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Adjusting the space between the caption below a figure


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4















I have the following:



documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{amsfonts, graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}
newtheorem{theorem}{Theorem}[section]
newtheorem{example}[theorem]{Example}

begin{document}
begin{example}
Consider a random walk on the $n$-cycle. Let $Omega = mathbb{Z}_n = lbrace 0, 1, 2, cdots, n-1 rbrace$ be the set of remainders modulo $n$. Also consider the transition matrix:
[
P(x,y) =
begin{cases}
frac{1}{2} & text{if } y=x+1;; (mod;n)\
frac{1}{2} & text{if } y=x-1;; (mod;n)\
0 & text{otherwise}
end{cases}
]

The associated Markov chain $X_t$ is called a random walk on the $n$-cycle. The sates can be visualised as equally spaced nodes arranged in a circle(see figure 1.1)
end{example}

begin{figure}[htbp]
centering
begin{tikzpicture}
foreach i in {90,54,...,-234} {
draw[ultra thick] (i:2)--({i-36}:2);
}
foreach i in {90,18,...,-198} {
draw[fill=black] (i:2) circle (1.25mm);
}
foreach i in {54,-18,...,-234} {
draw[fill=white] (i:2) circle (1.25mm);
}
begin{scope}[xshift=5cm]
foreach i in {90,50,...,-230} {
draw[ultra thick] (i:2)--({i-40}:2);
draw[fill=black] (i:2) circle (1.25mm);
}
end{scope}
end{tikzpicture}
caption{Random walk on $mathbb{Z}_10$ is periodic, since every step
goes from an even state to an odd state, or vice-versa. Random
walk on $mathbb{Z}_9$ is aperiodic.}
label{my:figure}
end{figure}
end{document}


now I want to adjust the spacing in the caption in the sense that i want to "push it into the middle", but I don't know how to proceed.



EDIT: similar question as above but the caption looks awful in this case, any fixes to stretch it out:



begin{example} Consider the graph $G$ following shown in figure 1.2. The transition matrix of a simple random walk $G$ is 

begin{equation*}
P =
begin{bmatrix}[1.25]
0 & frac{1}{3} & frac{1}{3} & frac{1}{3} & 0 & 0 \
frac{1}{4} & 0 & frac{1}{4} & 0 & frac{1}{4} & frac{1}{4} \
frac{1}{4} & frac{1}{4} & 0 & frac{1}{4} & frac{1}{4} & 0 \
frac{1}{3} & 0 & frac{1}{3} & 0 & frac{1}{3} & 0 \
0 & frac{1}{4} & frac{1}{4} & frac{1}{4} & 0 & frac{1}{4} \
0 & frac{1}{2} & 0 & 0 & frac{1}{2} & 0 \
end{bmatrix}
end{equation*}

begin{figure}[htbp]
centering
ffigbox[1.1FBwidth]{%
caption{An example of a vertex set $V = lbrace 1, 2, 3, 4, 5, 6rbrace$ with $10$ edges.}
label{my:figure}}%
{begin{tikzpicture}[bn/.style={circle,fill,draw,text=white,font=sffamily,minimum
size=1mm},every node/.append style={bn}]
path node (1) {1} -- ++ (50:2.5) node (2) {2} -- ++(-95:1.75) node (3) {3}
-- ++(-85:1.75) node (4) {4} -- ++(40:2.75) node (5) {5}
-- ++ (0,1.75) node (6) {6} ;
draw[thick] (1)--(2)--(6)--(5)--(4)--(1)--(3)--(5)--(2)--(3)--(4);
end{tikzpicture}}%
end{figure}
end{example}


is there a way to stretch this out into 2 lines at most?










share|improve this question









New contributor




Math is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





















  • the code is not compileable

    – AndréC
    Feb 27 at 16:22











  • @AndréC it should work now.

    – Math
    Feb 27 at 16:29













  • Your last sentence and the question title don't seem to match. Do you want more vertical space between the figure and the caption, or do you want to adjust the horizontal spacing of the caption?

    – Alan Munn
    Feb 27 at 17:13
















4















I have the following:



documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{amsfonts, graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}
newtheorem{theorem}{Theorem}[section]
newtheorem{example}[theorem]{Example}

begin{document}
begin{example}
Consider a random walk on the $n$-cycle. Let $Omega = mathbb{Z}_n = lbrace 0, 1, 2, cdots, n-1 rbrace$ be the set of remainders modulo $n$. Also consider the transition matrix:
[
P(x,y) =
begin{cases}
frac{1}{2} & text{if } y=x+1;; (mod;n)\
frac{1}{2} & text{if } y=x-1;; (mod;n)\
0 & text{otherwise}
end{cases}
]

The associated Markov chain $X_t$ is called a random walk on the $n$-cycle. The sates can be visualised as equally spaced nodes arranged in a circle(see figure 1.1)
end{example}

begin{figure}[htbp]
centering
begin{tikzpicture}
foreach i in {90,54,...,-234} {
draw[ultra thick] (i:2)--({i-36}:2);
}
foreach i in {90,18,...,-198} {
draw[fill=black] (i:2) circle (1.25mm);
}
foreach i in {54,-18,...,-234} {
draw[fill=white] (i:2) circle (1.25mm);
}
begin{scope}[xshift=5cm]
foreach i in {90,50,...,-230} {
draw[ultra thick] (i:2)--({i-40}:2);
draw[fill=black] (i:2) circle (1.25mm);
}
end{scope}
end{tikzpicture}
caption{Random walk on $mathbb{Z}_10$ is periodic, since every step
goes from an even state to an odd state, or vice-versa. Random
walk on $mathbb{Z}_9$ is aperiodic.}
label{my:figure}
end{figure}
end{document}


now I want to adjust the spacing in the caption in the sense that i want to "push it into the middle", but I don't know how to proceed.



EDIT: similar question as above but the caption looks awful in this case, any fixes to stretch it out:



begin{example} Consider the graph $G$ following shown in figure 1.2. The transition matrix of a simple random walk $G$ is 

begin{equation*}
P =
begin{bmatrix}[1.25]
0 & frac{1}{3} & frac{1}{3} & frac{1}{3} & 0 & 0 \
frac{1}{4} & 0 & frac{1}{4} & 0 & frac{1}{4} & frac{1}{4} \
frac{1}{4} & frac{1}{4} & 0 & frac{1}{4} & frac{1}{4} & 0 \
frac{1}{3} & 0 & frac{1}{3} & 0 & frac{1}{3} & 0 \
0 & frac{1}{4} & frac{1}{4} & frac{1}{4} & 0 & frac{1}{4} \
0 & frac{1}{2} & 0 & 0 & frac{1}{2} & 0 \
end{bmatrix}
end{equation*}

begin{figure}[htbp]
centering
ffigbox[1.1FBwidth]{%
caption{An example of a vertex set $V = lbrace 1, 2, 3, 4, 5, 6rbrace$ with $10$ edges.}
label{my:figure}}%
{begin{tikzpicture}[bn/.style={circle,fill,draw,text=white,font=sffamily,minimum
size=1mm},every node/.append style={bn}]
path node (1) {1} -- ++ (50:2.5) node (2) {2} -- ++(-95:1.75) node (3) {3}
-- ++(-85:1.75) node (4) {4} -- ++(40:2.75) node (5) {5}
-- ++ (0,1.75) node (6) {6} ;
draw[thick] (1)--(2)--(6)--(5)--(4)--(1)--(3)--(5)--(2)--(3)--(4);
end{tikzpicture}}%
end{figure}
end{example}


is there a way to stretch this out into 2 lines at most?










share|improve this question









New contributor




Math is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





















  • the code is not compileable

    – AndréC
    Feb 27 at 16:22











  • @AndréC it should work now.

    – Math
    Feb 27 at 16:29













  • Your last sentence and the question title don't seem to match. Do you want more vertical space between the figure and the caption, or do you want to adjust the horizontal spacing of the caption?

