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Another way to align this equation?

1

Is there another way to align this equation?
I tried two ways

documentclass[12pt,a4paper]{article}

usepackage{amsmath}

usepackage{mathtools}

DeclarePairedDelimiterabs{lvert}{rvert}

begin{document}

begin{alignat}{2}

P &=abs{z^2 + z} && + abs{z^2 - z} \

&= abs{z (z+1)} && + abs{z (z-1)} \

& = |z| abs{z+1} && + |z| abs{z-1} \

& =  abs{z+1} && + abs{z-1}

end{alignat}   



    begin{alignat*}{4}

    P &=abs{z^2 &&+ z} &&+ abs{z^2 &&- z} \

    &= abs{z (z&&+1)} &&+ abs{z (z&&-1)} \

    & = |z| abs{z&&+1} &&+ |z| abs{z&&-1} \

    & =  abs{z&&+1} &&+ abs{z&&-1}

    end{alignat*}

end{document}

align

share|improve this question

asked 10 mins ago

minhthien_2016minhthien_2016

1,4791917

add a comment | 

1

Is there another way to align this equation?
I tried two ways

documentclass[12pt,a4paper]{article}

usepackage{amsmath}

usepackage{mathtools}

DeclarePairedDelimiterabs{lvert}{rvert}

begin{document}

begin{alignat}{2}

P &=abs{z^2 + z} && + abs{z^2 - z} \

&= abs{z (z+1)} && + abs{z (z-1)} \

& = |z| abs{z+1} && + |z| abs{z-1} \

& =  abs{z+1} && + abs{z-1}

end{alignat}   



    begin{alignat*}{4}

    P &=abs{z^2 &&+ z} &&+ abs{z^2 &&- z} \

    &= abs{z (z&&+1)} &&+ abs{z (z&&-1)} \

    & = |z| abs{z&&+1} &&+ |z| abs{z&&-1} \

    & =  abs{z&&+1} &&+ abs{z&&-1}

    end{alignat*}

end{document}

align

share|improve this question

asked 10 mins ago

minhthien_2016minhthien_2016

1,4791917

add a comment | 

Is there another way to align this equation?
I tried two ways

documentclass[12pt,a4paper]{article}

usepackage{amsmath}

usepackage{mathtools}

DeclarePairedDelimiterabs{lvert}{rvert}

begin{document}

begin{alignat}{2}

P &=abs{z^2 + z} && + abs{z^2 - z} \

&= abs{z (z+1)} && + abs{z (z-1)} \

& = |z| abs{z+1} && + |z| abs{z-1} \

& =  abs{z+1} && + abs{z-1}

end{alignat}   



    begin{alignat*}{4}

    P &=abs{z^2 &&+ z} &&+ abs{z^2 &&- z} \

    &= abs{z (z&&+1)} &&+ abs{z (z&&-1)} \

    & = |z| abs{z&&+1} &&+ |z| abs{z&&-1} \

    & =  abs{z&&+1} &&+ abs{z&&-1}

    end{alignat*}

end{document}

align

share|improve this question

asked 10 mins ago

minhthien_2016minhthien_2016

1,4791917

documentclass[12pt,a4paper]{article}

usepackage{amsmath}

usepackage{mathtools}

DeclarePairedDelimiterabs{lvert}{rvert}

begin{document}

begin{alignat}{2}

P &=abs{z^2 + z} && + abs{z^2 - z} \

&= abs{z (z+1)} && + abs{z (z-1)} \

& = |z| abs{z+1} && + |z| abs{z-1} \

& =  abs{z+1} && + abs{z-1}

end{alignat}   



    begin{alignat*}{4}

    P &=abs{z^2 &&+ z} &&+ abs{z^2 &&- z} \

    &= abs{z (z&&+1)} &&+ abs{z (z&&-1)} \

    & = |z| abs{z&&+1} &&+ |z| abs{z&&-1} \

    & =  abs{z&&+1} &&+ abs{z&&-1}

    end{alignat*}

end{document}

share|improve this question

asked 10 mins ago

minhthien_2016minhthien_2016

1,4791917

share|improve this question

asked 10 mins ago

minhthien_2016minhthien_2016

1,4791917

asked 10 mins ago

minhthien_2016minhthien_2016

1,4791917

asked 10 mins ago

minhthien_2016minhthien_2016

1,4791917