TikZ: Advantage of position values attached with a unit?Drawing simple 3D cylinders in TikZtikz-3dplot causes...

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TikZ: Advantage of position values attached with a unit?


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1















Regarding TikZ-images: When should I type positioning values attached with a unit (e.g. draw (0cm, 0cm)...) and when should I type them without a unit (e.g. simply draw (0, 0)...)?





Minimum Working Example No. 1:



documentclass[border=5mm]{standalone}
usepackage{tikz}

begin{document}
begin{tikzpicture}
draw (0, 0) rectangle (4, 4);
end{tikzpicture}
end{document}




Minimum Working Example No. 2:



documentclass[border=5mm]{standalone}
usepackage{tikz}

begin{document}
begin{tikzpicture}
draw (0cm, 0cm) rectangle (4cm, 4cm);
end{tikzpicture}
end{document}




Screenshot of the result from MWE no. 1:



Screenshot of MWE no. 1





Screenshot of the result from MWE no. 2:



Screenshot of MWE no. 2





As you can see, both codes will create the completely same picture. Therefore: What is the advantage of draw (0cm, 0cm)... over draw (0, 0)... and vice versa?










share|improve this question


















  • 1





    default unit in tikz (with some exception, for example at xshift, yshift) is cm, so, if you stick with it you not need to write it explicit.

    – Zarko
    7 hours ago













  • TikZ interprets (x,y) as x*e_1+y*e_2, where the defaults for the unit vectors e_i are e_1=(1cm,0) and e_2=(0,1cm). The perhaps clearest explanation can be found in this answer by LoopSpace, which was written at a time when Jake still had questions. And I disagree with @Zarko, the default unit for TikZ is pt.

    – marmot
    4 hours ago
















1















Regarding TikZ-images: When should I type positioning values attached with a unit (e.g. draw (0cm, 0cm)...) and when should I type them without a unit (e.g. simply draw (0, 0)...)?





Minimum Working Example No. 1:



documentclass[border=5mm]{standalone}
usepackage{tikz}

begin{document}
begin{tikzpicture}
draw (0, 0) rectangle (4, 4);
end{tikzpicture}
end{document}




Minimum Working Example No. 2:



documentclass[border=5mm]{standalone}
usepackage{tikz}

begin{document}
begin{tikzpicture}
draw (0cm, 0cm) rectangle (4cm, 4cm);
end{tikzpicture}
end{document}




Screenshot of the result from MWE no. 1:



Screenshot of MWE no. 1





Screenshot of the result from MWE no. 2:



Screenshot of MWE no. 2





As you can see, both codes will create the completely same picture. Therefore: What is the advantage of draw (0cm, 0cm)... over draw (0, 0)... and vice versa?










share|improve this question


















  • 1





    default unit in tikz (with some exception, for example at xshift, yshift) is cm, so, if you stick with it you not need to write it explicit.

    – Zarko
    7 hours ago













  • TikZ interprets (x,y) as x*e_1+y*e_2, where the defaults for the unit vectors e_i are e_1=(1cm,0) and e_2=(0,1cm). The perhaps clearest explanation can be found in this answer by LoopSpace, which was written at a time when Jake still had questions. And I disagree with @Zarko, the default unit for TikZ is pt.

    – marmot
    4 hours ago














1












1








1


1






Regarding TikZ-images: When should I type positioning values attached with a unit (e.g. draw (0cm, 0cm)...) and when should I type them without a unit (e.g. simply draw (0, 0)...)?





Minimum Working Example No. 1:



documentclass[border=5mm]{standalone}
usepackage{tikz}

begin{document}
begin{tikzpicture}
draw (0, 0) rectangle (4, 4);
end{tikzpicture}
end{document}




Minimum Working Example No. 2:



documentclass[border=5mm]{standalone}
usepackage{tikz}

begin{document}
begin{tikzpicture}
draw (0cm, 0cm) rectangle (4cm, 4cm);
end{tikzpicture}
end{document}




Screenshot of the result from MWE no. 1:



Screenshot of MWE no. 1





Screenshot of the result from MWE no. 2:



Screenshot of MWE no. 2





As you can see, both codes will create the completely same picture. Therefore: What is the advantage of draw (0cm, 0cm)... over draw (0, 0)... and vice versa?










share|improve this question














Regarding TikZ-images: When should I type positioning values attached with a unit (e.g. draw (0cm, 0cm)...) and when should I type them without a unit (e.g. simply draw (0, 0)...)?





