Script that counts quarters, dimes, nickels, and penniesGroup By And Two CountsCross-platform performance and...
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Script that counts quarters, dimes, nickels, and pennies
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$begingroup$
I am learning Python and I wrote a script that counts how many coins you would need for an amount in dollars. I was wondering if I could make any improvements to it.
def change():
amnt = float(input("Enter an amount in USD: "))
quarters = divmod(amnt, 0.25)
print("Quarters: ", quarters[0])
amnt = round(quarters[1], 2)
dimes = divmod(amnt, 0.10)
print("Dimes: ", dimes[0])
amnt = round(dimes[1], 2)
nickels = divmod(amnt, 0.
print("Nickels: ", nickels[0])
amnt = round(nickels[1], 2)
penny = divmod(amnt, 0.01)
print("Pennies", penny[0])
change()
python beginner python-3.x change-making-problem
New contributor
$endgroup$
add a comment |
$begingroup$
I am learning Python and I wrote a script that counts how many coins you would need for an amount in dollars. I was wondering if I could make any improvements to it.
def change():
amnt = float(input("Enter an amount in USD: "))
quarters = divmod(amnt, 0.25)
print("Quarters: ", quarters[0])
amnt = round(quarters[1], 2)
dimes = divmod(amnt, 0.10)
print("Dimes: ", dimes[0])
amnt = round(dimes[1], 2)
nickels = divmod(amnt, 0.
print("Nickels: ", nickels[0])
amnt = round(nickels[1], 2)
penny = divmod(amnt, 0.01)
print("Pennies", penny[0])
change()
python beginner python-3.x change-making-problem
New contributor
$endgroup$
add a comment |
$begingroup$
I am learning Python and I wrote a script that counts how many coins you would need for an amount in dollars. I was wondering if I could make any improvements to it.
def change():
amnt = float(input("Enter an amount in USD: "))
quarters = divmod(amnt, 0.25)
print("Quarters: ", quarters[0])
amnt = round(quarters[1], 2)
dimes = divmod(amnt, 0.10)
print("Dimes: ", dimes[0])
amnt = round(dimes[1], 2)
nickels = divmod(amnt, 0.
print("Nickels: ", nickels[0])
amnt = round(nickels[1], 2)
penny = divmod(amnt, 0.01)
print("Pennies", penny[0])
change()
python beginner python-3.x change-making-problem
New contributor
$endgroup$
I am learning Python and I wrote a script that counts how many coins you would need for an amount in dollars. I was wondering if I could make any improvements to it.
def change():
amnt = float(input("Enter an amount in USD: "))
quarters = divmod(amnt, 0.25)
print("Quarters: ", quarters[0])
amnt = round(quarters[1], 2)
dimes = divmod(amnt, 0.10)
print("Dimes: ", dimes[0])
amnt = round(dimes[1], 2)
nickels = divmod(amnt, 0.
print("Nickels: ", nickels[0])
amnt = round(nickels[1], 2)
penny = divmod(amnt, 0.01)
print("Pennies", penny[0])
change()
python beginner python-3.x change-making-problem
python beginner python-3.x change-making-problem
New contributor
New contributor
edited 9 hours ago
200_success
130k16153419
130k16153419
New contributor
asked 12 hours ago
Hasan QaziHasan Qazi
282
282
New contributor
New contributor
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Separate input from processing. If you want to test your method with a number of different values, you'll have to call change()
multiple times, and enter in the value each time. Instead, change the function to accept the amnt
, and you can call it many times passing in the amount of cash as an argument:
def change(amnt):