    – Alan Munn
    Feb 27 at 17:13














4












4








4








I have the following:



documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{amsfonts, graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}
newtheorem{theorem}{Theorem}[section]
newtheorem{example}[theorem]{Example}

begin{document}
begin{example}
Consider a random walk on the $n$-cycle. Let $Omega = mathbb{Z}_n = lbrace 0, 1, 2, cdots, n-1 rbrace$ be the set of remainders modulo $n$. Also consider the transition matrix:
[
P(x,y) =
begin{cases}
frac{1}{2} & text{if } y=x+1;; (mod;n)\
frac{1}{2} & text{if } y=x-1;; (mod;n)\
0 & text{otherwise}
end{cases}
]

The associated Markov chain $X_t$ is called a random walk on the $n$-cycle. The sates can be visualised as equally spaced nodes arranged in a circle(see figure 1.1)
end{example}

begin{figure}[htbp]
centering
begin{tikzpicture}
foreach i in {90,54,...,-234} {
draw[ultra thick] (i:2)--({i-36}:2);
}
foreach i in {90,18,...,-198} {
draw[fill=black] (i:2) circle (1.25mm);
}
foreach i in {54,-18,...,-234} {
draw[fill=white] (i:2) circle (1.25mm);
}
begin{scope}[xshift=5cm]
foreach i in {90,50,...,-230} {
draw[ultra thick] (i:2)--({i-40}:2);
draw[fill=black] (i:2) circle (1.25mm);
}
end{scope}
end{tikzpicture}
caption{Random walk on $mathbb{Z}_10$ is periodic, since every step
goes from an even state to an odd state, or vice-versa. Random
walk on $mathbb{Z}_9$ is aperiodic.}
label{my:figure}
end{figure}
end{document}


now I want to adjust the spacing in the caption in the sense that i want to "push it into the middle", but I don't know how to proceed.



EDIT: similar question as above but the caption looks awful in this case, any fixes to stretch it out:



begin{example} Consider the graph $G$ following shown in figure 1.2. The transition matrix of a simple random walk $G$ is 

begin{equation*}
P =
begin{bmatrix}[1.25]
0 & frac{1}{3} & frac{1}{3} & frac{1}{3} & 0 & 0 \
frac{1}{4} & 0 & frac{1}{4} & 0 & frac{1}{4} & frac{1}{4} \
frac{1}{4} & frac{1}{4} & 0 & frac{1}{4} & frac{1}{4} & 0 \
frac{1}{3} & 0 & frac{1}{3} & 0 & frac{1}{3} & 0 \
0 & frac{1}{4} & frac{1}{4} & frac{1}{4} & 0 & frac{1}{4} \
0 & frac{1}{2} & 0 & 0 & frac{1}{2} & 0 \
end{bmatrix}
end{equation*}

begin{figure}[htbp]
centering
ffigbox[1.1FBwidth]{%
caption{An example of a vertex set $V = lbrace 1, 2, 3, 4, 5, 6rbrace$ with $10$ edges.}
label{my:figure}}%
{begin{tikzpicture}[bn/.style={circle,fill,draw,text=white,font=sffamily,minimum
size=1mm},every node/.append style={bn}]
path node (1) {1} -- ++ (50:2.5) node (2) {2} -- ++(-95:1.75) node (3) {3}
-- ++(-85:1.75) node (4) {4} -- ++(40:2.75) node (5) {5}
-- ++ (0,1.75) node (6) {6} ;
draw[thick] (1)--(2)--(6)--(5)--(4)--(1)--(3)--(5)--(2)--(3)--(4);
end{tikzpicture}}%
end{figure}
end{example}


is there a way to stretch this out into 2 lines at most?










share|improve this question









New contributor




Math is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












I have the following:



documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{amsfonts, graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}
newtheorem{theorem}{Theorem}[section]
newtheorem{example}[theorem]{Example}

begin{document}
begin{example}
Consider a random walk on the $n$-cycle. Let $Omega = mathbb{Z}_n = lbrace 0, 1, 2, cdots, n-1 rbrace$ be the set of remainders modulo $n$. Also consider the transition matrix:
[
P(x,y) =
begin{cases}
frac{1}{2} & text{if } y=x+1;; (mod;n)\
frac{1}{2} & text{if } y=x-1;; (mod;n)\
0 & text{otherwise}
end{cases}
]

The associated Markov chain $X_t$ is called a random walk on the $n$-cycle. The sates can be visualised as equally spaced nodes arranged in a circle(see figure 1.1)
end{example}

begin{figure}[htbp]
centering
begin{tikzpicture}
foreach i in {90,54,...,-234} {
draw[ultra thick] (i:2)--({i-36}:2);
}
foreach i in {90,18,...,-198} {
draw[fill=black] (i:2) circle (1.25mm);
}
foreach i in {54,-18,...,-234} {
draw[fill=white] (i:2) circle (1.25mm);
}
begin{scope}[xshift=5cm]
foreach i in {90,50,...,-230} {
draw[ultra thick] (i:2)--({i-40}:2);
draw[fill=black] (i:2) circle (1.25mm);
}
end{scope}
end{tikzpicture}
caption{Random walk on $mathbb{Z}_10$ is periodic, since every step
goes from an even state to an odd state, or vice-versa. Random
walk on $mathbb{Z}_9$ is aperiodic.}
label{my:figure}
end{figure}
end{document}


now I want to adjust the spacing in the caption in the sense that i want to "push it into the middle", but I don't know how to proceed.



EDIT: similar question as above but the caption looks awful in this case, any fixes to stretch it out:



begin{example} Consider the graph $G$ following shown in figure 1.2. The transition matrix of a simple random walk $G$ is 

begin{equation*}
P =
begin{bmatrix}[1.25]
0 & frac{1}{3} & frac{1}{3} & frac{1}{3} & 0 & 0 \
frac{1}{4} & 0 & frac{1}{4} & 0 & frac{1}{4} & frac{1}{4} \
frac{1}{4} & frac{1}{4} & 0 & frac{1}{4} & frac{1}{4} & 0 \
frac{1}{3} & 0 & frac{1}{3} & 0 & frac{1}{3} & 0 \
0 & frac{1}{4} & frac{1}{4} & frac{1}{4} & 0 & frac{1}{4} \
0 & frac{1}{2} & 0 & 0 & frac{1}{2} & 0 \
end{bmatrix}
end{equation*}

begin{figure}[htbp]
centering
ffigbox[1.1FBwidth]{%
caption{An example of a vertex set $V = lbrace 1, 2, 3, 4, 5, 6rbrace$ with $10$ edges.}
label{my:figure}}%
{begin{tikzpicture}[bn/.style={circle,fill,draw,text=white,font=sffamily,minimum
size=1mm},every node/.append style={bn}]
path node (1) {1} -- ++ (50:2.5) node (2) {2} -- ++(-95:1.75) node (3) {3}
-- ++(-85:1.75) node (4) {4} -- ++(40:2.75) node (5) {5}
-- ++ (0,1.75) node (6) {6} ;
draw[thick] (1)--(2)--(6)--(5)--(4)--(1)--(3)--(5)--(2)--(3)--(4);
end{tikzpicture}}%
end{figure}
end{example}


is there a way to stretch this out into 2 lines at most?







spacing captions






share|improve this question









New contributor




Math is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




Math is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited Mar 1 at 16:50







Math













New contributor




Math is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked Feb 27 at 16:01









MathMath

416




416




New contributor




Math is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Math is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Math is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.













  • the code is not compileable

    – AndréC
    Feb 27 at 16:22











  • @AndréC it should work now.

    – Math
    Feb 27 at 16:29













  • Your last sentence and the question title don't seem to match. Do you want more vertical space between the figure and the caption, or do you want to adjust the horizontal spacing of the caption?

    – Alan Munn
    Feb 27 at 17:13



















  • the code is not compileable

    – AndréC
    Feb 27 at 16:22











  • @AndréC it should work now.

    – Math
    Feb 27 at 16:29













  • Your last sentence and the question title don't seem to match. Do you want more vertical space between the figure and the caption, or do you want to adjust the horizontal spacing of the caption?

