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Recall an hypothesis
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Making a list of hypothesis and references to the hypothesisIncorrect hypothesis counterNew example environment, with symbol at the endRestart hypothesis counter in new chapterRecall a theorem in a different section of a chapteramsmath aligned environment: correct positioning of equation number on the last line with tbtagsChanging numbers of equations
I actually started to use Latex in order to prepare better works.
After that, there is a problem.
This is my code actually:
Determine Hyp 1 and 2
newtheorem{hypothesis}{Hypothesis}
begin{hypothesis} %Hyp 1
begin{justify}
[ RE>RM land RF>RM lor RE<RM land RF<RM implies ]
end{justify}par
end{hypothesis}
begin{hypothesis} %Hyp 2
begin{justify}
[ RE>RM land RF<RM lor RE<RM land RF>RM implies ]
end{justify}par
end{hypothesis}
Now i need to recall Hyp 1 and 2 and i do not want that continue to label it as 3, 4, and so on
begin{hypothesis} %Hyp1
begin{equation}
x
end{equation}par
end{hypothesis}
begin{hypothesis} %Hyp2
begin{equation}
xtimes (-1)
end{equation}par
end{hypothesis}
Writing this code, as i said, it label them as number 1, 2, 3, and 4 while i need Hyp 1, Hyp 2, Hyp1, and Hyp 2.
How can i achieve that?
Many Regards
numbering packages theorems text ntheorem
bumped to the homepage by Community♦ 2 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
add a comment |
I actually started to use Latex in order to prepare better works.
After that, there is a problem.
This is my code actually:
Determine Hyp 1 and 2
newtheorem{hypothesis}{Hypothesis}
begin{hypothesis} %Hyp 1
begin{justify}
[ RE>RM land RF>RM lor RE<RM land RF<RM implies ]
end{justify}par
end{hypothesis}
begin{hypothesis} %Hyp 2
begin{justify}
[ RE>RM land RF<RM lor RE<RM land RF>RM implies ]
end{justify}par
end{hypothesis}
Now i need to recall Hyp 1 and 2 and i do not want that continue to label it as 3, 4, and so on
begin{hypothesis} %Hyp1
begin{equation}
x
end{equation}par
end{hypothesis}
begin{hypothesis} %Hyp2
begin{equation}
xtimes (-1)
end{equation}par
end{hypothesis}
Writing this code, as i said, it label them as number 1, 2, 3, and 4 while i need Hyp 1, Hyp 2, Hyp1, and Hyp 2.
How can i achieve that?
Many Regards
numbering packages theorems text ntheorem
bumped to the homepage by Community♦ 2 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
add a comment |
I actually started to use Latex in order to prepare better works.
After that, there is a problem.
This is my code actually:
Determine Hyp 1 and 2
newtheorem{hypothesis}{Hypothesis}
begin{hypothesis} %Hyp 1
begin{justify}
[ RE>RM land RF>RM lor RE<RM land RF<RM implies ]
end{justify}par
end{hypothesis}
begin{hypothesis} %Hyp 2
begin{justify}
[ RE>RM land RF<RM lor RE<RM land RF>RM implies ]
end{justify}par
end{hypothesis}
Now i need to recall Hyp 1 and 2 and i do not want that continue to label it as 3, 4, and so on
begin{hypothesis} %Hyp1
begin{equation}
x
end{equation}par
end{hypothesis}
begin{hypothesis} %Hyp2
begin{equation}
xtimes (-1)
end{equation}par
end{hypothesis}
Writing this code, as i said, it label them as number 1, 2, 3, and 4 while i need Hyp 1, Hyp 2, Hyp1, and Hyp 2.
How can i achieve that?
Many Regards
numbering packages theorems text ntheorem
I actually started to use Latex in order to prepare better works.
After that, there is a problem.