# ...
Working with tuples from divmod
is awkward. Python has deconstructing assignment, which will take a returned tuple
an assign the members to separate variables:
def change(amnt):
quarters, amnt = divmod(amnt, 0.25)
print("Quarters: ", quarters)
dimes, amnt = divmod(round(amnt, 2), 0.10)
print("Dimes: ", dimes)
For the last operation, you don't use the remainder, so the "throw-away" variable _
can be used for it:
pennies, _ = divmod(round(amnt, 2), 0.01)
print("Pennies: ", pennies)
If you import this script into another program, you probably don't want the script to immediately run; rather you just want the change(amnt)
function to be defined so this other program can call it. This is done by adding a "guard" at the end of the script, which only runs the code if the script is invoked directly:
if __name__ == '__main__':
amnt = float(input("Enter an amount in USD: "))
change(amnt)
In addition to separating input from processing, you might want to separate the processing from the output:
def change(amnt):
quarters, amnt = divmod(amnt, 0.25)
dimes, amnt = divmod(amnt, 0.10)
nickels, amnt = divmod(amnt, 0.05)
pennies = round(amnt / 0.01, 0)
return list(map(int, [quarters, dimes, nickels, pennies]))
if __name__ == '__main__':
amnt = float(input("Enter an amount in USD: "))
quarters, dimes, nickels, pennies = change(amnt)
print("{} quarters, {} dimes, {} nickels, {} pennies".format(
quarters, dimes, nickels, pennies))
Despite attempts to fix rounding errors with things like round(amnt,2)
, calling change(0.85)
returns [3, 0, 1, 5]
, showing that there wasn't quite enough change to make 2 nickels, but after removing 1 nickel, approximately 5 pennies remained. This is caused by floating point math.
We can avoid these issues by switching to integer math, based on the number of pennies:
def change(amnt):
pennies = round(amnt * 100) # Convert from dollars to pennies
quarters, pennies = divmod(pennies, 25)
dimes, pennies = divmod(pennies, 10)
nickels, pennies = divmod(pennies, 5)
return quarters, dimes, nickels, pennies
if __name__ == '__main__':
amnt = float(input("Enter an amount in USD: "))
quarters, dimes, nickels, pennies = change(amnt)
print("{} quarters, {} dimes, {} nickels, {} pennies".format(
quarters, dimes, nickels, pennies))
$endgroup$
$begingroup$
+1 for everything except your non-PEP8 formatting, even though it does look nice here.
$endgroup$
– Graipher
10 hours ago
1
$begingroup$
It might be worth noting that the behavior of single-argumentround()
autoconverting floats to ints is specific to Python 3. In Python 2, you'd need to explicitly writepennies = int(round(amnt * 100))
if you want the results to be ints. (Of course, using an explicitint()
here is OK in Python 3 too, just redundant.)
$endgroup$
– Ilmari Karonen
7 hours ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
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oldest
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active
oldest
votes
$begingroup$
Separate input from processing. If you want to test your method with a number of different values, you'll have to call change()
multiple times, and enter in the value each time. Instead, change the function to accept the amnt
, and you can call it many times passing in the amount of cash as an argument:
def change(amnt):
# ...
Working with tuples from divmod
is awkward. Python has deconstructing assignment, which will take a returned tuple
an assign the members to separate variables:
def change(amnt):
quarters, amnt = divmod(amnt, 0.25)
print("Quarters: ", quarters)
dimes, amnt = divmod(round(amnt, 2), 0.10)
print("Dimes: ", dimes)
For the last operation, you don't use the remainder, so the "throw-away" variable _
can be used for it:
pennies, _ = divmod(round(amnt, 2), 0.01)
print("Pennies: ", pennies)
If you import this script into another program, you probably don't want the script to immediately run; rather you just want the change(amnt)
function to be defined so this other program can call it. This is done by adding a "guard" at the end of the script, which only runs the code if the script is invoked directly:
if __name__ == '__main__':
amnt = float(input("Enter an amount in USD: "))
change(amnt)
In addition to separating input from processing, you might want to separate the processing from the output:
def change(amnt):
quarters, amnt = divmod(amnt, 0.25)
dimes, amnt = divmod(amnt, 0.10)
nickels, amnt = divmod(amnt, 0.05)
pennies = round(amnt / 0.01, 0)
return list(map(int, [quarters, dimes, nickels, pennies]))
if __name__ == '__main__':
amnt = float(input("Enter an amount in USD: "))
quarters, dimes, nickels, pennies = change(amnt)
print("{} quarters, {} dimes, {} nickels, {} pennies".format(
quarters, dimes, nickels, pennies))
Despite attempts to fix rounding errors with things like round(amnt,2)
, calling change(0.85)
returns [3, 0, 1, 5]
, showing that there wasn't quite enough change to make 2 nickels, but after removing 1 nickel, approximately 5 pennies remained. This is caused by floating point math.