    – Alan Munn
    Feb 27 at 17:13

















the code is not compileable

– AndréC
Feb 27 at 16:22





the code is not compileable

– AndréC
Feb 27 at 16:22













@AndréC it should work now.

– Math
Feb 27 at 16:29







@AndréC it should work now.

– Math
Feb 27 at 16:29















Your last sentence and the question title don't seem to match. Do you want more vertical space between the figure and the caption, or do you want to adjust the horizontal spacing of the caption?

– Alan Munn
Feb 27 at 17:13





Your last sentence and the question title don't seem to match. Do you want more vertical space between the figure and the caption, or do you want to adjust the horizontal spacing of the caption?

– Alan Munn
Feb 27 at 17:13










2 Answers
2






active

oldest

votes


















2














If I understand you right, you can use the following two lines in your preamble



usepackage{caption} % <================================================
captionsetup{width=0.8textwidth} % <==================================


to let the caption use only 80% of textwidth. See the documentation of package caption for more possibilitys to manipulate the layout of captions with typing texdoc caption on ypur console/terminal.



The complete code



documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{amsfonts, graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}

usepackage{caption} % <================================================
captionsetup{width=0.8textwidth} % <==================================

newtheorem{theorem}{Theorem}[section]
newtheorem{example}[theorem]{Example}


begin{document}

begin{example}
Consider a random walk on the $n$-cycle.
Let $Omega = mathbb{Z}_n = lbrace 0, 1, 2, cdots, n-1 rbrace$ be
the set of remainders modulo $n$. Also consider the transition matrix:
[
P(x,y) =
begin{cases}
frac{1}{2} & text{if } y=x+1;; (mod;n)\
frac{1}{2} & text{if } y=x-1;; (mod;n)\
0 & text{otherwise}
end{cases}
]

The associated Markov chain $X_t$ is called a random walk on the
$n$-cycle. The sates can be visualised as equally spaced nodes arranged
in a circle (see figure~ref{my:figure}). % <==========================
end{example}

begin{figure}[htbp]
centering
begin{tikzpicture}
foreach i in {90,54,...,-234} {
draw[ultra thick] (i:2)--({i-36}:2);
}
foreach i in {90,18,...,-198} {
draw[fill=black] (i:2) circle (1.25mm);
}
foreach i in {54,-18,...,-234} {
draw[fill=white] (i:2) circle (1.25mm);
}
begin{scope}[xshift=5cm]
foreach i in {90,50,...,-230} {
draw[ultra thick] (i:2)--({i-40}:2);
draw[fill=black] (i:2) circle (1.25mm);
}
end{scope}
end{tikzpicture}
caption{Random walk on $mathbb{Z}_10$ is periodic, since every step
goes from an even state to an odd state, or vice-versa. Random
walk on $mathbb{Z}_9$ is aperiodic.}
label{my:figure}
end{figure}
Text after the figure.
end{document}


gives you the result:



resulting pdf



EDIT:



With your second example (after commenting ffigbox, see markings <====== in code)



documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{amsfonts, graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}

usepackage{floatrow}

usepackage{caption} % <================================================
captionsetup{width=0.8textwidth} % <==================================

newtheorem{theorem}{Theorem}[section]
newtheorem{example}[theorem]{Example}


begin{document}

begin{example}
Consider a random walk on the $n$-cycle.
Let $Omega = mathbb{Z}_n = lbrace 0, 1, 2, cdots, n-1 rbrace$ be
the set of remainders modulo $n$. Also consider the transition matrix:
[
P(x,y) =
begin{cases}
frac{1}{2} & text{if } y=x+1;; (mod;n)\
frac{1}{2} & text{if } y=x-1;; (mod;n)\
0 & text{otherwise}
end{cases}
]

The associated Markov chain $X_t$ is called a random walk on the
$n$-cycle. The sates can be visualised as equally spaced nodes arranged
in a circle (see figure~ref{my:figure}).
end{example}

begin{figure}[htbp]
centering
begin{tikzpicture}
foreach i in {90,54,...,-234} {
draw[ultra thick] (i:2)--({i-36}:2);
}
foreach i in {90,18,...,-198} {
draw[fill=black] (i:2) circle (1.25mm);
}
foreach i in {54,-18,...,-234} {
draw[fill=white] (i:2) circle (1.25mm);
}
begin{scope}[xshift=5cm]
foreach i in {90,50,...,-230} {
draw[ultra thick] (i:2)--({i-40}:2);
draw[fill=black] (i:2) circle (1.25mm);
}
end{scope}
end{tikzpicture}
caption{Random walk on $mathbb{Z}_10$ is periodic, since every step
goes from an even state to an odd state, or vice-versa. Random
walk on $mathbb{Z}_9$ is aperiodic.}
label{my:figure}
end{figure}
Text after the figure.

clearpage
begin{example} Consider the graph $G$ following shown in figure 1.2. The transition matrix of a simple random walk $G$ is

begin{equation*}
P =
begin{bmatrix}[1.25]
0 & frac{1}{3} & frac{1}{3} & frac{1}{3} & 0 & 0 \
frac{1}{4} & 0 & frac{1}{4} & 0 & frac{1}{4} & frac{1}{4} \
frac{1}{4} & frac{1}{4} & 0 & frac{1}{4} & frac{1}{4} & 0 \
frac{1}{3} & 0 & frac{1}{3} & 0 & frac{1}{3} & 0 \
0 & frac{1}{4} & frac{1}{4} & frac{1}{4} & 0 & frac{1}{4} \
0 & frac{1}{2} & 0 & 0 & frac{1}{2} & 0 \
end{bmatrix}
end{equation*}

begin{figure}[htbp]
centering
%ffigbox[1.1FBwidth]{% <==============================================
caption{An example of a vertex set $V = lbrace 1, 2, 3, 4, 5, 6rbrace$ with $10$ edges.}
label{my:figure}%
%}% <===================================================================
{begin{tikzpicture}[bn/.style={circle,fill,draw,text=white,font=sffamily,minimum
size=1mm},every node/.append style={bn}]
path node (1) {1} -- ++ (50:2.5) node (2) {2} -- ++(-95:1.75) node (3) {3}
-- ++(-85:1.75) node (4) {4} -- ++(40:2.75) node (5) {5}
-- ++ (0,1.75) node (6) {6} ;
draw[thick] (1)--(2)--(6)--(5)--(4)--(1)--(3)--(5)--(2)--(3)--(4);
end{tikzpicture}}%
end{figure}
end{example}
end{document}


you get the resulting second figure/page:



second page






share|improve this answer


























  • thanks, precisely what I wanted.

    – Math
    Mar 1 at 11:52











  • @Math You are welcome!

    – Kurt
    Mar 1 at 17:05











  • please check my edited question, there is another problem similar to this

    – Math
    Mar 1 at 17:06











  • @Math you mean the caption of figure with ffigbox? Comment ffigbox and the closing }. That looks much better I guess?

    – Kurt
    Mar 1 at 17:19











  • sorry I wasn't available on the weakened. Yes, could you edit your answer adding the extra part, it will be very helpful :)

    – Math
    16 hours ago



















2














If I've well understood what you want, this is easy with the ffigbox command from floatrow, which gives full control on the caption width:



documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}
newtheorem{theorem}{Theorem}[section]
newtheorem{example}[theorem]{Example}
usepackage{floatrow}

begin{document}

begin{example}
Consider a random walk on the $n$-cycle. Let $Omega = mathbb{Z}_n = lbrace 0, 1, 2, cdots, n-1 rbrace$ be the set of remainders modulo $n$. Also consider the transition matrix:
[
P(x,y) =
begin{cases}
frac{1}{2} & text{if } y=x+1 pmod n\
frac{1}{2} & text{if } y=x-1pmod n\
0 & text{otherwise}
end{cases}
]

The associated Markov chain $X_t$ is called a random walk on the $n$-cycle. The states can be visualised as equally spaced nodes arranged in a circle(see figure 1.1)
end{example}

begin{figure}[htbp]
centering
ffigbox[1.1FBwidth]{%
caption{Random walk on $mathbb{Z}_10$ is periodic, since every step
goes from an even state to an odd state, or vice-versa. Random
walk on $mathbb{Z}_9$ is aperiodic.}
label{my:figure}}%
{begin{tikzpicture}
foreach i in {90,54,...,-234} {
draw[ultra thick] (i:2)--({i-36}:2);
}
foreach i in {90,18,...,-198} {
draw[fill=black] (i:2) circle (1.25mm);
}
foreach i in {54,-18,...,-234} {
draw[fill=white] (i:2) circle (1.25mm);
}
begin{scope}[xshift=5cm]
foreach i in {90,50,...,-230} {
draw[ultra thick] (i:2)--({i-40}:2);
draw[fill=black] (i:2) circle (1.25mm);
}
end{scope}
end{tikzpicture}}%
end{figure}

end{document}


enter image description here






share|improve this answer
























  • +1 for another solution however Kurt beat you to it!

