments... Thank you for trying though. (+1)
$endgroup$
– MarcoB
1 hour ago
$begingroup$
thank you @MarcoB.
$endgroup$
– kglr
1 hour ago
add a comment |
$begingroup$
This will reproduce your matlab generated chart.
Demand = {10, 15, 20, 17, 9};
Supply1 = {8, 13, 18, 14, 11};
Supply2 = {9, 14, 19, 16, 10};
b1 = BarChart[Transpose[{Demand, Supply2}],
ChartStyle -> {{Automatic}, {Automatic, Red}}];
b2 = BarChart[Transpose[{Demand, Supply1}]];
Show[b1, b2, Frame -> True]

It has the same defect as the matlab chart — the longer blue bar at the right end of chart hides the shorter red bar behind it.
$endgroup$
add a comment |
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2 Answers
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2 Answers
2
active
oldest
votes
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oldest
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active
oldest
votes
$begingroup$
BarChart does not support mixed layouts (it does not allow combining Grouped and Overlapped layouts). So, we cheat by inserting fake data sets with 0 height betweeen groups to separate the five groups:
demand = {10, 15, 20, 17, 9};
supply1 = {8, 13, 18, 14, 11};
supply2 = {9, 14, 19, 16, 10};
s = Transpose[{Style[#, Blue] & /@ supply1, Style[#, Yellow] & /@ supply2}];
d = Thread[{Style[#, Red] & /@ demand, Style[0, Opacity[0]]}];
data = Join @@ Thread[{0, 0, 0, 0, 0, d, s}];
bc = BarChart[data,
ChartLayout -> "Overlapped",
ChartLegends -> SwatchLegend[{Red, Blue, Yellow}, {"D", "S1", "S2"}],
BarSpacing -> {0, .1}, PerformanceGoal -> "Speed"];

To make all rectangles visible, we post-process to re-order the yellow and blue rectangles based on their heights (I added PerformanceGoal -> "Speed" above to make this post-processing easier):
bc /. pattern : {{_, Rectangle[{_, _}, {_, h1_}, ___]}, {_,
Rectangle[{_, _}, {_, h2_}, ___]}} :> If[h2 <= h1, pattern, Reverse[pattern]]

Fixing ticks and labels is an altogether different challenge.
Update: An alternative, more convenient and better, approach is to pre-process data to reorder based on heights:
sb = If[#[[1]] <= #[[2]],
{Style[#[[2]], Yellow], Style[#[[1]], Blue]},
{Style[#[[1]], Blue], Style[#[[2]], Yellow]}] & /@
Transpose[{supply1, supply2}];
datab = Join @@ Thread[{0, 0, 0, 0, 0, d, sb}];
bcb = BarChart[datab, ChartLayout -> "Overlapped",
ChartLegends -> SwatchLegend[{Red, Blue, Yellow}, {"D", "S1", "S2"}],
BarSpacing -> {0, .1}]

With this approach we don't need to add PerformanceGoal -> "Speed", thus we retain all the tool-tips and and dynamic highlighting.
Update 2: Better approach to pre-processing inspired by m_goldberg's answer:
b1 = BarChart[Transpose[{Style[#, Red] & /@ demand,
If[#[[1]] <= #[[2]], Style[#[[2]], Yellow],
Style[#[[1]], Blue]] & /@ Transpose[{supply1, supply2}]}],
ChartLabels -> {Placed["Group " <> ToString[#] & /@ Range[5], Axis],
Placed[{"D", "S"}, Axis]},
ChartLegends -> SwatchLegend[{Red, Blue, Yellow}, {"D", "S1", "S2"}]];
b2 = BarChart[Transpose[{Style[#, Red] & /@ demand,
If[#[[1]] <= #[[2]], Style[#[[1]], Blue],
Style[#[[2]], Yellow]] & /@ Transpose[{supply1, supply2}]}]];
Show[b1, b2]

