Script that counts quarters, dimes, nickels, and penniesGroup By And Two CountsCross-platform performance and...

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Script that counts quarters, dimes, nickels, and pennies


Group By And Two CountsCross-platform performance and statistical information scriptGrouping logs and providing countsCounting single degree vertex removal rounds (from a graph)Let's protect that CLI Python scriptIterative “counting change” implementation in mit-schemeCalculating frequencies of each obs in the dataInfinite monkey theorem demonstration in PythonReturn the amount of Quarters, Dimes, Nickels, and Pennies that you would get from the total amount of changeSimple game of hangman which counts wins and losses













5












$begingroup$


I am learning Python and I wrote a script that counts how many coins you would need for an amount in dollars. I was wondering if I could make any improvements to it.



def change():
amnt = float(input("Enter an amount in USD: "))
quarters = divmod(amnt, 0.25)
print("Quarters: ", quarters[0])
amnt = round(quarters[1], 2)
dimes = divmod(amnt, 0.10)
print("Dimes: ", dimes[0])
amnt = round(dimes[1], 2)
nickels = divmod(amnt, 0.
print("Nickels: ", nickels[0])
amnt = round(nickels[1], 2)
penny = divmod(amnt, 0.01)
print("Pennies", penny[0])
change()









share|improve this question









New contributor




Hasan Qazi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$

















    5












    $begingroup$


    I am learning Python and I wrote a script that counts how many coins you would need for an amount in dollars. I was wondering if I could make any improvements to it.



    def change():
    amnt = float(input("Enter an amount in USD: "))
    quarters = divmod(amnt, 0.25)
    print("Quarters: ", quarters[0])
    amnt = round(quarters[1], 2)
    dimes = divmod(amnt, 0.10)
    print("Dimes: ", dimes[0])
    amnt = round(dimes[1], 2)
    nickels = divmod(amnt, 0.
    print("Nickels: ", nickels[0])
    amnt = round(nickels[1], 2)
    penny = divmod(amnt, 0.01)
    print("Pennies", penny[0])
    change()









    share|improve this question









    New contributor




    Hasan Qazi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$















      5












      5








      5


      1



      $begingroup$


      I am learning Python and I wrote a script that counts how many coins you would need for an amount in dollars. I was wondering if I could make any improvements to it.



      def change():
      amnt = float(input("Enter an amount in USD: "))
      quarters = divmod(amnt, 0.25)
      print("Quarters: ", quarters[0])
      amnt = round(quarters[1], 2)
      dimes = divmod(amnt, 0.10)
      print("Dimes: ", dimes[0])
      amnt = round(dimes[1], 2)
      nickels = divmod(amnt, 0.
      print("Nickels: ", nickels[0])
      amnt = round(nickels[1], 2)
      penny = divmod(amnt, 0.01)
      print("Pennies", penny[0])
      change()









      share|improve this question









      New contributor




      Hasan Qazi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      I am learning Python and I wrote a script that counts how many coins you would need for an amount in dollars. I was wondering if I could make any improvements to it.



      def change():
      amnt = float(input("Enter an amount in USD: "))
      quarters = divmod(amnt, 0.25)
      print("Quarters: ", quarters[0])
      amnt = round(quarters[1], 2)
      dimes = divmod(amnt, 0.10)
      print("Dimes: ", dimes[0])
      amnt = round(dimes[1], 2)
      nickels = divmod(amnt, 0.
      print("Nickels: ", nickels[0])
      amnt = round(nickels[1], 2)
      penny = divmod(amnt, 0.01)
      print("Pennies", penny[0])
      change()






      python beginner python-3.x change-making-problem






      share|improve this question









      New contributor




      Hasan Qazi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      Hasan Qazi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question








      edited 9 hours ago









      200_success

      130k16153419




      130k16153419






      New contributor




      Hasan Qazi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 12 hours ago









      Hasan QaziHasan Qazi

      282




      282




      New contributor




      Hasan Qazi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      Hasan Qazi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      Hasan Qazi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






















          1 Answer
          1






          active

          oldest

          votes


















          9












          $begingroup$

          Separate input from processing. If you want to test your method with a number of different values, you'll have to call change() multiple times, and enter in the value each time. Instead, change the function to accept the amnt, and you can call it many times passing in the amount of cash as an argument:



          def change(amnt):
          # ...