Minimum Working Example No. 1:



documentclass[border=5mm]{standalone}
usepackage{tikz}

begin{document}
begin{tikzpicture}
draw (0, 0) rectangle (4, 4);
end{tikzpicture}
end{document}




Minimum Working Example No. 2:



documentclass[border=5mm]{standalone}
usepackage{tikz}

begin{document}
begin{tikzpicture}
draw (0cm, 0cm) rectangle (4cm, 4cm);
end{tikzpicture}
end{document}




Screenshot of the result from MWE no. 1:



Screenshot of MWE no. 1





Screenshot of the result from MWE no. 2:



Screenshot of MWE no. 2





As you can see, both codes will create the completely same picture. Therefore: What is the advantage of draw (0cm, 0cm)... over draw (0, 0)... and vice versa?







tikz-pgf positioning draw units unit-of-measure






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 7 hours ago









DaveDave

1,195619




1,195619








  • 1





    default unit in tikz (with some exception, for example at xshift, yshift) is cm, so, if you stick with it you not need to write it explicit.

    – Zarko
    7 hours ago













  • TikZ interprets (x,y) as x*e_1+y*e_2, where the defaults for the unit vectors e_i are e_1=(1cm,0) and e_2=(0,1cm). The perhaps clearest explanation can be found in this answer by LoopSpace, which was written at a time when Jake still had questions. And I disagree with @Zarko, the default unit for TikZ is pt.

    – marmot
    4 hours ago














  • 1





    default unit in tikz (with some exception, for example at xshift, yshift) is cm, so, if you stick with it you not need to write it explicit.

    – Zarko
    7 hours ago













  • TikZ interprets (x,y) as x*e_1+y*e_2, where the defaults for the unit vectors e_i are e_1=(1cm,0) and e_2=(0,1cm). The perhaps clearest explanation can be found in this answer by LoopSpace, which was written at a time when Jake still had questions. And I disagree with @Zarko, the default unit for TikZ is pt.

    – marmot
    4 hours ago








1




1





default unit in tikz (with some exception, for example at xshift, yshift) is cm, so, if you stick with it you not need to write it explicit.

– Zarko
7 hours ago







default unit in tikz (with some exception, for example at xshift, yshift) is cm, so, if you stick with it you not need to write it explicit.

– Zarko
7 hours ago















TikZ interprets (x,y) as x*e_1+y*e_2, where the defaults for the unit vectors e_i are e_1=(1cm,0) and e_2=(0,1cm). The perhaps clearest explanation can be found in this answer by LoopSpace, which was written at a time when Jake still had questions. And I disagree with @Zarko, the default unit for TikZ is pt.

– marmot
4 hours ago





TikZ interprets (x,y) as x*e_1+y*e_2, where the defaults for the unit vectors e_i are e_1=(1cm,0) and e_2=(0,1cm). The perhaps clearest explanation can be found in this answer by LoopSpace, which was written at a time when Jake still had questions. And I disagree with @Zarko, the default unit for TikZ is pt.

– marmot
4 hours ago










1 Answer
1






active

oldest

votes


















0














These two expressions are in principle very different and give "accidentally" the same result. IMHO the clearest discussion of this site can be found in this nice answer by LoopSpace, out of which I recycle some relevant parts here. TikZ interprets (x,y) rather differently depending on whether or not x and y carry units.




  1. If they are dimensionless, then the coordinate (x,y) means x times unit vector in x direction plus y times unit vector in y direction.

  2. If they carry units, then it just means x to the right and y up.


By default, the unit vector in x direction is (1cm,0) and the unit vector in y direction is (0,1cm), such that for two dimensionless numbers x and y in the default settings (x,y) and (xcm,ycm) yield the same result, which is what your MWEs illustrate. However, if we change the basis vectors, this is no longer true, as the following example shows (using a rectangle may not be the best example to illustrate these issues, but at least it is simple).