$endgroup$
$begingroup$
Yep, this is the kind of heroic effort that I was hinting at in my comments... Thank you for trying though. (+1)
$endgroup$
– MarcoB
1 hour ago
$begingroup$
thank you @MarcoB.
$endgroup$
– kglr
1 hour ago
add a comment |
$begingroup$
BarChart does not support mixed layouts (it does not allow combining Grouped and Overlapped layouts). So, we cheat by inserting fake data sets with 0 height betweeen groups to separate the five groups:
demand = {10, 15, 20, 17, 9};
supply1 = {8, 13, 18, 14, 11};
supply2 = {9, 14, 19, 16, 10};
s = Transpose[{Style[#, Blue] & /@ supply1, Style[#, Yellow] & /@ supply2}];
d = Thread[{Style[#, Red] & /@ demand, Style[0, Opacity[0]]}];
data = Join @@ Thread[{0, 0, 0, 0, 0, d, s}];
bc = BarChart[data,
ChartLayout -> "Overlapped",
ChartLegends -> SwatchLegend[{Red, Blue, Yellow}, {"D", "S1", "S2"}],
BarSpacing -> {0, .1}, PerformanceGoal -> "Speed"];

To make all rectangles visible, we post-process to re-order the yellow and blue rectangles based on their heights (I added PerformanceGoal -> "Speed" above to make this post-processing easier):
bc /. pattern : {{_, Rectangle[{_, _}, {_, h1_}, ___]}, {_,
Rectangle[{_, _}, {_, h2_}, ___]}} :> If[h2 <= h1, pattern, Reverse[pattern]]

Fixing ticks and labels is an altogether different challenge.
Update: An alternative, more convenient and better, approach is to pre-process data to reorder based on heights:
sb = If[#[[1]] <= #[[2]],
{Style[#[[2]], Yellow], Style[#[[1]], Blue]},
{Style[#[[1]], Blue], Style[#[[2]], Yellow]}] & /@
Transpose[{supply1, supply2}];
datab = Join @@ Thread[{0, 0, 0, 0, 0, d, sb}];
bcb = BarChart[datab, ChartLayout -> "Overlapped",
ChartLegends -> SwatchLegend[{Red, Blue, Yellow}, {"D", "S1", "S2"}],
BarSpacing -> {0, .1}]

With this approach we don't need to add PerformanceGoal -> "Speed", thus we retain all the tool-tips and and dynamic highlighting.
Update 2: Better approach to pre-processing inspired by m_goldberg's answer:
b1 = BarChart[Transpose[{Style[#, Red] & /@ demand,
If[#[[1]] <= #[[2]], Style[#[[2]], Yellow],
Style[#[[1]], Blue]] & /@ Transpose[{supply1, supply2}]}],
ChartLabels -> {Placed["Group " <> ToString[#] & /@ Range[5], Axis],
Placed[{"D", "S"}, Axis]},
ChartLegends -> SwatchLegend[{Red, Blue, Yellow}, {"D", "S1", "S2"}]];
b2 = BarChart[Transpose[{Style[#, Red] & /@ demand,
If[#[[1]] <= #[[2]], Style[#[[1]], Blue],
Style[#[[2]], Yellow]] & /@ Transpose[{supply1, supply2}]}]];
Show[b1, b2]

$endgroup$
$begingroup$
Yep, this is the kind of heroic effort that I was hinting at in my comments... Thank you for trying though. (+1)
$endgroup$
– MarcoB
1 hour ago
$begingroup$
thank you @MarcoB.
$endgroup$
– kglr
1 hour ago
add a comment |
$begingroup$
BarChart does not support mixed layouts (it does not allow combining Grouped and Overlapped layouts). So, we cheat by inserting fake data sets with 0 height betweeen groups to separate the five groups:
demand = {10, 15, 20, 17, 9};
supply1 = {8, 13, 18, 14, 11};
supply2 = {9, 14, 19, 16, 10};
s = Transpose[{Style[#, Blue] & /@ supply1, Style[#, Yellow] & /@ supply2}];
d = Thread[{Style[#, Red] & /@ demand, Style[0, Opacity[0]]}];
data = Join @@ Thread[{0, 0, 0, 0, 0, d, s}];
bc = BarChart[data,
ChartLayout -> "Overlapped",
ChartLegends -> SwatchLegend[{Red, Blue, Yellow}, {"D", "S1", "S2"}],
BarSpacing -> {0, .1}, PerformanceGoal -> "Speed"];

To make all rectangles visible, we post-process to re-order the yellow and blue rectangles based on their heights (I added PerformanceGoal -> "Speed" above to make this post-processing easier):
bc /. pattern : {{_, Rectangle[{_, _}, {_, h1_}, ___]}, {_,
Rectangle[{_, _}, {_, h2_}, ___]}} :> If[h2 <= h1, pattern, Reverse[pattern]]