          Working with tuples from divmod is awkward. Python has deconstructing assignment, which will take a returned tuple an assign the members to separate variables:



          def change(amnt):
          quarters, amnt = divmod(amnt, 0.25)
          print("Quarters: ", quarters)

          dimes, amnt = divmod(round(amnt, 2), 0.10)
          print("Dimes: ", dimes)


          For the last operation, you don't use the remainder, so the "throw-away" variable _ can be used for it:



              pennies, _ = divmod(round(amnt, 2), 0.01)
          print("Pennies: ", pennies)


          If you import this script into another program, you probably don't want the script to immediately run; rather you just want the change(amnt) function to be defined so this other program can call it. This is done by adding a "guard" at the end of the script, which only runs the code if the script is invoked directly:



          if __name__ == '__main__':
          amnt = float(input("Enter an amount in USD: "))
          change(amnt)




          In addition to separating input from processing, you might want to separate the processing from the output:



          def change(amnt):
          quarters, amnt = divmod(amnt, 0.25)
          dimes, amnt = divmod(amnt, 0.10)
          nickels, amnt = divmod(amnt, 0.05)
          pennies = round(amnt / 0.01, 0)

          return list(map(int, [quarters, dimes, nickels, pennies]))

          if __name__ == '__main__':
          amnt = float(input("Enter an amount in USD: "))
          quarters, dimes, nickels, pennies = change(amnt)
          print("{} quarters, {} dimes, {} nickels, {} pennies".format(
          quarters, dimes, nickels, pennies))




          Despite attempts to fix rounding errors with things like round(amnt,2), calling change(0.85) returns [3, 0, 1, 5], showing that there wasn't quite enough change to make 2 nickels, but after removing 1 nickel, approximately 5 pennies remained. This is caused by floating point math.



          We can avoid these issues by switching to integer math, based on the number of pennies:



          def change(amnt):
          pennies = round(amnt * 100) # Convert from dollars to pennies

          quarters, pennies = divmod(pennies, 25)
          dimes, pennies = divmod(pennies, 10)
          nickels, pennies = divmod(pennies, 5)

          return quarters, dimes, nickels, pennies

          if __name__ == '__main__':
          amnt = float(input("Enter an amount in USD: "))
          quarters, dimes, nickels, pennies = change(amnt)
          print("{} quarters, {} dimes, {} nickels, {} pennies".format(
          quarters, dimes, nickels, pennies))





          share|improve this answer











          $endgroup$













          • $begingroup$
            +1 for everything except your non-PEP8 formatting, even though it does look nice here.
            $endgroup$
            – Graipher
            10 hours ago






          • 1




            $begingroup$
            It might be worth noting that the behavior of single-argument round() autoconverting floats to ints is specific to Python 3. In Python 2, you'd need to explicitly write pennies = int(round(amnt * 100)) if you want the results to be ints. (Of course, using an explicit int() here is OK in Python 3 too, just redundant.)
            $endgroup$
            – Ilmari Karonen
            7 hours ago













          Your Answer





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          1 Answer
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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          9












          $begingroup$

          Separate input from processing. If you want to test your method with a number of different values, you'll have to call change() multiple times, and enter in the value each time. Instead, change the function to accept the amnt, and you can call it many times passing in the amount of cash as an argument:



          def change(amnt):
          # ...


          Working with tuples from divmod is awkward. Python has deconstructing assignment, which will take a returned tuple an assign the members to separate variables:



          def change(amnt):
          quarters, amnt = divmod(amnt, 0.25)
          print("Quarters: ", quarters)

          dimes, amnt = divmod(round(amnt, 2), 0.10)
          print("Dimes: ", dimes)


          For the last operation, you don't use the remainder, so the "throw-away" variable _ can be used for it:



              pennies, _ = divmod(round(amnt, 2), 0.01)
          print("Pennies: ", pennies)


          If you import this script into another program, you probably don't want the script to immediately run; rather you just want the change(amnt) function to be defined so this other program can call it. This is done by adding a "guard" at the end of the script, which only runs the code if the script is invoked directly:



          if __name__ == '__main__':
          amnt = float(input("Enter an amount in USD: "))
          change(amnt)