We can avoid these issues by switching to integer math, based on the number of pennies:
def change(amnt):
pennies = round(amnt * 100) # Convert from dollars to pennies
quarters, pennies = divmod(pennies, 25)
dimes, pennies = divmod(pennies, 10)
nickels, pennies = divmod(pennies, 5)
return quarters, dimes, nickels, pennies
if __name__ == '__main__':
amnt = float(input("Enter an amount in USD: "))
quarters, dimes, nickels, pennies = change(amnt)
print("{} quarters, {} dimes, {} nickels, {} pennies".format(
quarters, dimes, nickels, pennies))
$endgroup$
$begingroup$
+1 for everything except your non-PEP8 formatting, even though it does look nice here.
$endgroup$
– Graipher
10 hours ago
1
$begingroup$
It might be worth noting that the behavior of single-argumentround()
autoconverting floats to ints is specific to Python 3. In Python 2, you'd need to explicitly writepennies = int(round(amnt * 100))
if you want the results to be ints. (Of course, using an explicitint()
here is OK in Python 3 too, just redundant.)
$endgroup$
– Ilmari Karonen
7 hours ago
add a comment |
$begingroup$
Separate input from processing. If you want to test your method with a number of different values, you'll have to call change()
multiple times, and enter in the value each time. Instead, change the function to accept the amnt
, and you can call it many times passing in the amount of cash as an argument:
def change(amnt):
# ...
Working with tuples from divmod
is awkward. Python has deconstructing assignment, which will take a returned tuple
an assign the members to separate variables:
def change(amnt):
quarters, amnt = divmod(amnt, 0.25)
print("Quarters: ", quarters)
dimes, amnt = divmod(round(amnt, 2), 0.10)
print("Dimes: ", dimes)
For the last operation, you don't use the remainder, so the "throw-away" variable _
can be used for it:
pennies, _ = divmod(round(amnt, 2), 0.01)
print("Pennies: ", pennies)
If you import this script into another program, you probably don't want the script to immediately run; rather you just want the change(amnt)
function to be defined so this other program can call it. This is done by adding a "guard" at the end of the script, which only runs the code if the script is invoked directly:
if __name__ == '__main__':
amnt = float(input("Enter an amount in USD: "))
change(amnt)
In addition to separating input from processing, you might want to separate the processing from the output:
def change(amnt):
quarters, amnt = divmod(amnt, 0.25)
dimes, amnt = divmod(amnt, 0.10)
nickels, amnt = divmod(amnt, 0.05)
pennies = round(amnt / 0.01, 0)
return list(map(int, [quarters, dimes, nickels, pennies]))
if __name__ == '__main__':
amnt = float(input("Enter an amount in USD: "))
quarters, dimes, nickels, pennies = change(amnt)
print("{} quarters, {} dimes, {} nickels, {} pennies".format(
quarters, dimes, nickels, pennies))
Despite attempts to fix rounding errors with things like round(amnt,2)
, calling change(0.85)
returns [3, 0, 1, 5]
, showing that there wasn't quite enough change to make 2 nickels, but after removing 1 nickel, approximately 5 pennies remained. This is caused by floating point math.
We can avoid these issues by switching to integer math, based on the number of pennies:
def change(amnt):
pennies = round(amnt * 100) # Convert from dollars to pennies
quarters, pennies = divmod(pennies, 25)
dimes, pennies = divmod(pennies, 10)
nickels, pennies = divmod(pennies, 5)
return quarters, dimes, nickels, pennies
if __name__ == '__main__':
amnt = float(input("Enter an amount in USD: "))
quarters, dimes, nickels, pennies = change(amnt)
print("{} quarters, {} dimes, {} nickels, {} pennies".format(
quarters, dimes, nickels, pennies))
$endgroup$
$begingroup$
+1 for everything except your non-PEP8 formatting, even though it does look nice here.