documentclass[border=5mm]{standalone}
usepackage{tikz}

begin{document}
begin{tikzpicture}[font=sffamily]
begin{scope}[local bounding box=standard]
begin{scope}[local bounding box=without units 1]
draw (0, 0) rectangle (4, 4);
end{scope}
node[above] at (without units 1.north){without units};
begin{scope}[xshift=5cm,local bounding box=with units 1]
draw (0cm, 0cm) rectangle (4cm, 4cm);
end{scope}
node[above] at (with units 1.north){with units};
end{scope}
node[rotate=90,above=2em] at (standard.west){standard unit vectors};
begin{scope}[local bounding box=nonstandard,
yshift=-5cm,x={(0.75,0.25)},y={(0,0.8)}]
begin{scope}[local bounding box=without units 2]
draw (0, 0) rectangle (4, 4);
end{scope}
node[above] at (without units 2.north){without units};
begin{scope}[xshift=5cm,local bounding box=with units 2]
draw (0cm, 0cm) rectangle (4cm, 4cm);
end{scope}
node[above] at (with units 2.north){with units};
end{scope}
node[rotate=90,above=2em] at (nonstandard.west){nonstandard unit vectors};
end{tikzpicture}
end{document}


enter image description here



Internally pgf uses pt as units, which is why the pgf key xshift=2 yields a shift by 2pt (as remarked by Zarko). However, this does not mean that the radii of circles get interpreted as pt, rather, as explained in this nice answer by LoopSpace the command draw[ultra thick] (0,0) circle[x radius=2,y radius=2]; yields, in the default coordinate system, a circle of radius 2cm.



So a possible answer to the question




When should I type positioning values attached with a unit (e.g. draw
(0cm, 0cm)...)
and when should I type them without a unit (e.g. simply
draw (0, 0)...)?




is




It depends on what you need and/or are doing. In many situations you
install nonstandard coordinate systems for a reason, which is why you
may not want to add cm when dealing with them.




Side-remark: the tikz-3dplot package adds cm to all coordinates, which can lead to confusion in some cases.






share|improve this answer
























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    0














    These two expressions are in principle very different and give "accidentally" the same result. IMHO the clearest discussion of this site can be found in this nice answer by LoopSpace, out of which I recycle some relevant parts here. TikZ interprets (x,y) rather differently depending on whether or not x and y carry units.




    1. If they are dimensionless, then the coordinate (x,y) means x times unit vector in x direction plus y times unit vector in y direction.

    2. If they carry units, then it just means x to the right and y up.


    By default, the unit vector in x direction is (1cm,0) and the unit vector in y direction is (0,1cm), such that for two dimensionless numbers x and y in the default settings (x,y) and (xcm,ycm) yield the same result, which is what your MWEs illustrate. However, if we change the basis vectors, this is no longer true, as the following example shows (using a rectangle may not be the best example to illustrate these issues, but at least it is simple).



    documentclass[border=5mm]{standalone}
    usepackage{tikz}

    begin{document}
    begin{tikzpicture}[font=sffamily]
    begin{scope}[local bounding box=standard]
    begin{scope}[local bounding box=without units 1]
    draw (0, 0) rectangle (4, 4);
    end{scope}
    node[above] at (without units 1.north){without units};
    begin{scope}[xshift=5cm,local bounding box=with units 1]
    draw (0cm, 0cm) rectangle (4cm, 4cm);
    end{scope}
    node[above] at (with units 1.north){with units};
    end{scope}
    node[rotate=90,above=2em] at (standard.west){standard unit vectors};
    begin{scope}[local bounding box=nonstandard,
    yshift=-5cm,x={(0.75,0.25)},y={(0,0.8)}]
    begin{scope}[local bounding box=without units 2]
    draw (0, 0) rectangle (4, 4);
    end{scope}
    node[above] at (without units 2.north){without units};
    begin{scope}[xshift=5cm,local bounding box=with units 2]
    draw (0cm, 0cm) rectangle (4cm, 4cm);
    end{scope}
    node[above] at (with units 2.north){with units};
    end{scope}
    node[rotate=90,above=2em] at (nonstandard.west){nonstandard unit vectors};
    end{tikzpicture}
    end{document}


    enter image description here



    Internally pgf uses pt as units, which is why the pgf key xshift=2 yields a shift by 2pt (as remarked by Zarko). However, this does not mean that the radii of circles get interpreted as pt, rather, as explained in this nice answer by LoopSpace the command draw[ultra thick] (0,0) circle[x radius=2,y radius=2]; yields, in the default coordinate system, a circle of radius 2cm.



    So a possible answer to the question




    When should I type positioning values attached with a unit (e.g. draw
    (0cm, 0cm)...)
    and when should I type them without a unit (e.g. simply
    draw (0, 0)...)?




    is




    It depends on what you need and/or are doing. In many situations you
    install nonstandard coordinate systems for a reason, which is why you
    may not want to add cm when dealing with them.




    Side-remark: the tikz-3dplot package adds cm to all coordinates, which can lead to confusion in some cases.






    share|improve this answer




























      0














      These two expressions are in principle very different and give "accidentally" the same result. IMHO the clearest discussion of this site can be found in this nice answer by LoopSpace, out of which I recycle some relevant parts here. TikZ interprets (x,y) rather differently depending on whether or not x and y carry units.