          In addition to separating input from processing, you might want to separate the processing from the output:



          def change(amnt):
          quarters, amnt = divmod(amnt, 0.25)
          dimes, amnt = divmod(amnt, 0.10)
          nickels, amnt = divmod(amnt, 0.05)
          pennies = round(amnt / 0.01, 0)

          return list(map(int, [quarters, dimes, nickels, pennies]))

          if __name__ == '__main__':
          amnt = float(input("Enter an amount in USD: "))
          quarters, dimes, nickels, pennies = change(amnt)
          print("{} quarters, {} dimes, {} nickels, {} pennies".format(
          quarters, dimes, nickels, pennies))




          Despite attempts to fix rounding errors with things like round(amnt,2), calling change(0.85) returns [3, 0, 1, 5], showing that there wasn't quite enough change to make 2 nickels, but after removing 1 nickel, approximately 5 pennies remained. This is caused by floating point math.



          We can avoid these issues by switching to integer math, based on the number of pennies:



          def change(amnt):
          pennies = round(amnt * 100) # Convert from dollars to pennies

          quarters, pennies = divmod(pennies, 25)
          dimes, pennies = divmod(pennies, 10)
          nickels, pennies = divmod(pennies, 5)

          return quarters, dimes, nickels, pennies

          if __name__ == '__main__':
          amnt = float(input("Enter an amount in USD: "))
          quarters, dimes, nickels, pennies = change(amnt)
          print("{} quarters, {} dimes, {} nickels, {} pennies".format(
          quarters, dimes, nickels, pennies))





          share|improve this answer











          $endgroup$













          • $begingroup$
            +1 for everything except your non-PEP8 formatting, even though it does look nice here.
            $endgroup$
            – Graipher
            10 hours ago






          • 1




            $begingroup$
            It might be worth noting that the behavior of single-argument round() autoconverting floats to ints is specific to Python 3. In Python 2, you'd need to explicitly write pennies = int(round(amnt * 100)) if you want the results to be ints. (Of course, using an explicit int() here is OK in Python 3 too, just redundant.)
            $endgroup$
            – Ilmari Karonen
            7 hours ago


















          9












          $begingroup$

          Separate input from processing. If you want to test your method with a number of different values, you'll have to call change() multiple times, and enter in the value each time. Instead, change the function to accept the amnt, and you can call it many times passing in the amount of cash as an argument:



          def change(amnt):
          # ...


          Working with tuples from divmod is awkward. Python has deconstructing assignment, which will take a returned tuple an assign the members to separate variables:



          def change(amnt):
          quarters, amnt = divmod(amnt, 0.25)
          print("Quarters: ", quarters)

          dimes, amnt = divmod(round(amnt, 2), 0.10)
          print("Dimes: ", dimes)


          For the last operation, you don't use the remainder, so the "throw-away" variable _ can be used for it:



              pennies, _ = divmod(round(amnt, 2), 0.01)
          print("Pennies: ", pennies)


          If you import this script into another program, you probably don't want the script to immediately run; rather you just want the change(amnt) function to be defined so this other program can call it. This is done by adding a "guard" at the end of the script, which only runs the code if the script is invoked directly:



          if __name__ == '__main__':
          amnt = float(input("Enter an amount in USD: "))
          change(amnt)




          In addition to separating input from processing, you might want to separate the processing from the output:



          def change(amnt):
          quarters, amnt = divmod(amnt, 0.25)
          dimes, amnt = divmod(amnt, 0.10)
          nickels, amnt = divmod(amnt, 0.05)
          pennies = round(amnt / 0.01, 0)

          return list(map(int, [quarters, dimes, nickels, pennies]))

          if __name__ == '__main__':
          amnt = float(input("Enter an amount in USD: "))
          quarters, dimes, nickels, pennies = change(amnt)
          print("{} quarters, {} dimes, {} nickels, {} pennies".format(
          quarters, dimes, nickels, pennies))




          Despite attempts to fix rounding errors with things like round(amnt,2), calling change(0.85) returns [3, 0, 1, 5], showing that there wasn't quite enough change to make 2 nickels, but after removing 1 nickel, approximately 5 pennies remained. This is caused by floating point math.