$endgroup$
– Graipher
10 hours ago
1
$begingroup$
It might be worth noting that the behavior of single-argumentround()
autoconverting floats to ints is specific to Python 3. In Python 2, you'd need to explicitly writepennies = int(round(amnt * 100))
if you want the results to be ints. (Of course, using an explicitint()
here is OK in Python 3 too, just redundant.)
$endgroup$
– Ilmari Karonen
7 hours ago
add a comment |
$begingroup$
Separate input from processing. If you want to test your method with a number of different values, you'll have to call change()
multiple times, and enter in the value each time. Instead, change the function to accept the amnt
, and you can call it many times passing in the amount of cash as an argument:
def change(amnt):
# ...
Working with tuples from divmod
is awkward. Python has deconstructing assignment, which will take a returned tuple
an assign the members to separate variables:
def change(amnt):
quarters, amnt = divmod(amnt, 0.25)
print("Quarters: ", quarters)
dimes, amnt = divmod(round(amnt, 2), 0.10)
print("Dimes: ", dimes)
For the last operation, you don't use the remainder, so the "throw-away" variable _
can be used for it:
pennies, _ = divmod(round(amnt, 2), 0.01)
print("Pennies: ", pennies)
If you import this script into another program, you probably don't want the script to immediately run; rather you just want the change(amnt)
function to be defined so this other program can call it. This is done by adding a "guard" at the end of the script, which only runs the code if the script is invoked directly:
if __name__ == '__main__':
amnt = float(input("Enter an amount in USD: "))
change(amnt)
In addition to separating input from processing, you might want to separate the processing from the output:
def change(amnt):
quarters, amnt = divmod(amnt, 0.25)
dimes, amnt = divmod(amnt, 0.10)
nickels, amnt = divmod(amnt, 0.05)
pennies = round(amnt / 0.01, 0)
return list(map(int, [quarters, dimes, nickels, pennies]))
if __name__ == '__main__':
amnt = float(input("Enter an amount in USD: "))
quarters, dimes, nickels, pennies = change(amnt)
print("{} quarters, {} dimes, {} nickels, {} pennies".format(
quarters, dimes, nickels, pennies))
Despite attempts to fix rounding errors with things like round(amnt,2)
, calling change(0.85)
returns [3, 0, 1, 5]
, showing that there wasn't quite enough change to make 2 nickels, but after removing 1 nickel, approximately 5 pennies remained. This is caused by floating point math.
We can avoid these issues by switching to integer math, based on the number of pennies:
def change(amnt):
pennies = round(amnt * 100) # Convert from dollars to pennies
quarters, pennies = divmod(pennies, 25)
dimes, pennies = divmod(pennies, 10)
nickels, pennies = divmod(pennies, 5)
return quarters, dimes, nickels, pennies
if __name__ == '__main__':
amnt = float(input("Enter an amount in USD: "))
quarters, dimes, nickels, pennies = change(amnt)
print("{} quarters, {} dimes, {} nickels, {} pennies".format(
quarters, dimes, nickels, pennies))
$endgroup$
Separate input from processing. If you want to test your method with a number of different values, you'll have to call change()
multiple times, and enter in the value each time. Instead, change the function to accept the amnt
, and you can call it many times passing in the amount of cash as an argument:
def change(amnt):
