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Self-referential multiple-choice question [duplicate]

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2

1

$begingroup$

This question already has an answer here:

• 
  Multiple-choice question about the probability of a random answer to itself being correct
  
  6 answers
  
  

I came across this question, which I believe cannot be satisfactorily answered, but I'm not completely sure. Can you tell me if it has a answer?

If you choose the answer to this question at random,

what is the chance that you will be correct?

a) 25%

b) 50%

c) 60%

d) 25%

logic paradoxes

share|cite|improve this question

edited 8 hours ago

Bernard

124k741116

asked 11 hours ago

Ricardo MagallanesRicardo Magallanes

264

$endgroup$

marked as duplicate by Martin R, Community♦ 6 hours ago

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  Possible duplicate of Multiple-choice question about the probability of a random answer to itself being correct (for reviewers: only option (c) is different from the duplicating target, but 60% clearly doesn't make more sense than 0%)
  $endgroup$
  – YuiTo Cheng
  8 hours ago
  
  
  

  
  
  
  

add a comment | 

2

1

$begingroup$

This question already has an answer here:

• 
  Multiple-choice question about the probability of a random answer to itself being correct
  
  6 answers
  
  

I came across this question, which I believe cannot be satisfactorily answered, but I'm not completely sure. Can you tell me if it has a answer?

If you choose the answer to this question at random,

what is the chance that you will be correct?

a) 25%

b) 50%

c) 60%

d) 25%

logic paradoxes

share|cite|improve this question

edited 8 hours ago

Bernard

124k741116

asked 11 hours ago

Ricardo MagallanesRicardo Magallanes

264

$endgroup$

marked as duplicate by Martin R, Community♦ 6 hours ago

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  Possible duplicate of Multiple-choice question about the probability of a random answer to itself being correct (for reviewers: only option (c) is different from the duplicating target, but 60% clearly doesn't make more sense than 0%)
  $endgroup$
  – YuiTo Cheng
  8 hours ago
  
  
  

  
  
  
  

add a comment | 

$begingroup$

This question already has an answer here:

• 
  Multiple-choice question about the probability of a random answer to itself being correct
  
  6 answers
  
  

I came across this question, which I believe cannot be satisfactorily answered, but I'm not completely sure. Can you tell me if it has a answer?

If you choose the answer to this question at random,

what is the chance that you will be correct?

a) 25%

b) 50%

c) 60%

d) 25%

logic paradoxes

share|cite|improve this question

edited 8 hours ago

Bernard

124k741116

asked 11 hours ago

Ricardo MagallanesRicardo Magallanes

264

$endgroup$

If you choose the answer to this question at random,

what is the chance that you will be correct?

a) 25%

b) 50%

c) 60%

d) 25%

share|cite|improve this question

edited 8 hours ago

Bernard

124k741116

asked 11 hours ago

Ricardo MagallanesRicardo Magallanes

264

share|cite|improve this question

edited 8 hours ago

Bernard

124k741116

asked 11 hours ago

Ricardo MagallanesRicardo Magallanes

264

edited 8 hours ago

Bernard

124k741116

edited 8 hours ago

Bernard

124k741116

asked 11 hours ago

Ricardo MagallanesRicardo Magallanes

264

asked 11 hours ago

Ricardo MagallanesRicardo Magallanes

264

1 Answer
1

active

oldest

votes

3

$begingroup$

Correct (on the typical assumptions we can only pick one answer, that the selection is uniformly random, etc.). The question is actually a fairly common paradox. The cause is the sort of self-referential nature of the question.

• Typically for multiple-choice questions with four answers, at random there is a $25%$ chance to get it right. But two answers have that choice.




• So logically it would be $50%$, but only one choice corresponds to that. So you're damned if you pick either one: if $50%$ is correct, the odds are $25%$ and if $25%$ is correct the odds are $50%$.




• $60%$ simply makes no sense, being not a multiple of $25%$, and can be ruled out outright.

So as it is posed, there is no correct answer.

share|cite|improve this answer

answered 11 hours ago

Eevee TrainerEevee Trainer

10.1k31742

$endgroup$

add a comment | 

3

$begingroup$

Correct (on the typical assumptions we can only pick one answer, that the selection is uniformly random, etc.). The question is actually a fairly common paradox. The cause is the sort of self-referential nature of the question.

• Typically for multiple-choice questions with four answers, at random there is a $25%$ chance to get it right. But two answers have that choice.




• So logically it would be $50%$, but only one choice corresponds to that. So you're damned if you pick either one: if $50%$ is correct, the odds are $25%$ and if $25%$ is correct the odds are $50%$.




• $60%$ simply makes no sense, being not a multiple of $25%$, and can be ruled out outright.

So as it is posed, there is no correct answer.

share|cite|improve this answer

answered 11 hours ago

Eevee TrainerEevee Trainer

10.1k31742

$endgroup$

add a comment | 

3

$begingroup$

Correct (on the typical assumptions we can only pick one answer, that the selection is uniformly random, etc.). The question is actually a fairly common paradox. The cause is the sort of self-referential nature of the question.

• Typically for multiple-choice questions with four answers, at random there is a $25%$ chance to get it right. But two answers have that choice.




• So logically it would be $50%$, but only one choice corresponds to that. So you're damned if you pick either one: if $50%$ is correct, the odds are $25%$ and if $25%$ is correct the odds are $50%$.




• $60%$ simply makes no sense, being not a multiple of $25%$, and can be ruled out outright.

So as it is posed, there is no correct answer.

share|cite|improve this answer

answered 11 hours ago

Eevee TrainerEevee Trainer

10.1k31742

$endgroup$

add a comment | 

$begingroup$

Correct (on the typical assumptions we can only pick one answer, that the selection is uniformly random, etc.). The question is actually a fairly common paradox. The cause is the sort of self-referential nature of the question.

• Typically for multiple-choice questions with four answers, at random there is a $25%$ chance to get it right. But two answers have that choice.




• So logically it would be $50%$, but only one choice corresponds to that. So you're damned if you pick either one: if $50%$ is correct, the odds are $25%$ and if $25%$ is correct the odds are $50%$.




• $60%$ simply makes no sense, being not a multiple of $25%$, and can be ruled out outright.

So as it is posed, there is no correct answer.

share|cite|improve this answer

answered 11 hours ago

Eevee TrainerEevee Trainer

10.1k31742

$endgroup$

share|cite|improve this answer

answered 11 hours ago

Eevee TrainerEevee Trainer

10.1k31742

answered 11 hours ago

Eevee TrainerEevee Trainer

10.1k31742

answered 11 hours ago

Eevee TrainerEevee Trainer

10.1k31742