          We can avoid these issues by switching to integer math, based on the number of pennies:



          def change(amnt):
          pennies = round(amnt * 100) # Convert from dollars to pennies

          quarters, pennies = divmod(pennies, 25)
          dimes, pennies = divmod(pennies, 10)
          nickels, pennies = divmod(pennies, 5)

          return quarters, dimes, nickels, pennies

          if __name__ == '__main__':
          amnt = float(input("Enter an amount in USD: "))
          quarters, dimes, nickels, pennies = change(amnt)
          print("{} quarters, {} dimes, {} nickels, {} pennies".format(
          quarters, dimes, nickels, pennies))





          share|improve this answer











          $endgroup$













          • $begingroup$
            +1 for everything except your non-PEP8 formatting, even though it does look nice here.
            $endgroup$
            – Graipher
            10 hours ago






          • 1




            $begingroup$
            It might be worth noting that the behavior of single-argument round() autoconverting floats to ints is specific to Python 3. In Python 2, you'd need to explicitly write pennies = int(round(amnt * 100)) if you want the results to be ints. (Of course, using an explicit int() here is OK in Python 3 too, just redundant.)
            $endgroup$
            – Ilmari Karonen
            7 hours ago
















          9












          9








          9





          $begingroup$

          Separate input from processing. If you want to test your method with a number of different values, you'll have to call change() multiple times, and enter in the value each time. Instead, change the function to accept the amnt, and you can call it many times passing in the amount of cash as an argument:



          def change(amnt):
          # ...


          Working with tuples from divmod is awkward. Python has deconstructing assignment, which will take a returned tuple an assign the members to separate variables:



          def change(amnt):
          quarters, amnt = divmod(amnt, 0.25)
          print("Quarters: ", quarters)

          dimes, amnt = divmod(round(amnt, 2), 0.10)
          print("Dimes: ", dimes)


          For the last operation, you don't use the remainder, so the "throw-away" variable _ can be used for it:



              pennies, _ = divmod(round(amnt, 2), 0.01)
          print("Pennies: ", pennies)


          If you import this script into another program, you probably don't want the script to immediately run; rather you just want the change(amnt) function to be defined so this other program can call it. This is done by adding a "guard" at the end of the script, which only runs the code if the script is invoked directly:



          if __name__ == '__main__':
          amnt = float(input("Enter an amount in USD: "))
          change(amnt)




          In addition to separating input from processing, you might want to separate the processing from the output:



          def change(amnt):
          quarters, amnt = divmod(amnt, 0.25)
          dimes, amnt = divmod(amnt, 0.10)
          nickels, amnt = divmod(amnt, 0.05)
          pennies = round(amnt / 0.01, 0)

          return list(map(int, [quarters, dimes, nickels, pennies]))

          if __name__ == '__main__':
          amnt = float(input("Enter an amount in USD: "))
          quarters, dimes, nickels, pennies = change(amnt)
          print("{} quarters, {} dimes, {} nickels, {} pennies".format(
          quarters, dimes, nickels, pennies))




          Despite attempts to fix rounding errors with things like round(amnt,2), calling change(0.85) returns [3, 0, 1, 5], showing that there wasn't quite enough change to make 2 nickels, but after removing 1 nickel, approximately 5 pennies remained. This is caused by floating point math.



          We can avoid these issues by switching to integer math, based on the number of pennies:



          def change(amnt):
          pennies = round(amnt * 100) # Convert from dollars to pennies

          quarters, pennies = divmod(pennies, 25)
          dimes, pennies = divmod(pennies, 10)
          nickels, pennies = divmod(pennies, 5)

          return quarters, dimes, nickels, pennies

          if __name__ == '__main__':
          amnt = float(input("Enter an amount in USD: "))
          quarters, dimes, nickels, pennies = change(amnt)
          print("{} quarters, {} dimes, {} nickels, {} pennies".format(
          quarters, dimes, nickels, pennies))





          share|improve this answer











          $endgroup$



          Separate input from processing. If you want to test your method with a number of different values, you'll have to call change() multiple times, and enter in the value each time. Instead, change the function to accept the amnt, and you can call it many times passing in the amount of cash as an argument:



          def change(amnt):
          # ...