      1. If they are dimensionless, then the coordinate (x,y) means x times unit vector in x direction plus y times unit vector in y direction.

      2. If they carry units, then it just means x to the right and y up.


      By default, the unit vector in x direction is (1cm,0) and the unit vector in y direction is (0,1cm), such that for two dimensionless numbers x and y in the default settings (x,y) and (xcm,ycm) yield the same result, which is what your MWEs illustrate. However, if we change the basis vectors, this is no longer true, as the following example shows (using a rectangle may not be the best example to illustrate these issues, but at least it is simple).



      documentclass[border=5mm]{standalone}
      usepackage{tikz}

      begin{document}
      begin{tikzpicture}[font=sffamily]
      begin{scope}[local bounding box=standard]
      begin{scope}[local bounding box=without units 1]
      draw (0, 0) rectangle (4, 4);
      end{scope}
      node[above] at (without units 1.north){without units};
      begin{scope}[xshift=5cm,local bounding box=with units 1]
      draw (0cm, 0cm) rectangle (4cm, 4cm);
      end{scope}
      node[above] at (with units 1.north){with units};
      end{scope}
      node[rotate=90,above=2em] at (standard.west){standard unit vectors};
      begin{scope}[local bounding box=nonstandard,
      yshift=-5cm,x={(0.75,0.25)},y={(0,0.8)}]
      begin{scope}[local bounding box=without units 2]
      draw (0, 0) rectangle (4, 4);
      end{scope}
      node[above] at (without units 2.north){without units};
      begin{scope}[xshift=5cm,local bounding box=with units 2]
      draw (0cm, 0cm) rectangle (4cm, 4cm);
      end{scope}
      node[above] at (with units 2.north){with units};
      end{scope}
      node[rotate=90,above=2em] at (nonstandard.west){nonstandard unit vectors};
      end{tikzpicture}
      end{document}


      enter image description here



      Internally pgf uses pt as units, which is why the pgf key xshift=2 yields a shift by 2pt (as remarked by Zarko). However, this does not mean that the radii of circles get interpreted as pt, rather, as explained in this nice answer by LoopSpace the command draw[ultra thick] (0,0) circle[x radius=2,y radius=2]; yields, in the default coordinate system, a circle of radius 2cm.



      So a possible answer to the question




      When should I type positioning values attached with a unit (e.g. draw
      (0cm, 0cm)...)
      and when should I type them without a unit (e.g. simply
      draw (0, 0)...)?




      is




      It depends on what you need and/or are doing. In many situations you
      install nonstandard coordinate systems for a reason, which is why you
      may not want to add cm when dealing with them.




      Side-remark: the tikz-3dplot package adds cm to all coordinates, which can lead to confusion in some cases.






      share|improve this answer


























        0












        0








        0







        These two expressions are in principle very different and give "accidentally" the same result. IMHO the clearest discussion of this site can be found in this nice answer by LoopSpace, out of which I recycle some relevant parts here. TikZ interprets (x,y) rather differently depending on whether or not x and y carry units.




        1. If they are dimensionless, then the coordinate (x,y) means x times unit vector in x direction plus y times unit vector in y direction.

        2. If they carry units, then it just means x to the right and y up.


        By default, the unit vector in x direction is (1cm,0) and the unit vector in y direction is (0,1cm), such that for two dimensionless numbers x and y in the default settings (x,y) and (xcm,ycm) yield the same result, which is what your MWEs illustrate. However, if we change the basis vectors, this is no longer true, as the following example shows (using a rectangle may not be the best example to illustrate these issues, but at least it is simple).



        documentclass[border=5mm]{standalone}
        usepackage{tikz}

        begin{document}
        begin{tikzpicture}[font=sffamily]
        begin{scope}[local bounding box=standard]
        begin{scope}[local bounding box=without units 1]
        draw (0, 0) rectangle (4, 4);
        end{scope}
        node[above] at (without units 1.north){without units};
        begin{scope}[xshift=5cm,local bounding box=with units 1]
        draw (0cm, 0cm) rectangle (4cm, 4cm);
        end{scope}
        node[above] at (with units 1.north){with units};
        end{scope}
        node[rotate=90,above=2em] at (standard.west){standard unit vectors};
        begin{scope}[local bounding box=nonstandard,
        yshift=-5cm,x={(0.75,0.25)},y={(0,0.8)}]
        begin{scope}[local bounding box=without units 2]
        draw (0, 0) rectangle (4, 4);
        end{scope}
        node[above] at (without units 2.north){without units};
        begin{scope}[xshift=5cm,local bounding box=with units 2]
        draw (0cm, 0cm) rectangle (4cm, 4cm);
        end{scope}
        node[above] at (with units 2.north){with units};
        end{scope}
        node[rotate=90,above=2em] at (nonstandard.west){nonstandard unit vectors};
        end{tikzpicture}
        end{document}