    – Math
    Mar 1 at 11:57













  • I'm not competing :o). The advantage with the solution with ffigbox, from my point of view, is that the caption width can be automatically calculated in function of the figure natural width.

    – Bernard
    Mar 1 at 12:07











  • I understand. the reason I liked Kurt's answer is because for this particular problem I will only need to adjust one number to get my desired output however the drawback is, with another figure, if it doesn't have the same dimensions as the figure above, the caption will be off

    – Math
    Mar 1 at 12:13











  • that's where your solution comes in handy I believe.

    – Math
    Mar 1 at 12:13











  • To clarify, will your method work for all figures?

    – Math
    Mar 1 at 12:17











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If I understand you right, you can use the following two lines in your preamble



usepackage{caption} % <================================================
captionsetup{width=0.8textwidth} % <==================================


to let the caption use only 80% of textwidth. See the documentation of package caption for more possibilitys to manipulate the layout of captions with typing texdoc caption on ypur console/terminal.



The complete code



documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{amsfonts, graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}

usepackage{caption} % <================================================
captionsetup{width=0.8textwidth} % <==================================

newtheorem{theorem}{Theorem}[section]
newtheorem{example}[theorem]{Example}


begin{document}

begin{example}
Consider a random walk on the $n$-cycle.
Let $Omega = mathbb{Z}_n = lbrace 0, 1, 2, cdots, n-1 rbrace$ be
the set of remainders modulo $n$. Also consider the transition matrix:
[
P(x,y) =
begin{cases}
frac{1}{2} & text{if } y=x+1;; (mod;n)\
frac{1}{2} & text{if } y=x-1;; (mod;n)\
0 & text{otherwise}
end{cases}
]

The associated Markov chain $X_t$ is called a random walk on the
$n$-cycle. The sates can be visualised as equally spaced nodes arranged
in a circle (see figure~ref{my:figure}). % <==========================
end{example}

begin{figure}[htbp]
centering
begin{tikzpicture}
foreach i in {90,54,...,-234} {
draw[ultra thick] (i:2)--({i-36}:2);
}
foreach i in {90,18,...,-198} {
draw[fill=black] (i:2) circle (1.25mm);
}
foreach i in {54,-18,...,-234} {
draw[fill=white] (i:2) circle (1.25mm);
}
begin{scope}[xshift=5cm]
foreach i in {90,50,...,-230} {
draw[ultra thick] (i:2)--({i-40}:2);
draw[fill=black] (i:2) circle (1.25mm);
}
end{scope}
end{tikzpicture}
caption{Random walk on $mathbb{Z}_10$ is periodic, since every step
goes from an even state to an odd state, or vice-versa. Random
walk on $mathbb{Z}_9$ is aperiodic.}
label{my:figure}
end{figure}
Text after the figure.
end{document}


gives you the result:



resulting pdf



EDIT:



With your second example (after commenting ffigbox, see markings <====== in code)



documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{amsfonts, graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}

usepackage{floatrow}

usepackage{caption} % <================================================
captionsetup{width=0.8textwidth} % <==================================

newtheorem{theorem}{Theorem}[section]
newtheorem{example}[theorem]{Example}


begin{document}

begin{example}
Consider a random walk on the $n$-cycle.
Let $Omega = mathbb{Z}_n = lbrace 0, 1, 2, cdots, n-1 rbrace$ be
the set of remainders modulo $n$. Also consider the transition matrix:
[
P(x,y) =
begin{cases}
frac{1}{2} & text{if } y=x+1;; (mod;n)\
frac{1}{2} & text{if } y=x-1;; (mod;n)\
0 & text{otherwise}
end{cases}
]

The associated Markov chain $X_t$ is called a random walk on the
$n$-cycle. The sates can be visualised as equally spaced nodes arranged
in a circle (see figure~ref{my:figure}).
end{example}

begin{figure}[htbp]
centering
begin{tikzpicture}
foreach i in {90,54,...,-234} {
draw[ultra thick] (i:2)--({i-36}:2);
}
foreach i in {90,18,...,-198} {
draw[fill=black] (i:2) circle (1.25mm);
}
foreach i in {54,-18,...,-234} {
draw[fill=white] (i:2) circle (1.25mm);
}
begin{scope}[xshift=5cm]
foreach i in {90,50,...,-230} {
draw[ultra thick] (i:2)--({i-40}:2);
draw[fill=black] (i:2) circle (1.25mm);
}
end{scope}
end{tikzpicture}
caption{Random walk on $mathbb{Z}_10$ is periodic, since every step
goes from an even state to an odd state, or vice-versa. Random
walk on $mathbb{Z}_9$ is aperiodic.}
label{my:figure}
end{figure}
Text after the figure.

clearpage
begin{example} Consider the graph $G$ following shown in figure 1.2. The transition matrix of a simple random walk $G$ is

begin{equation*}
P =
begin{bmatrix}[1.25]
0 & frac{1}{3} & frac{1}{3} & frac{1}{3} & 0 & 0 \
frac{1}{4} & 0 & frac{1}{4} & 0 & frac{1}{4} & frac{1}{4} \
frac{1}{4} & frac{1}{4} & 0 & frac{1}{4} & frac{1}{4} & 0 \
frac{1}{3} & 0 & frac{1}{3} & 0 & frac{1}{3} & 0 \
0 & frac{1}{4} & frac{1}{4} & frac{1}{4} & 0 & frac{1}{4} \
0 & frac{1}{2} & 0 & 0 & frac{1}{2} & 0 \
end{bmatrix}
end{equation*}

begin{figure}[htbp]
centering
%ffigbox[1.1FBwidth]{% <==============================================
caption{An example of a vertex set $V = lbrace 1, 2, 3, 4, 5, 6rbrace$ with $10$ edges.}
label{my:figure}%
%}% <===================================================================
{begin{tikzpicture}[bn/.style={circle,fill,draw,text=white,font=sffamily,minimum
size=1mm},every node/.append style={bn}]
path node (1) {1} -- ++ (50:2.5) node (2) {2} -- ++(-95:1.75) node (3) {3}
-- ++(-85:1.75) node (4) {4} -- ++(40:2.75) node (5) {5}
-- ++ (0,1.75) node (6) {6} ;
draw[thick] (1)--(2)--(6)--(5)--(4)--(1)--(3)--(5)--(2)--(3)--(4);
end{tikzpicture}}%
end{figure}
end{example}
end{document}


you get the resulting second figure/page:



second page






share|improve this answer


























  • thanks, precisely what I wanted.

    – Math
    Mar 1 at 11:52











  • @Math You are welcome!

    – Kurt
    Mar 1 at 17:05











  • please check my edited question, there is another problem similar to this

    – Math
    Mar 1 at 17:06











  • @Math you mean the caption of figure with ffigbox? Comment ffigbox and the closing }. That looks much better I guess?

    – Kurt
    Mar 1 at 17:19











  • sorry I wasn't available on the weakened. Yes, could you edit your answer adding the extra part, it will be very helpful :)

    – Math
    16 hours ago
















2














If I understand you right, you can use the following two lines in your preamble



usepackage{caption} % <================================================
captionsetup{width=0.8textwidth} % <==================================


to let the caption use only 80% of textwidth. See the documentation of package caption for more possibilitys to manipulate the layout of captions with typing texdoc caption on ypur console/terminal.