This is my code actually:
Determine Hyp 1 and 2
newtheorem{hypothesis}{Hypothesis}
begin{hypothesis} %Hyp 1
begin{justify}
[ RE>RM land RF>RM lor RE<RM land RF<RM implies ]
end{justify}par
end{hypothesis}
begin{hypothesis} %Hyp 2
begin{justify}
[ RE>RM land RF<RM lor RE<RM land RF>RM implies ]
end{justify}par
end{hypothesis}
Now i need to recall Hyp 1 and 2 and i do not want that continue to label it as 3, 4, and so on
begin{hypothesis} %Hyp1
begin{equation}
x
end{equation}par
end{hypothesis}
begin{hypothesis} %Hyp2
begin{equation}
xtimes (-1)
end{equation}par
end{hypothesis}
Writing this code, as i said, it label them as number 1, 2, 3, and 4 while i need Hyp 1, Hyp 2, Hyp1, and Hyp 2.
How can i achieve that?
Many Regards
numbering packages theorems text ntheorem
numbering packages theorems text ntheorem
edited Jun 20 '18 at 10:59
Rufyyyyy
asked Jun 20 '18 at 10:35
RufyyyyyRufyyyyy
62
62
bumped to the homepage by Community♦ 2 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
bumped to the homepage by Community♦ 2 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
The following is pretty ugly, but gets the job done. Essentially, it makes a new command for hypothesis 1 and 2 that displays some set text and an equation that is numbered as normal. It plays around with the counter and manipulates it to be what is desired. I wasn't sure what your "justifications" were, so I replaced it with equations, but it can be adapted pretty easily based on what you have in mind.
documentclass{article}
usepackage{amsthm, amsmath}
newcounter{hypcounter}
newtheorem{hypothesis}{Hypothesis}
newcommand{firsthyp}[1]{
setcounter{hypcounter}{value{hypothesis}} % save what number we're at
setcounter{hypothesis}{0} % so that the hypothesis is numbered 1
begin{hypothesis}
My first hypothesis states some stuff
begin{equation} #1 end{equation}
end{hypothesis}
setcounter{hypothesis}{value{hypcounter}} % rewrite that number back into counter
}
newcommand{secondhyp}[1]{
setcounter{hypcounter}{value{hypothesis}}
setcounter{hypothesis}{1} % so that the hypothesis is numbered 2
begin{hypothesis}
My second hypothesis states some other stuff
begin{equation} #1 end{equation}
end{hypothesis}
setcounter{hypothesis}{value{hypcounter}}
}
begin{document}
setcounter{hypothesis}{2} % so that a hypotheses afterwards will begin at 3
firsthyp{RE>RM land RF>RM lor RE<RM land RF<RM implies}
secondhyp{RE>RM land RF<RM lor RE<RM land RF>RM implies}
begin{hypothesis}
Another hypothesis will be numbered with the next number, $3$.
begin{equation}
text{Equation numbering continue as normal}
end{equation}
end{hypothesis}
firsthyp{x}
secondhyp{xtimes (-1)}
end{document}
I thinksetcounter{hypothesis}{n}
(n= previous value) before calling the hypothesis and asetcounter{hypothesis}{x}
(x= previous than the last hypothesis) after that would be enough for an accepted answer. Or at least if you want to automate it you could do it in anewenvironment
command with possibly an optional argument... Seems too complicated to me
– koleygr
Sep 19 '18 at 1:09
add a comment |
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The following is pretty ugly, but gets the job done. Essentially, it makes a new command for hypothesis 1 and 2 that displays some set text and an equation that is numbered as normal. It plays around with the counter and manipulates it to be what is desired. I wasn't sure what your "justifications" were, so I replaced it with equations, but it can be adapted pretty easily based on what you have in mind.
documentclass{article}
usepackage{amsthm, amsmath}
newcounter{hypcounter}
newtheorem{hypothesis}{Hypothesis}
newcommand{firsthyp}[1]{
setcounter{hypcounter}{value{hypothesis}} % save what number we're at
setcounter{hypothesis}{0} % so that the hypothesis is numbered 1
begin{hypothesis}
My first hypothesis states some stuff
begin{equation} #1 end{equation}
end{hypothesis}
setcounter{hypothesis}{value{hypcounter}} % rewrite that number back into counter
}
newcommand{secondhyp}[1]{
setcounter{hypcounter}{value{hypothesis}}
setcounter{hypothesis}{1} % so that the hypothesis is numbered 2
begin{hypothesis}
My second hypothesis states some other stuff
begin{equation} #1 end{equation}
end{hypothesis}
setcounter{hypothesis}{value{hypcounter}}
}
begin{document}
setcounter{hypothesis}{2} % so that a hypotheses afterwards will begin at 3
firsthyp{RE>RM land RF>RM lor RE<RM land RF<RM implies}
secondhyp{RE>RM land RF<RM lor RE<RM land RF>RM implies}
begin{hypothesis}
Another hypothesis will be numbered with the next number, $3$.