Fixing ticks and labels is an altogether different challenge.
Update: An alternative, more convenient and better, approach is to pre-process data to reorder based on heights:
sb = If[#[[1]] <= #[[2]],
{Style[#[[2]], Yellow], Style[#[[1]], Blue]},
{Style[#[[1]], Blue], Style[#[[2]], Yellow]}] & /@
Transpose[{supply1, supply2}];
datab = Join @@ Thread[{0, 0, 0, 0, 0, d, sb}];
bcb = BarChart[datab, ChartLayout -> "Overlapped",
ChartLegends -> SwatchLegend[{Red, Blue, Yellow}, {"D", "S1", "S2"}],
BarSpacing -> {0, .1}]

With this approach we don't need to add PerformanceGoal -> "Speed", thus we retain all the tool-tips and and dynamic highlighting.
Update 2: Better approach to pre-processing inspired by m_goldberg's answer:
b1 = BarChart[Transpose[{Style[#, Red] & /@ demand,
If[#[[1]] <= #[[2]], Style[#[[2]], Yellow],
Style[#[[1]], Blue]] & /@ Transpose[{supply1, supply2}]}],
ChartLabels -> {Placed["Group " <> ToString[#] & /@ Range[5], Axis],
Placed[{"D", "S"}, Axis]},
ChartLegends -> SwatchLegend[{Red, Blue, Yellow}, {"D", "S1", "S2"}]];
b2 = BarChart[Transpose[{Style[#, Red] & /@ demand,
If[#[[1]] <= #[[2]], Style[#[[1]], Blue],
Style[#[[2]], Yellow]] & /@ Transpose[{supply1, supply2}]}]];
Show[b1, b2]

$endgroup$
BarChart does not support mixed layouts (it does not allow combining Grouped and Overlapped layouts). So, we cheat by inserting fake data sets with 0 height betweeen groups to separate the five groups:
demand = {10, 15, 20, 17, 9};
supply1 = {8, 13, 18, 14, 11};
supply2 = {9, 14, 19, 16, 10};
s = Transpose[{Style[#, Blue] & /@ supply1, Style[#, Yellow] & /@ supply2}];
d = Thread[{Style[#, Red] & /@ demand, Style[0, Opacity[0]]}];
data = Join @@ Thread[{0, 0, 0, 0, 0, d, s}];
bc = BarChart[data,
ChartLayout -> "Overlapped",
ChartLegends -> SwatchLegend[{Red, Blue, Yellow}, {"D", "S1", "S2"}],
BarSpacing -> {0, .1}, PerformanceGoal -> "Speed"];

To make all rectangles visible, we post-process to re-order the yellow and blue rectangles based on their heights (I added PerformanceGoal -> "Speed" above to make this post-processing easier):
bc /. pattern : {{_, Rectangle[{_, _}, {_, h1_}, ___]}, {_,
Rectangle[{_, _}, {_, h2_}, ___]}} :> If[h2 <= h1, pattern, Reverse[pattern]]

Fixing ticks and labels is an altogether different challenge.
Update: An alternative, more convenient and better, approach is to pre-process data to reorder based on heights:
sb = If[#[[1]] <= #[[2]],
{Style[#[[2]], Yellow], Style[#[[1]], Blue]},
{Style[#[[1]], Blue], Style[#[[2]], Yellow]}] & /@
Transpose[{supply1, supply2}];
datab = Join @@ Thread[{0, 0, 0, 0, 0, d, sb}];
bcb = BarChart[datab, ChartLayout -> "Overlapped",
ChartLegends -> SwatchLegend[{Red, Blue, Yellow}, {"D", "S1", "S2"}],
BarSpacing -> {0, .1}]

With this approach we don't need to add PerformanceGoal -> "Speed", thus we retain all the tool-tips and and dynamic highlighting.
Update 2: Better approach to pre-processing inspired by m_goldberg's answer:
b1 = BarChart[Transpose[{Style[#, Red] & /@ demand,
If[#[[1]] <= #[[2]], Style[#[[2]], Yellow],
Style[#[[1]], Blue]] & /@ Transpose[{supply1, supply2}]}],
ChartLabels -> {Placed["Group " <> ToString[#] & /@ Range[5], Axis],
Placed[{"D", "S"}, Axis]},
ChartLegends -> SwatchLegend[{Red, Blue, Yellow}, {"D", "S1", "S2"}]];
b2 = BarChart[Transpose[{Style[#, Red] & /@ demand,
If[#[[1]] <= #[[2]], Style[#[[1]], Blue],
Style[#[[2]], Yellow]] & /@ Transpose[{supply1, supply2}]}]];
Show[b1, b2]