The complete code



documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{amsfonts, graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}

usepackage{caption} % <================================================
captionsetup{width=0.8textwidth} % <==================================

newtheorem{theorem}{Theorem}[section]
newtheorem{example}[theorem]{Example}


begin{document}

begin{example}
Consider a random walk on the $n$-cycle.
Let $Omega = mathbb{Z}_n = lbrace 0, 1, 2, cdots, n-1 rbrace$ be
the set of remainders modulo $n$. Also consider the transition matrix:
[
P(x,y) =
begin{cases}
frac{1}{2} & text{if } y=x+1;; (mod;n)\
frac{1}{2} & text{if } y=x-1;; (mod;n)\
0 & text{otherwise}
end{cases}
]

The associated Markov chain $X_t$ is called a random walk on the
$n$-cycle. The sates can be visualised as equally spaced nodes arranged
in a circle (see figure~ref{my:figure}). % <==========================
end{example}

begin{figure}[htbp]
centering
begin{tikzpicture}
foreach i in {90,54,...,-234} {
draw[ultra thick] (i:2)--({i-36}:2);
}
foreach i in {90,18,...,-198} {
draw[fill=black] (i:2) circle (1.25mm);
}
foreach i in {54,-18,...,-234} {
draw[fill=white] (i:2) circle (1.25mm);
}
begin{scope}[xshift=5cm]
foreach i in {90,50,...,-230} {
draw[ultra thick] (i:2)--({i-40}:2);
draw[fill=black] (i:2) circle (1.25mm);
}
end{scope}
end{tikzpicture}
caption{Random walk on $mathbb{Z}_10$ is periodic, since every step
goes from an even state to an odd state, or vice-versa. Random
walk on $mathbb{Z}_9$ is aperiodic.}
label{my:figure}
end{figure}
Text after the figure.
end{document}


gives you the result:



resulting pdf



EDIT:



With your second example (after commenting ffigbox, see markings <====== in code)



documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{amsfonts, graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}

usepackage{floatrow}

usepackage{caption} % <================================================
captionsetup{width=0.8textwidth} % <==================================

newtheorem{theorem}{Theorem}[section]
newtheorem{example}[theorem]{Example}


begin{document}

begin{example}
Consider a random walk on the $n$-cycle.
Let $Omega = mathbb{Z}_n = lbrace 0, 1, 2, cdots, n-1 rbrace$ be
the set of remainders modulo $n$. Also consider the transition matrix:
[
P(x,y) =
begin{cases}
frac{1}{2} & text{if } y=x+1;; (mod;n)\
frac{1}{2} & text{if } y=x-1;; (mod;n)\
0 & text{otherwise}
end{cases}
]

The associated Markov chain $X_t$ is called a random walk on the
$n$-cycle. The sates can be visualised as equally spaced nodes arranged
in a circle (see figure~ref{my:figure}).
end{example}

begin{figure}[htbp]
centering
begin{tikzpicture}
foreach i in {90,54,...,-234} {
draw[ultra thick] (i:2)--({i-36}:2);
}
foreach i in {90,18,...,-198} {
draw[fill=black] (i:2) circle (1.25mm);
}
foreach i in {54,-18,...,-234} {
draw[fill=white] (i:2) circle (1.25mm);
}
begin{scope}[xshift=5cm]
foreach i in {90,50,...,-230} {
draw[ultra thick] (i:2)--({i-40}:2);
draw[fill=black] (i:2) circle (1.25mm);
}
end{scope}
end{tikzpicture}
caption{Random walk on $mathbb{Z}_10$ is periodic, since every step
goes from an even state to an odd state, or vice-versa. Random
walk on $mathbb{Z}_9$ is aperiodic.}
label{my:figure}
end{figure}
Text after the figure.

clearpage
begin{example} Consider the graph $G$ following shown in figure 1.2. The transition matrix of a simple random walk $G$ is

begin{equation*}
P =
begin{bmatrix}[1.25]
0 & frac{1}{3} & frac{1}{3} & frac{1}{3} & 0 & 0 \
frac{1}{4} & 0 & frac{1}{4} & 0 & frac{1}{4} & frac{1}{4} \
frac{1}{4} & frac{1}{4} & 0 & frac{1}{4} & frac{1}{4} & 0 \
frac{1}{3} & 0 & frac{1}{3} & 0 & frac{1}{3} & 0 \
0 & frac{1}{4} & frac{1}{4} & frac{1}{4} & 0 & frac{1}{4} \
0 & frac{1}{2} & 0 & 0 & frac{1}{2} & 0 \
end{bmatrix}
end{equation*}

begin{figure}[htbp]
centering
%ffigbox[1.1FBwidth]{% <==============================================
caption{An example of a vertex set $V = lbrace 1, 2, 3, 4, 5, 6rbrace$ with $10$ edges.}
label{my:figure}%
%}% <===================================================================
{begin{tikzpicture}[bn/.style={circle,fill,draw,text=white,font=sffamily,minimum
size=1mm},every node/.append style={bn}]
path node (1) {1} -- ++ (50:2.5) node (2) {2} -- ++(-95:1.75) node (3) {3}
-- ++(-85:1.75) node (4) {4} -- ++(40:2.75) node (5) {5}
-- ++ (0,1.75) node (6) {6} ;
draw[thick] (1)--(2)--(6)--(5)--(4)--(1)--(3)--(5)--(2)--(3)--(4);
end{tikzpicture}}%
end{figure}
end{example}
end{document}


you get the resulting second figure/page:



second page






share|improve this answer


























  • thanks, precisely what I wanted.

    – Math
    Mar 1 at 11:52











  • @Math You are welcome!

    – Kurt
    Mar 1 at 17:05











  • please check my edited question, there is another problem similar to this

    – Math
    Mar 1 at 17:06











  • @Math you mean the caption of figure with ffigbox? Comment ffigbox and the closing }. That looks much better I guess?

    – Kurt
    Mar 1 at 17:19











  • sorry I wasn't available on the weakened. Yes, could you edit your answer adding the extra part, it will be very helpful :)

    – Math
    16 hours ago














2












2








2







If I understand you right, you can use the following two lines in your preamble



usepackage{caption} % <================================================
captionsetup{width=0.8textwidth} % <==================================


to let the caption use only 80% of textwidth. See the documentation of package caption for more possibilitys to manipulate the layout of captions with typing texdoc caption on ypur console/terminal.



The complete code



documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{amsfonts, graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}

usepackage{caption} % <================================================
captionsetup{width=0.8textwidth} % <==================================

newtheorem{theorem}{Theorem}[section]
newtheorem{example}[theorem]{Example}


begin{document}

begin{example}
Consider a random walk on the $n$-cycle.
Let $Omega = mathbb{Z}_n = lbrace 0, 1, 2, cdots, n-1 rbrace$ be
the set of remainders modulo $n$. Also consider the transition matrix:
[
P(x,y) =
begin{cases}
frac{1}{2} & text{if } y=x+1;; (mod;n)\
frac{1}{2} & text{if } y=x-1;; (mod;n)\
0 & text{otherwise}
end{cases}
]

The associated Markov chain $X_t$ is called a random walk on the
$n$-cycle. The sates can be visualised as equally spaced nodes arranged
in a circle (see figure~ref{my:figure}). % <==========================
end{example}

begin{figure}[htbp]
centering
begin{tikzpicture}
foreach i in {90,54,...,-234} {
draw[ultra thick] (i:2)--({i-36}:2);
}
foreach i in {90,18,...,-198} {
draw[fill=black] (i:2) circle (1.25mm);
}
foreach i in {54,-18,...,-234} {
draw[fill=white] (i:2) circle (1.25mm);
}
begin{scope}[xshift=5cm]
foreach i in {90,50,...,-230} {
draw[ultra thick] (i:2)--({i-40}:2);
draw[fill=black] (i:2) circle (1.25mm);
}
end{scope}
end{tikzpicture}
caption{Random walk on $mathbb{Z}_10$ is periodic, since every step
goes from an even state to an odd state, or vice-versa. Random
walk on $mathbb{Z}_9$ is aperiodic.}
label{my:figure}
end{figure}
Text after the figure.
end{document}


gives you the result:



resulting pdf



EDIT:



With your second example (after commenting ffigbox, see markings <====== in code)



documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{amsfonts, graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}

usepackage{floatrow}

usepackage{caption} % <================================================
captionsetup{width=0.8textwidth} % <==================================

newtheorem{theorem}{Theorem}[section]
newtheorem{example}[theorem]{Example}


begin{document}

begin{example}
Consider a random walk on the $n$-cycle.
Let $Omega = mathbb{Z}_n = lbrace 0, 1, 2, cdots, n-1 rbrace$ be
the set of remainders modulo $n$. Also consider the transition matrix:
[
P(x,y) =
begin{cases}
frac{1}{2} & text{if } y=x+1;; (mod;n)\
frac{1}{2} & text{if } y=x-1;; (mod;n)\
0 & text{otherwise}
end{cases}
]

The associated Markov chain $X_t$ is called a random walk on the
$n$-cycle. The sates can be visualised as equally spaced nodes arranged
in a circle (see figure~ref{my:figure}).
end{example}

begin{figure}[htbp]
centering
begin{tikzpicture}
foreach i in {90,54,...,-234} {
draw[ultra thick] (i:2)--({i-36}:2);
}
foreach i in {90,18,...,-198} {
draw[fill=black] (i:2) circle (1.25mm);
}
foreach i in {54,-18,...,-234} {
draw[fill=white] (i:2) circle (1.25mm);
}
begin{scope}[xshift=5cm]
foreach i in {90,50,...,-230} {
draw[ultra thick] (i:2)--({i-40}:2);
draw[fill=black] (i:2) circle (1.25mm);
}
end{scope}
end{tikzpicture}
caption{Random walk on $mathbb{Z}_10$ is periodic, since every step
goes from an even state to an odd state, or vice-versa. Random
walk on $mathbb{Z}_9$ is aperiodic.}
label{my:figure}
end{figure}
Text after the figure.

clearpage
begin{example} Consider the graph $G$ following shown in figure 1.2. The transition matrix of a simple random walk $G$ is

begin{equation*}
P =
begin{bmatrix}[1.25]
0 & frac{1}{3} & frac{1}{3} & frac{1}{3} & 0 & 0 \
frac{1}{4} & 0 & frac{1}{4} & 0 & frac{1}{4} & frac{1}{4} \
frac{1}{4} & frac{1}{4} & 0 & frac{1}{4} & frac{1}{4} & 0 \
frac{1}{3} & 0 & frac{1}{3} & 0 & frac{1}{3} & 0 \
0 & frac{1}{4} & frac{1}{4} & frac{1}{4} & 0 & frac{1}{4} \
0 & frac{1}{2} & 0 & 0 & frac{1}{2} & 0 \
end{bmatrix}
end{equation*}

begin{figure}[htbp]
centering
%ffigbox[1.1FBwidth]{% <==============================================
caption{An example of a vertex set $V = lbrace 1, 2, 3, 4, 5, 6rbrace$ with $10$ edges.}
label{my:figure}%
%}% <===================================================================
{begin{tikzpicture}[bn/.style={circle,fill,draw,text=white,font=sffamily,minimum
size=1mm},every node/.append style={bn}]
path node (1) {1} -- ++ (50:2.5) node (2) {2} -- ++(-95:1.75) node (3) {3}
-- ++(-85:1.75) node (4) {4} -- ++(40:2.75) node (5) {5}
-- ++ (0,1.75) node (6) {6} ;
draw[thick] (1)--(2)--(6)--(5)--(4)--(1)--(3)--(5)--(2)--(3)--(4);
end{tikzpicture}}%
end{figure}
end{example}
end{document}


you get the resulting second figure/page:



second page






share|improve this answer















If I understand you right, you can use the following two lines in your preamble



usepackage{caption} % <================================================
captionsetup{width=0.8textwidth} % <==================================


to let the caption use only 80% of textwidth. See the documentation of package caption for more possibilitys to manipulate the layout of captions with typing texdoc caption on ypur console/terminal.



The complete code



documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{amsfonts, graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}

usepackage{caption} % <================================================
captionsetup{width=0.8textwidth} % <==================================

newtheorem{theorem}{Theorem}[section]
newtheorem{example}[theorem]{Example}


begin{document}

begin{example}
Consider a random walk on the $n$-cycle.
Let $Omega = mathbb{Z}_n = lbrace 0, 1, 2, cdots, n-1 rbrace$ be
the set of remainders modulo $n$. Also consider the transition matrix:
[
P(x,y) =
begin{cases}
frac{1}{2} & text{if } y=x+1;; (mod;n)\
frac{1}{2} & text{if } y=x-1;; (mod;n)\
0 & text{otherwise}
end{cases}
]

The associated Markov chain $X_t$ is called a random walk on the
$n$-cycle. The sates can be visualised as equally spaced nodes arranged
in a circle (see figure~ref{my:figure}). % <==========================
end{example}

begin{figure}[htbp]
centering
begin{tikzpicture}
foreach i in {90,54,...,-234} {
draw[ultra thick] (i:2)--({i-36}:2);
}
foreach i in {90,18,...,-198} {
draw[fill=black] (i:2) circle (1.25mm);
}
foreach i in {54,-18,...,-234} {
draw[fill=white] (i:2) circle (1.25mm);
}
begin{scope}[xshift=5cm]
foreach i in {90,50,...,-230} {
draw[ultra thick] (i:2)--({i-40}:2);
draw[fill=black] (i:2) circle (1.25mm);
}
end{scope}
end{tikzpicture}
caption{Random walk on $mathbb{Z}_10$ is periodic, since every step
goes from an even state to an odd state, or vice-versa. Random
walk on $mathbb{Z}_9$ is aperiodic.}
label{my:figure}
end{figure}
Text after the figure.
end{document}


gives you the result:



resulting pdf



EDIT:



With your second example (after commenting ffigbox, see markings <====== in code)



documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{amsfonts, graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}

usepackage{floatrow}

usepackage{caption} % <================================================
captionsetup{width=0.8textwidth} % <==================================

newtheorem{theorem}{Theorem}[section]
newtheorem{example}[theorem]{Example}


begin{document}

begin{example}
Consider a random walk on the $n$-cycle.
Let $Omega = mathbb{Z}_n = lbrace 0, 1, 2, cdots, n-1 rbrace$ be
the set of remainders modulo $n$. Also consider the transition matrix:
[
P(x,y) =
begin{cases}
frac{1}{2} & text{if } y=x+1;; (mod;n)\
frac{1}{2} & text{if } y=x-1;; (mod;n)\
0 & text{otherwise}
end{cases}
]

The associated Markov chain $X_t$ is called a random walk on the
$n$-cycle. The sates can be visualised as equally spaced nodes arranged
in a circle (see figure~ref{my:figure}).
end{example}

begin{figure}[htbp]
centering
begin{tikzpicture}
foreach i in {90,54,...,-234} {
draw[ultra thick] (i:2)--({i-36}:2);
}
foreach i in {90,18,...,-198} {
draw[fill=black] (i:2) circle (1.25mm);
}
foreach i in {54,-18,...,-234} {
draw[fill=white] (i:2) circle (1.25mm);
}
begin{scope}[xshift=5cm]
foreach i in {90,50,...,-230} {
draw[ultra thick] (i:2)--({i-40}:2);
draw[fill=black] (i:2) circle (1.25mm);
}
end{scope}
end{tikzpicture}
caption{Random walk on $mathbb{Z}_10$ is periodic, since every step
goes from an even state to an odd state, or vice-versa. Random
walk on $mathbb{Z}_9$ is aperiodic.}
label{my:figure}
end{figure}
Text after the figure.

