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Flattening the sub-lists

2

$begingroup$

Is there a way to flatten the sub-lists within a list?

Transform

{{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}

Into

{{1, x}, {2, x}, {3, x}, {4, x}, {5, x}, {6, x}, {7, x}, {8, x}, {9, x}, {10, x}}

I know I can do

Flatten /@ {{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}

I am wondering whether there are some dedicated functions for such sub-list flattening?

list-manipulation

share|improve this question

edited 5 hours ago

m0nhawk

2,92711532

asked 5 hours ago

bakerbaker

463

$endgroup$

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  $begingroup$
  try Flatten[list,1]
  $endgroup$
  – J42161217
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  One can also consider using Join @@ yourlist.
  $endgroup$
  – Αλέξανδρος Ζεγγ
  3 hours ago
  

  
  
  
  

add a comment | 

2

$begingroup$

Is there a way to flatten the sub-lists within a list?

Transform

{{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}

Into

{{1, x}, {2, x}, {3, x}, {4, x}, {5, x}, {6, x}, {7, x}, {8, x}, {9, x}, {10, x}}

I know I can do

Flatten /@ {{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}

I am wondering whether there are some dedicated functions for such sub-list flattening?

list-manipulation

share|improve this question

edited 5 hours ago

m0nhawk

2,92711532

asked 5 hours ago

bakerbaker

463

$endgroup$

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  $begingroup$
  try Flatten[list,1]
  $endgroup$
  – J42161217
  5 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  One can also consider using Join @@ yourlist.
  $endgroup$
  – Αλέξανδρος Ζεγγ
  3 hours ago
  

  
  
  
  

add a comment | 

$begingroup$

Is there a way to flatten the sub-lists within a list?

Transform

{{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}

Into

{{1, x}, {2, x}, {3, x}, {4, x}, {5, x}, {6, x}, {7, x}, {8, x}, {9, x}, {10, x}}

I know I can do

Flatten /@ {{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}

I am wondering whether there are some dedicated functions for such sub-list flattening?

list-manipulation

share|improve this question

edited 5 hours ago

m0nhawk

2,92711532

asked 5 hours ago

bakerbaker

463

$endgroup$

{{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}

{{1, x}, {2, x}, {3, x}, {4, x}, {5, x}, {6, x}, {7, x}, {8, x}, {9, x}, {10, x}}

Flatten /@ {{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}

share|improve this question

edited 5 hours ago

m0nhawk

2,92711532

asked 5 hours ago

bakerbaker

463

share|improve this question

edited 5 hours ago

m0nhawk

2,92711532

asked 5 hours ago

bakerbaker

463

edited 5 hours ago

m0nhawk

2,92711532

edited 5 hours ago

m0nhawk

2,92711532

asked 5 hours ago

bakerbaker

463

asked 5 hours ago

bakerbaker

463

2 Answers
2

active

oldest

votes

7

$begingroup$

You are doing redundant step with /@, Flatten can make this directly:

Flatten[{{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, 

    x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}, 1]

(* {{1, x}, {2, x}, {3, x}, {4, x}, {5, x}, {6, x}, {7, x}, {8, 

  x}, {9, x}, {10, x}} *)

share|improve this answer

answered 5 hours ago

m0nhawkm0nhawk

2,92711532

$endgroup$

add a comment | 

0

$begingroup$

Yes, there is a built-in function for what you want to do.

data = {{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}};

Catenate @ data

{{1, x}, {2, x}, {3, x}, {4, x}, {5, x}, {6, x}, {7, x}, {8, x}, {9, x}, {10, x}}

share

answered 3 mins ago

m_goldbergm_goldberg

89.1k873200

$endgroup$

add a comment | 

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7

$begingroup$

You are doing redundant step with /@, Flatten can make this directly:

Flatten[{{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, 

    x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}, 1]

(* {{1, x}, {2, x}, {3, x}, {4, x}, {5, x}, {6, x}, {7, x}, {8, 

  x}, {9, x}, {10, x}} *)

share|improve this answer

answered 5 hours ago

m0nhawkm0nhawk

2,92711532

$endgroup$

add a comment | 

7

$begingroup$

You are doing redundant step with /@, Flatten can make this directly:

Flatten[{{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, 

    x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}, 1]

(* {{1, x}, {2, x}, {3, x}, {4, x}, {5, x}, {6, x}, {7, x}, {8, 

  x}, {9, x}, {10, x}} *)

share|improve this answer

answered 5 hours ago

m0nhawkm0nhawk

2,92711532

$endgroup$

add a comment | 

$begingroup$

You are doing redundant step with /@, Flatten can make this directly:

Flatten[{{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, 

    x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}, 1]

(* {{1, x}, {2, x}, {3, x}, {4, x}, {5, x}, {6, x}, {7, x}, {8, 

  x}, {9, x}, {10, x}} *)

share|improve this answer

answered 5 hours ago

m0nhawkm0nhawk

2,92711532

$endgroup$

Flatten[{{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, 

    x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}, 1]

(* {{1, x}, {2, x}, {3, x}, {4, x}, {5, x}, {6, x}, {7, x}, {8, 

  x}, {9, x}, {10, x}} *)

share|improve this answer

answered 5 hours ago

m0nhawkm0nhawk

2,92711532

answered 5 hours ago

m0nhawkm0nhawk

2,92711532

answered 5 hours ago

m0nhawkm0nhawk

2,92711532

0

$begingroup$

Yes, there is a built-in function for what you want to do.

data = {{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}};

Catenate @ data

{{1, x}, {2, x}, {3, x}, {4, x}, {5, x}, {6, x}, {7, x}, {8, x}, {9, x}, {10, x}}

share

answered 3 mins ago

m_goldbergm_goldberg

89.1k873200

$endgroup$

add a comment | 

0

$begingroup$

Yes, there is a built-in function for what you want to do.

data = {{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}};

Catenate @ data

{{1, x}, {2, x}, {3, x}, {4, x}, {5, x}, {6, x}, {7, x}, {8, x}, {9, x}, {10, x}}

share

answered 3 mins ago

m_goldbergm_goldberg

89.1k873200

$endgroup$

add a comment | 

$begingroup$

Yes, there is a built-in function for what you want to do.

data = {{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}};

Catenate @ data

{{1, x}, {2, x}, {3, x}, {4, x}, {5, x}, {6, x}, {7, x}, {8, x}, {9, x}, {10, x}}

share

answered 3 mins ago

m_goldbergm_goldberg

89.1k873200

$endgroup$

data = {{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}};

Catenate @ data

share

answered 3 mins ago

m_goldbergm_goldberg

89.1k873200

answered 3 mins ago

m_goldbergm_goldberg

89.1k873200

answered 3 mins ago

m_goldbergm_goldberg

89.1k873200