edited 18 mins ago
answered 1 hour ago
kglrkglr
187k10203421
187k10203421
$begingroup$
Yep, this is the kind of heroic effort that I was hinting at in my comments... Thank you for trying though. (+1)
$endgroup$
– MarcoB
1 hour ago
$begingroup$
thank you @MarcoB.
$endgroup$
– kglr
1 hour ago
add a comment |
$begingroup$
Yep, this is the kind of heroic effort that I was hinting at in my comments... Thank you for trying though. (+1)
$endgroup$
– MarcoB
1 hour ago
$begingroup$
thank you @MarcoB.
$endgroup$
– kglr
1 hour ago
$begingroup$
Yep, this is the kind of heroic effort that I was hinting at in my comments... Thank you for trying though. (+1)
$endgroup$
– MarcoB
1 hour ago
$begingroup$
Yep, this is the kind of heroic effort that I was hinting at in my comments... Thank you for trying though. (+1)
$endgroup$
– MarcoB
1 hour ago
$begingroup$
thank you @MarcoB.
$endgroup$
– kglr
1 hour ago
$begingroup$
thank you @MarcoB.
$endgroup$
– kglr
1 hour ago
add a comment |
$begingroup$
This will reproduce your matlab generated chart.
Demand = {10, 15, 20, 17, 9};
Supply1 = {8, 13, 18, 14, 11};
Supply2 = {9, 14, 19, 16, 10};
b1 = BarChart[Transpose[{Demand, Supply2}],
ChartStyle -> {{Automatic}, {Automatic, Red}}];
b2 = BarChart[Transpose[{Demand, Supply1}]];
Show[b1, b2, Frame -> True]

It has the same defect as the matlab chart — the longer blue bar at the right end of chart hides the shorter red bar behind it.
$endgroup$
add a comment |
$begingroup$
This will reproduce your matlab generated chart.
Demand = {10, 15, 20, 17, 9};
Supply1 = {8, 13, 18, 14, 11};
Supply2 = {9, 14, 19, 16, 10};
b1 = BarChart[Transpose[{Demand, Supply2}],
ChartStyle -> {{Automatic}, {Automatic, Red}}];
b2 = BarChart[Transpose[{Demand, Supply1}]];
Show[b1, b2, Frame -> True]

It has the same defect as the matlab chart — the longer blue bar at the right end of chart hides the shorter red bar behind it.
$endgroup$
add a comment |
$begingroup$
This will reproduce your matlab generated chart.
Demand = {10, 15, 20, 17, 9};
Supply1 = {8, 13, 18, 14, 11};
Supply2 = {9, 14, 19, 16, 10};
b1 = BarChart[Transpose[{Demand, Supply2}],
ChartStyle -> {{Automatic}, {Automatic, Red}}];
b2 = BarChart[Transpose[{Demand, Supply1}]];
Show[b1, b2, Frame -> True]

It has the same defect as the matlab chart — the longer blue bar at the right end of chart hides the shorter red bar behind it.
$endgroup$
This will reproduce your matlab generated chart.
Demand = {10, 15, 20, 17, 9};
Supply1 = {8, 13, 18, 14, 11};
Supply2 = {9, 14, 19, 16, 10};
b1 = BarChart[Transpose[{Demand, Supply2}],
ChartStyle -> {{Automatic}, {Automatic, Red}}];
b2 = BarChart[Transpose[{Demand, Supply1}]];
Show[b1, b2, Frame -> True]

It has the same defect as the matlab chart — the longer blue bar at the right end of chart hides the shorter red bar behind it.
edited 9 mins ago
answered 53 mins ago
m_goldbergm_goldberg
87.4k872198
87.4k872198
add a comment |
add a comment |
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$begingroup$
What have you tried so far using
BarChart?$endgroup$
– MarcoB
3 hours ago
$begingroup$
@kglr, this is not what I want. I have revised my question...
$endgroup$
– dipak narayanan
2 hours ago
$begingroup$
try adding the option
ChartBaseStyle -> Opacity[.5]?$endgroup$
– kglr
2 hours ago
$begingroup$
@kglr, but the attached figure I obtained with MATLAB. So, then the first question is how to obtain such a plot in Mathematica? Also, I want it without Opacity feature.
$endgroup$
– dipak narayanan
2 hours ago
1
$begingroup$
I'm voting to close this question as off-topic because the OP is asking for the impossible, despite reasonable suggestions. Furthermore, any solution will be extremely localized to their problem only.
$endgroup$
– MarcoB
1 hour ago