          Working with tuples from divmod is awkward. Python has deconstructing assignment, which will take a returned tuple an assign the members to separate variables:



          def change(amnt):
          quarters, amnt = divmod(amnt, 0.25)
          print("Quarters: ", quarters)

          dimes, amnt = divmod(round(amnt, 2), 0.10)
          print("Dimes: ", dimes)


          For the last operation, you don't use the remainder, so the "throw-away" variable _ can be used for it:



              pennies, _ = divmod(round(amnt, 2), 0.01)
          print("Pennies: ", pennies)


          If you import this script into another program, you probably don't want the script to immediately run; rather you just want the change(amnt) function to be defined so this other program can call it. This is done by adding a "guard" at the end of the script, which only runs the code if the script is invoked directly:



          if __name__ == '__main__':
          amnt = float(input("Enter an amount in USD: "))
          change(amnt)




          In addition to separating input from processing, you might want to separate the processing from the output:



          def change(amnt):
          quarters, amnt = divmod(amnt, 0.25)
          dimes, amnt = divmod(amnt, 0.10)
          nickels, amnt = divmod(amnt, 0.05)
          pennies = round(amnt / 0.01, 0)

          return list(map(int, [quarters, dimes, nickels, pennies]))

          if __name__ == '__main__':
          amnt = float(input("Enter an amount in USD: "))
          quarters, dimes, nickels, pennies = change(amnt)
          print("{} quarters, {} dimes, {} nickels, {} pennies".format(
          quarters, dimes, nickels, pennies))




          Despite attempts to fix rounding errors with things like round(amnt,2), calling change(0.85) returns [3, 0, 1, 5], showing that there wasn't quite enough change to make 2 nickels, but after removing 1 nickel, approximately 5 pennies remained. This is caused by floating point math.



          We can avoid these issues by switching to integer math, based on the number of pennies:



          def change(amnt):
          pennies = round(amnt * 100) # Convert from dollars to pennies

          quarters, pennies = divmod(pennies, 25)
          dimes, pennies = divmod(pennies, 10)
          nickels, pennies = divmod(pennies, 5)

          return quarters, dimes, nickels, pennies

          if __name__ == '__main__':
          amnt = float(input("Enter an amount in USD: "))
          quarters, dimes, nickels, pennies = change(amnt)
          print("{} quarters, {} dimes, {} nickels, {} pennies".format(
          quarters, dimes, nickels, pennies))






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 11 hours ago

























          answered 12 hours ago









          AJNeufeldAJNeufeld

          5,8541420




          5,8541420












          • $begingroup$
            +1 for everything except your non-PEP8 formatting, even though it does look nice here.
            $endgroup$
            – Graipher
            10 hours ago






          • 1




            $begingroup$
            It might be worth noting that the behavior of single-argument round() autoconverting floats to ints is specific to Python 3. In Python 2, you'd need to explicitly write pennies = int(round(amnt * 100)) if you want the results to be ints. (Of course, using an explicit int() here is OK in Python 3 too, just redundant.)
            $endgroup$
            – Ilmari Karonen
            7 hours ago




















          • $begingroup$
            +1 for everything except your non-PEP8 formatting, even though it does look nice here.
            $endgroup$
            – Graipher
            10 hours ago






          • 1




            $begingroup$
            It might be worth noting that the behavior of single-argument round() autoconverting floats to ints is specific to Python 3. In Python 2, you'd need to explicitly write pennies = int(round(amnt * 100)) if you want the results to be ints. (Of course, using an explicit int() here is OK in Python 3 too, just redundant.)
            $endgroup$
            – Ilmari Karonen
            7 hours ago


















          $begingroup$
          +1 for everything except your non-PEP8 formatting, even though it does look nice here.
          $endgroup$
          – Graipher
          10 hours ago




          $begingroup$
          +1 for everything except your non-PEP8 formatting, even though it does look nice here.
          $endgroup$
          – Graipher
          10 hours ago




          1




          1




          $begingroup$
          It might be worth noting that the behavior of single-argument round() autoconverting floats to ints is specific to Python 3. In Python 2, you'd need to explicitly write pennies = int(round(amnt * 100)) if you want the results to be ints. (Of course, using an explicit int() here is OK in Python 3 too, just redundant.)
          $endgroup$
          – Ilmari Karonen
          7 hours ago






          $begingroup$
          It might be worth noting that the behavior of single-argument round() autoconverting floats to ints is specific to Python 3. In Python 2, you'd need to explicitly write pennies = int(round(amnt * 100)) if you want the results to be ints. (Of course, using an explicit int() here is OK in Python 3 too, just redundant.)
          $endgroup$
          – Ilmari Karonen
          7 hours ago












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