clearpage
begin{example} Consider the graph $G$ following shown in figure 1.2. The transition matrix of a simple random walk $G$ is

begin{equation*}
P =
begin{bmatrix}[1.25]
0 & frac{1}{3} & frac{1}{3} & frac{1}{3} & 0 & 0 \
frac{1}{4} & 0 & frac{1}{4} & 0 & frac{1}{4} & frac{1}{4} \
frac{1}{4} & frac{1}{4} & 0 & frac{1}{4} & frac{1}{4} & 0 \
frac{1}{3} & 0 & frac{1}{3} & 0 & frac{1}{3} & 0 \
0 & frac{1}{4} & frac{1}{4} & frac{1}{4} & 0 & frac{1}{4} \
0 & frac{1}{2} & 0 & 0 & frac{1}{2} & 0 \
end{bmatrix}
end{equation*}

begin{figure}[htbp]
centering
%ffigbox[1.1FBwidth]{% <==============================================
caption{An example of a vertex set $V = lbrace 1, 2, 3, 4, 5, 6rbrace$ with $10$ edges.}
label{my:figure}%
%}% <===================================================================
{begin{tikzpicture}[bn/.style={circle,fill,draw,text=white,font=sffamily,minimum
size=1mm},every node/.append style={bn}]
path node (1) {1} -- ++ (50:2.5) node (2) {2} -- ++(-95:1.75) node (3) {3}
-- ++(-85:1.75) node (4) {4} -- ++(40:2.75) node (5) {5}
-- ++ (0,1.75) node (6) {6} ;
draw[thick] (1)--(2)--(6)--(5)--(4)--(1)--(3)--(5)--(2)--(3)--(4);
end{tikzpicture}}%
end{figure}
end{example}
end{document}


you get the resulting second figure/page:



second page







share|improve this answer














share|improve this answer



share|improve this answer








edited 16 hours ago

























answered Feb 27 at 17:30









KurtKurt

38.5k848162




38.5k848162













  • thanks, precisely what I wanted.

    – Math
    Mar 1 at 11:52











  • @Math You are welcome!

    – Kurt
    Mar 1 at 17:05











  • please check my edited question, there is another problem similar to this

    – Math
    Mar 1 at 17:06











  • @Math you mean the caption of figure with ffigbox? Comment ffigbox and the closing }. That looks much better I guess?

    – Kurt
    Mar 1 at 17:19











  • sorry I wasn't available on the weakened. Yes, could you edit your answer adding the extra part, it will be very helpful :)

    – Math
    16 hours ago



















  • thanks, precisely what I wanted.

    – Math
    Mar 1 at 11:52











  • @Math You are welcome!

    – Kurt
    Mar 1 at 17:05











  • please check my edited question, there is another problem similar to this

    – Math
    Mar 1 at 17:06











  • @Math you mean the caption of figure with ffigbox? Comment ffigbox and the closing }. That looks much better I guess?

    – Kurt
    Mar 1 at 17:19











  • sorry I wasn't available on the weakened. Yes, could you edit your answer adding the extra part, it will be very helpful :)

    – Math
    16 hours ago

















thanks, precisely what I wanted.

– Math
Mar 1 at 11:52





thanks, precisely what I wanted.

– Math
Mar 1 at 11:52













@Math You are welcome!

– Kurt
Mar 1 at 17:05





@Math You are welcome!

– Kurt
Mar 1 at 17:05













please check my edited question, there is another problem similar to this

– Math
Mar 1 at 17:06





please check my edited question, there is another problem similar to this

– Math
Mar 1 at 17:06













@Math you mean the caption of figure with ffigbox? Comment ffigbox and the closing }. That looks much better I guess?

– Kurt
Mar 1 at 17:19





@Math you mean the caption of figure with ffigbox? Comment ffigbox and the closing }. That looks much better I guess?

– Kurt
Mar 1 at 17:19













sorry I wasn't available on the weakened. Yes, could you edit your answer adding the extra part, it will be very helpful :)

– Math
16 hours ago





sorry I wasn't available on the weakened. Yes, could you edit your answer adding the extra part, it will be very helpful :)

– Math
16 hours ago











2














If I've well understood what you want, this is easy with the ffigbox command from floatrow, which gives full control on the caption width:



documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}
newtheorem{theorem}{Theorem}[section]
newtheorem{example}[theorem]{Example}
usepackage{floatrow}

begin{document}

begin{example}
Consider a random walk on the $n$-cycle. Let $Omega = mathbb{Z}_n = lbrace 0, 1, 2, cdots, n-1 rbrace$ be the set of remainders modulo $n$. Also consider the transition matrix:
[
P(x,y) =
begin{cases}
frac{1}{2} & text{if } y=x+1 pmod n\
frac{1}{2} & text{if } y=x-1pmod n\
0 & text{otherwise}
end{cases}
]

The associated Markov chain $X_t$ is called a random walk on the $n$-cycle. The states can be visualised as equally spaced nodes arranged in a circle(see figure 1.1)
end{example}

begin{figure}[htbp]
centering
ffigbox[1.1FBwidth]{%
caption{Random walk on $mathbb{Z}_10$ is periodic, since every step
goes from an even state to an odd state, or vice-versa. Random
walk on $mathbb{Z}_9$ is aperiodic.}
label{my:figure}}%
{begin{tikzpicture}
foreach i in {90,54,...,-234} {
draw[ultra thick] (i:2)--({i-36}:2);
}
foreach i in {90,18,...,-198} {
draw[fill=black] (i:2) circle (1.25mm);
}
foreach i in {54,-18,...,-234} {
draw[fill=white] (i:2) circle (1.25mm);
}
begin{scope}[xshift=5cm]
foreach i in {90,50,...,-230} {
draw[ultra thick] (i:2)--({i-40}:2);
draw[fill=black] (i:2) circle (1.25mm);
}
end{scope}
end{tikzpicture}}%
end{figure}

end{document}


enter image description here






share|improve this answer
























  • +1 for another solution however Kurt beat you to it!

    – Math
    Mar 1 at 11:57













  • I'm not competing :o). The advantage with the solution with ffigbox, from my point of view, is that the caption width can be automatically calculated in function of the figure natural width.

    – Bernard
    Mar 1 at 12:07











  • I understand. the reason I liked Kurt's answer is because for this particular problem I will only need to adjust one number to get my desired output however the drawback is, with another figure, if it doesn't have the same dimensions as the figure above, the caption will be off

    – Math
    Mar 1 at 12:13











  • that's where your solution comes in handy I believe.

    – Math
    Mar 1 at 12:13











  • To clarify, will your method work for all figures?

    – Math
    Mar 1 at 12:17
















2














If I've well understood what you want, this is easy with the ffigbox command from floatrow, which gives full control on the caption width:



documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}
newtheorem{theorem}{Theorem}[section]
newtheorem{example}[theorem]{Example}
usepackage{floatrow}

begin{document}

begin{example}
Consider a random walk on the $n$-cycle. Let $Omega = mathbb{Z}_n = lbrace 0, 1, 2, cdots, n-1 rbrace$ be the set of remainders modulo $n$. Also consider the transition matrix:
[
P(x,y) =
begin{cases}
frac{1}{2} & text{if } y=x+1 pmod n\
frac{1}{2} & text{if } y=x-1pmod n\
0 & text{otherwise}
end{cases}
]

The associated Markov chain $X_t$ is called a random walk on the $n$-cycle. The states can be visualised as equally spaced nodes arranged in a circle(see figure 1.1)
end{example}

begin{figure}[htbp]
centering
ffigbox[1.1FBwidth]{%
caption{Random walk on $mathbb{Z}_10$ is periodic, since every step
goes from an even state to an odd state, or vice-versa. Random
walk on $mathbb{Z}_9$ is aperiodic.}
label{my:figure}}%
{begin{tikzpicture}
foreach i in {90,54,...,-234} {
draw[ultra thick] (i:2)--({i-36}:2);
}
foreach i in {90,18,...,-198} {
draw[fill=black] (i:2) circle (1.25mm);
}
foreach i in {54,-18,...,-234} {
draw[fill=white] (i:2) circle (1.25mm);
}
begin{scope}[xshift=5cm]
foreach i in {90,50,...,-230} {
draw[ultra thick] (i:2)--({i-40}:2);
draw[fill=black] (i:2) circle (1.25mm);
}
end{scope}
end{tikzpicture}}%
end{figure}

end{document}


enter image description here






share|improve this answer
























  • +1 for another solution however Kurt beat you to it!