begin{equation}
text{Equation numbering continue as normal}
end{equation}
end{hypothesis}
firsthyp{x}
secondhyp{xtimes (-1)}
end{document}
I thinksetcounter{hypothesis}{n}
(n= previous value) before calling the hypothesis and asetcounter{hypothesis}{x}
(x= previous than the last hypothesis) after that would be enough for an accepted answer. Or at least if you want to automate it you could do it in anewenvironment
command with possibly an optional argument... Seems too complicated to me
– koleygr
Sep 19 '18 at 1:09
add a comment |
The following is pretty ugly, but gets the job done. Essentially, it makes a new command for hypothesis 1 and 2 that displays some set text and an equation that is numbered as normal. It plays around with the counter and manipulates it to be what is desired. I wasn't sure what your "justifications" were, so I replaced it with equations, but it can be adapted pretty easily based on what you have in mind.
documentclass{article}
usepackage{amsthm, amsmath}
newcounter{hypcounter}
newtheorem{hypothesis}{Hypothesis}
newcommand{firsthyp}[1]{
setcounter{hypcounter}{value{hypothesis}} % save what number we're at
setcounter{hypothesis}{0} % so that the hypothesis is numbered 1
begin{hypothesis}
My first hypothesis states some stuff
begin{equation} #1 end{equation}
end{hypothesis}
setcounter{hypothesis}{value{hypcounter}} % rewrite that number back into counter
}
newcommand{secondhyp}[1]{
setcounter{hypcounter}{value{hypothesis}}
setcounter{hypothesis}{1} % so that the hypothesis is numbered 2
begin{hypothesis}
My second hypothesis states some other stuff
begin{equation} #1 end{equation}
end{hypothesis}
setcounter{hypothesis}{value{hypcounter}}
}
begin{document}
setcounter{hypothesis}{2} % so that a hypotheses afterwards will begin at 3
firsthyp{RE>RM land RF>RM lor RE<RM land RF<RM implies}
secondhyp{RE>RM land RF<RM lor RE<RM land RF>RM implies}
begin{hypothesis}
Another hypothesis will be numbered with the next number, $3$.
begin{equation}
text{Equation numbering continue as normal}
end{equation}
end{hypothesis}
firsthyp{x}
secondhyp{xtimes (-1)}
end{document}
I thinksetcounter{hypothesis}{n}
(n= previous value) before calling the hypothesis and asetcounter{hypothesis}{x}
(x= previous than the last hypothesis) after that would be enough for an accepted answer. Or at least if you want to automate it you could do it in anewenvironment
command with possibly an optional argument... Seems too complicated to me
– koleygr
Sep 19 '18 at 1:09
add a comment |
The following is pretty ugly, but gets the job done. Essentially, it makes a new command for hypothesis 1 and 2 that displays some set text and an equation that is numbered as normal. It plays around with the counter and manipulates it to be what is desired. I wasn't sure what your "justifications" were, so I replaced it with equations, but it can be adapted pretty easily based on what you have in mind.