# ...
Working with tuples from divmod
is awkward. Python has deconstructing assignment, which will take a returned tuple
an assign the members to separate variables:
def change(amnt):
quarters, amnt = divmod(amnt, 0.25)
print("Quarters: ", quarters)
dimes, amnt = divmod(round(amnt, 2), 0.10)
print("Dimes: ", dimes)
For the last operation, you don't use the remainder, so the "throw-away" variable _
can be used for it:
pennies, _ = divmod(round(amnt, 2), 0.01)
print("Pennies: ", pennies)
If you import this script into another program, you probably don't want the script to immediately run; rather you just want the change(amnt)
function to be defined so this other program can call it. This is done by adding a "guard" at the end of the script, which only runs the code if the script is invoked directly:
if __name__ == '__main__':
amnt = float(input("Enter an amount in USD: "))
change(amnt)
In addition to separating input from processing, you might want to separate the processing from the output:
def change(amnt):
quarters, amnt = divmod(amnt, 0.25)
dimes, amnt = divmod(amnt, 0.10)
nickels, amnt = divmod(amnt, 0.05)
pennies = round(amnt / 0.01, 0)
return list(map(int, [quarters, dimes, nickels, pennies]))
if __name__ == '__main__':
amnt = float(input("Enter an amount in USD: "))
quarters, dimes, nickels, pennies = change(amnt)
print("{} quarters, {} dimes, {} nickels, {} pennies".format(
quarters, dimes, nickels, pennies))
Despite attempts to fix rounding errors with things like round(amnt,2)
, calling change(0.85)
returns [3, 0, 1, 5]
, showing that there wasn't quite enough change to make 2 nickels, but after removing 1 nickel, approximately 5 pennies remained. This is caused by floating point math.
We can avoid these issues by switching to integer math, based on the number of pennies:
def change(amnt):
pennies = round(amnt * 100) # Convert from dollars to pennies
quarters, pennies = divmod(pennies, 25)
dimes, pennies = divmod(pennies, 10)
nickels, pennies = divmod(pennies, 5)
return quarters, dimes, nickels, pennies
if __name__ == '__main__':
amnt = float(input("Enter an amount in USD: "))
quarters, dimes, nickels, pennies = change(amnt)
print("{} quarters, {} dimes, {} nickels, {} pennies".format(
quarters, dimes, nickels, pennies))
edited 11 hours ago
answered 12 hours ago
AJNeufeldAJNeufeld
5,8541420
5,8541420
$begingroup$
+1 for everything except your non-PEP8 formatting, even though it does look nice here.
$endgroup$
– Graipher
10 hours ago
1
$begingroup$
It might be worth noting that the behavior of single-argumentround()
autoconverting floats to ints is specific to Python 3. In Python 2, you'd need to explicitly writepennies = int(round(amnt * 100))
if you want the results to be ints. (Of course, using an explicitint()
here is OK in Python 3 too, just redundant.)
$endgroup$
– Ilmari Karonen
7 hours ago
add a comment |
$begingroup$
+1 for everything except your non-PEP8 formatting, even though it does look nice here.
$endgroup$
– Graipher
10 hours ago
1
$begingroup$
It might be worth noting that the behavior of single-argumentround()
autoconverting floats to ints is specific to Python 3. In Python 2, you'd need to explicitly writepennies = int(round(amnt * 100))
if you want the results to be ints. (Of course, using an explicitint()
here is OK in Python 3 too, just redundant.)
$endgroup$
– Ilmari Karonen
7 hours ago
$begingroup$
+1 for everything except your non-PEP8 formatting, even though it does look nice here.
$endgroup$
– Graipher
10 hours ago
$begingroup$
+1 for everything except your non-PEP8 formatting, even though it does look nice here.
$endgroup$
– Graipher
10 hours ago
1
1
$begingroup$
It might be worth noting that the behavior of single-argument
round()
autoconverting floats to ints is specific to Python 3. In Python 2, you'd need to explicitly write pennies = int(round(amnt * 100))
if you want the results to be ints. (Of course, using an explicit int()
here is OK in Python 3 too, just redundant.)$endgroup$
– Ilmari Karonen
7 hours ago
$begingroup$
It might be worth noting that the behavior of single-argument
round()
autoconverting floats to ints is specific to Python 3. In Python 2, you'd need to explicitly write pennies = int(round(amnt * 100))
if you want the results to be ints. (Of course, using an explicit int()
here is OK in Python 3 too, just redundant.)$endgroup$
– Ilmari Karonen
7 hours ago
add a comment |
Hasan Qazi is a new contributor. Be nice, and check out our Code of Conduct.
Hasan Qazi is a new contributor. Be nice, and check out our Code of Conduct.
Hasan Qazi is a new contributor. Be nice, and check out our Code of Conduct.
Hasan Qazi is a new contributor. Be nice, and check out our Code of Conduct.
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