    – Math
    Mar 1 at 11:57













  • I'm not competing :o). The advantage with the solution with ffigbox, from my point of view, is that the caption width can be automatically calculated in function of the figure natural width.

    – Bernard
    Mar 1 at 12:07











  • I understand. the reason I liked Kurt's answer is because for this particular problem I will only need to adjust one number to get my desired output however the drawback is, with another figure, if it doesn't have the same dimensions as the figure above, the caption will be off

    – Math
    Mar 1 at 12:13











  • that's where your solution comes in handy I believe.

    – Math
    Mar 1 at 12:13











  • To clarify, will your method work for all figures?

    – Math
    Mar 1 at 12:17














2












2








2







If I've well understood what you want, this is easy with the ffigbox command from floatrow, which gives full control on the caption width:



documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}
newtheorem{theorem}{Theorem}[section]
newtheorem{example}[theorem]{Example}
usepackage{floatrow}

begin{document}

begin{example}
Consider a random walk on the $n$-cycle. Let $Omega = mathbb{Z}_n = lbrace 0, 1, 2, cdots, n-1 rbrace$ be the set of remainders modulo $n$. Also consider the transition matrix:
[
P(x,y) =
begin{cases}
frac{1}{2} & text{if } y=x+1 pmod n\
frac{1}{2} & text{if } y=x-1pmod n\
0 & text{otherwise}
end{cases}
]

The associated Markov chain $X_t$ is called a random walk on the $n$-cycle. The states can be visualised as equally spaced nodes arranged in a circle(see figure 1.1)
end{example}

begin{figure}[htbp]
centering
ffigbox[1.1FBwidth]{%
caption{Random walk on $mathbb{Z}_10$ is periodic, since every step
goes from an even state to an odd state, or vice-versa. Random
walk on $mathbb{Z}_9$ is aperiodic.}
label{my:figure}}%
{begin{tikzpicture}
foreach i in {90,54,...,-234} {
draw[ultra thick] (i:2)--({i-36}:2);
}
foreach i in {90,18,...,-198} {
draw[fill=black] (i:2) circle (1.25mm);
}
foreach i in {54,-18,...,-234} {
draw[fill=white] (i:2) circle (1.25mm);
}
begin{scope}[xshift=5cm]
foreach i in {90,50,...,-230} {
draw[ultra thick] (i:2)--({i-40}:2);
draw[fill=black] (i:2) circle (1.25mm);
}
end{scope}
end{tikzpicture}}%
end{figure}

end{document}


enter image description here






share|improve this answer













If I've well understood what you want, this is easy with the ffigbox command from floatrow, which gives full control on the caption width:



documentclass[11pt, a4paper]{report}
usepackage{bm}
usepackage{graphicx, verbatim, amsmath,amssymb, amsthm}
usepackage{color}
usepackage{array}
usepackage{setspace}% if you must (for double spacing thesis)
usepackage{fancyhdr}
usepackage{enumitem}
usepackage{tikz}
usepackage{parskip}
usepackage{lipsum}
newtheorem{theorem}{Theorem}[section]
newtheorem{example}[theorem]{Example}
usepackage{floatrow}

begin{document}

begin{example}
Consider a random walk on the $n$-cycle. Let $Omega = mathbb{Z}_n = lbrace 0, 1, 2, cdots, n-1 rbrace$ be the set of remainders modulo $n$. Also consider the transition matrix:
[
P(x,y) =
begin{cases}
frac{1}{2} & text{if } y=x+1 pmod n\
frac{1}{2} & text{if } y=x-1pmod n\
0 & text{otherwise}
end{cases}
]

The associated Markov chain $X_t$ is called a random walk on the $n$-cycle. The states can be visualised as equally spaced nodes arranged in a circle(see figure 1.1)
end{example}

begin{figure}[htbp]
centering
ffigbox[1.1FBwidth]{%
caption{Random walk on $mathbb{Z}_10$ is periodic, since every step
goes from an even state to an odd state, or vice-versa. Random
walk on $mathbb{Z}_9$ is aperiodic.}
label{my:figure}}%
{begin{tikzpicture}
foreach i in {90,54,...,-234} {
draw[ultra thick] (i:2)--({i-36}:2);
}
foreach i in {90,18,...,-198} {
draw[fill=black] (i:2) circle (1.25mm);
}
foreach i in {54,-18,...,-234} {
draw[fill=white] (i:2) circle (1.25mm);
}
begin{scope}[xshift=5cm]
foreach i in {90,50,...,-230} {
draw[ultra thick] (i:2)--({i-40}:2);
draw[fill=black] (i:2) circle (1.25mm);
}
end{scope}
end{tikzpicture}}%
end{figure}

end{document}


enter image description here







share|improve this answer












share|improve this answer



share|improve this answer










answered Feb 27 at 17:21









BernardBernard

172k776204




172k776204













  • +1 for another solution however Kurt beat you to it!

    – Math
    Mar 1 at 11:57













  • I'm not competing :o). The advantage with the solution with ffigbox, from my point of view, is that the caption width can be automatically calculated in function of the figure natural width.

    – Bernard
    Mar 1 at 12:07











  • I understand. the reason I liked Kurt's answer is because for this particular problem I will only need to adjust one number to get my desired output however the drawback is, with another figure, if it doesn't have the same dimensions as the figure above, the caption will be off

    – Math
    Mar 1 at 12:13











  • that's where your solution comes in handy I believe.

    – Math
    Mar 1 at 12:13











  • To clarify, will your method work for all figures?

    – Math
    Mar 1 at 12:17



















  • +1 for another solution however Kurt beat you to it!

    – Math
    Mar 1 at 11:57













  • I'm not competing :o). The advantage with the solution with ffigbox, from my point of view, is that the caption width can be automatically calculated in function of the figure natural width.

    – Bernard
    Mar 1 at 12:07











  • I understand. the reason I liked Kurt's answer is because for this particular problem I will only need to adjust one number to get my desired output however the drawback is, with another figure, if it doesn't have the same dimensions as the figure above, the caption will be off

    – Math
    Mar 1 at 12:13











  • that's where your solution comes in handy I believe.

    – Math
    Mar 1 at 12:13











  • To clarify, will your method work for all figures?

    – Math
    Mar 1 at 12:17

















+1 for another solution however Kurt beat you to it!

– Math
Mar 1 at 11:57







+1 for another solution however Kurt beat you to it!

– Math
Mar 1 at 11:57















I'm not competing :o). The advantage with the solution with ffigbox, from my point of view, is that the caption width can be automatically calculated in function of the figure natural width.

– Bernard
Mar 1 at 12:07





I'm not competing :o). The advantage with the solution with ffigbox, from my point of view, is that the caption width can be automatically calculated in function of the figure natural width.

– Bernard
Mar 1 at 12:07













I understand. the reason I liked Kurt's answer is because for this particular problem I will only need to adjust one number to get my desired output however the drawback is, with another figure, if it doesn't have the same dimensions as the figure above, the caption will be off

– Math
Mar 1 at 12:13





I understand. the reason I liked Kurt's answer is because for this particular problem I will only need to adjust one number to get my desired output however the drawback is, with another figure, if it doesn't have the same dimensions as the figure above, the caption will be off

– Math
Mar 1 at 12:13













that's where your solution comes in handy I believe.

– Math
Mar 1 at 12:13





that's where your solution comes in handy I believe.

– Math
Mar 1 at 12:13













To clarify, will your method work for all figures?

– Math
Mar 1 at 12:17





To clarify, will your method work for all figures?

– Math
Mar 1 at 12:17










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