documentclass{article}
usepackage{amsthm, amsmath}
newcounter{hypcounter}
newtheorem{hypothesis}{Hypothesis}
newcommand{firsthyp}[1]{
setcounter{hypcounter}{value{hypothesis}} % save what number we're at
setcounter{hypothesis}{0} % so that the hypothesis is numbered 1
begin{hypothesis}
My first hypothesis states some stuff
begin{equation} #1 end{equation}
end{hypothesis}
setcounter{hypothesis}{value{hypcounter}} % rewrite that number back into counter
}
newcommand{secondhyp}[1]{
setcounter{hypcounter}{value{hypothesis}}
setcounter{hypothesis}{1} % so that the hypothesis is numbered 2
begin{hypothesis}
My second hypothesis states some other stuff
begin{equation} #1 end{equation}
end{hypothesis}
setcounter{hypothesis}{value{hypcounter}}
}
begin{document}
setcounter{hypothesis}{2} % so that a hypotheses afterwards will begin at 3
firsthyp{RE>RM land RF>RM lor RE<RM land RF<RM implies}
secondhyp{RE>RM land RF<RM lor RE<RM land RF>RM implies}
begin{hypothesis}
Another hypothesis will be numbered with the next number, $3$.
begin{equation}
text{Equation numbering continue as normal}
end{equation}
end{hypothesis}
firsthyp{x}
secondhyp{xtimes (-1)}
end{document}
The following is pretty ugly, but gets the job done. Essentially, it makes a new command for hypothesis 1 and 2 that displays some set text and an equation that is numbered as normal. It plays around with the counter and manipulates it to be what is desired. I wasn't sure what your "justifications" were, so I replaced it with equations, but it can be adapted pretty easily based on what you have in mind.
documentclass{article}
usepackage{amsthm, amsmath}
newcounter{hypcounter}
newtheorem{hypothesis}{Hypothesis}
newcommand{firsthyp}[1]{
setcounter{hypcounter}{value{hypothesis}} % save what number we're at
setcounter{hypothesis}{0} % so that the hypothesis is numbered 1
begin{hypothesis}
My first hypothesis states some stuff
begin{equation} #1 end{equation}
end{hypothesis}
setcounter{hypothesis}{value{hypcounter}} % rewrite that number back into counter
}
newcommand{secondhyp}[1]{
setcounter{hypcounter}{value{hypothesis}}
setcounter{hypothesis}{1} % so that the hypothesis is numbered 2
begin{hypothesis}
My second hypothesis states some other stuff
begin{equation} #1 end{equation}
end{hypothesis}
setcounter{hypothesis}{value{hypcounter}}
}
begin{document}
setcounter{hypothesis}{2} % so that a hypotheses afterwards will begin at 3
firsthyp{RE>RM land RF>RM lor RE<RM land RF<RM implies}
secondhyp{RE>RM land RF<RM lor RE<RM land RF>RM implies}
begin{hypothesis}
Another hypothesis will be numbered with the next number, $3$.
begin{equation}
text{Equation numbering continue as normal}
end{equation}
end{hypothesis}
firsthyp{x}
secondhyp{xtimes (-1)}
end{document}
answered Jun 20 '18 at 22:34
CrimsonRainCrimsonRain
72727
72727
I thinksetcounter{hypothesis}{n}
(n= previous value) before calling the hypothesis and asetcounter{hypothesis}{x}
(x= previous than the last hypothesis) after that would be enough for an accepted answer. Or at least if you want to automate it you could do it in anewenvironment
command with possibly an optional argument... Seems too complicated to me
– koleygr
Sep 19 '18 at 1:09
add a comment |
I thinksetcounter{hypothesis}{n}
(n= previous value) before calling the hypothesis and asetcounter{hypothesis}{x}
(x= previous than the last hypothesis) after that would be enough for an accepted answer. Or at least if you want to automate it you could do it in anewenvironment
command with possibly an optional argument... Seems too complicated to me
– koleygr
Sep 19 '18 at 1:09
I think
setcounter{hypothesis}{n}
(n= previous value) before calling the hypothesis and a setcounter{hypothesis}{x}
(x= previous than the last hypothesis) after that would be enough for an accepted answer. Or at least if you want to automate it you could do it in a newenvironment
command with possibly an optional argument... Seems too complicated to me– koleygr
Sep 19 '18 at 1:09
I think
setcounter{hypothesis}{n}
(n= previous value) before calling the hypothesis and a setcounter{hypothesis}{x}
(x= previous than the last hypothesis) after that would be enough for an accepted answer. Or at least if you want to automate it you could do it in a newenvironment
command with possibly an optional argument... Seems too complicated to me– koleygr
Sep 19 '18 at 1:09
add a comment |
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