        enter image description here



        Internally pgf uses pt as units, which is why the pgf key xshift=2 yields a shift by 2pt (as remarked by Zarko). However, this does not mean that the radii of circles get interpreted as pt, rather, as explained in this nice answer by LoopSpace the command draw[ultra thick] (0,0) circle[x radius=2,y radius=2]; yields, in the default coordinate system, a circle of radius 2cm.



        So a possible answer to the question




        When should I type positioning values attached with a unit (e.g. draw
        (0cm, 0cm)...)
        and when should I type them without a unit (e.g. simply
        draw (0, 0)...)?




        is




        It depends on what you need and/or are doing. In many situations you
        install nonstandard coordinate systems for a reason, which is why you
        may not want to add cm when dealing with them.




        Side-remark: the tikz-3dplot package adds cm to all coordinates, which can lead to confusion in some cases.






        share|improve this answer













        These two expressions are in principle very different and give "accidentally" the same result. IMHO the clearest discussion of this site can be found in this nice answer by LoopSpace, out of which I recycle some relevant parts here. TikZ interprets (x,y) rather differently depending on whether or not x and y carry units.




        1. If they are dimensionless, then the coordinate (x,y) means x times unit vector in x direction plus y times unit vector in y direction.

        2. If they carry units, then it just means x to the right and y up.


        By default, the unit vector in x direction is (1cm,0) and the unit vector in y direction is (0,1cm), such that for two dimensionless numbers x and y in the default settings (x,y) and (xcm,ycm) yield the same result, which is what your MWEs illustrate. However, if we change the basis vectors, this is no longer true, as the following example shows (using a rectangle may not be the best example to illustrate these issues, but at least it is simple).



        documentclass[border=5mm]{standalone}
        usepackage{tikz}

        begin{document}
        begin{tikzpicture}[font=sffamily]
        begin{scope}[local bounding box=standard]
        begin{scope}[local bounding box=without units 1]
        draw (0, 0) rectangle (4, 4);
        end{scope}
        node[above] at (without units 1.north){without units};
        begin{scope}[xshift=5cm,local bounding box=with units 1]
        draw (0cm, 0cm) rectangle (4cm, 4cm);
        end{scope}
        node[above] at (with units 1.north){with units};
        end{scope}
        node[rotate=90,above=2em] at (standard.west){standard unit vectors};
        begin{scope}[local bounding box=nonstandard,
        yshift=-5cm,x={(0.75,0.25)},y={(0,0.8)}]
        begin{scope}[local bounding box=without units 2]
        draw (0, 0) rectangle (4, 4);
        end{scope}
        node[above] at (without units 2.north){without units};
        begin{scope}[xshift=5cm,local bounding box=with units 2]
        draw (0cm, 0cm) rectangle (4cm, 4cm);
        end{scope}
        node[above] at (with units 2.north){with units};
        end{scope}
        node[rotate=90,above=2em] at (nonstandard.west){nonstandard unit vectors};
        end{tikzpicture}
        end{document}


        enter image description here



        Internally pgf uses pt as units, which is why the pgf key xshift=2 yields a shift by 2pt (as remarked by Zarko). However, this does not mean that the radii of circles get interpreted as pt, rather, as explained in this nice answer by LoopSpace the command draw[ultra thick] (0,0) circle[x radius=2,y radius=2]; yields, in the default coordinate system, a circle of radius 2cm.



        So a possible answer to the question




        When should I type positioning values attached with a unit (e.g. draw
        (0cm, 0cm)...)
        and when should I type them without a unit (e.g. simply
        draw (0, 0)...)?




        is




        It depends on what you need and/or are doing. In many situations you
        install nonstandard coordinate systems for a reason, which is why you
        may not want to add cm when dealing with them.




        Side-remark: the tikz-3dplot package adds cm to all coordinates, which can lead to confusion in some cases.







        share|improve this answer












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        answered 1 hour ago









        marmotmarmot

        115k5146277




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