Power LED from 3.3V Power Pin without ResistorLED resistor questionWiring RGB LED'sbattery power for RPI and...
Pressure to defend the relevance of one's area of mathematics
How to creep the reader out with what seems like a normal person?
Would "lab meat" be able to feed a much larger global population
Why do freehub and cassette have only one position that matches?
How do I tell my manager that his code review comment is wrong?
Airbnb - host wants to reduce rooms, can we get refund?
Did we get closer to another plane than we were supposed to, or was the pilot just protecting our delicate sensibilities?
Was the ancestor of SCSI, the SASI protocol, nothing more than a draft?
How can I close a gap between my fence and my neighbor's that's on his side of the property line?
Why are notes ordered like they are on a piano?
Historically, were women trained for obligatory wars? Or did they serve some other military function?
Survey Confirmation - Emphasize the question or the answer?
Transfer over $10k
Junior developer struggles: how to communicate with management?
Disabling Resource Governor in SQL Server
My ID is expired, can I fly to the Bahamas with my passport
Can commander tax be proliferated?
If 1. e4 c6 is considered as a sound defense for black, why is 1. c3 so rare?
Copy line and insert it in a new position with sed or awk
How did Captain America use this power?
How could a planet have most of its water in the atmosphere?
Can I use 1000v rectifier diodes instead of 600v rectifier diodes?
Why is Thanos so tough at the beginning of "Avengers: Endgame"?
If Earth is tilted, why is Polaris always above the same spot?
Power LED from 3.3V Power Pin without Resistor
LED resistor questionWiring RGB LED'sbattery power for RPI and IR LED bank?PWM-based controlling an LED-strip using transistors, circuitry problemsTurn TouchScreen Backlight Off after ShutdownUsing jumper cables to turn on LEDsRaspberry PI + DS1820 + Led. Resistor confusion (series or parallel?)Control 5m of WS2812 LED Strip: Wire it uphelp reconstructing blinking LED circuit that required GPIO #17 pin low rather than highProblem with LED blink program on PiPowering a sensor using an external power supply board
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}
I tried wiring one white LED to the 3.3V pin on a Pi Zero W with a 330 Ohm resistor but it's not as bright as I would like. If I wire it up without a resister I get a good amount of brightness. Is that a viable solution? Or should I try a smaller resistor?
If it matters, the power supply is a standard 5V 2.5A supply like this one. The LED is this one.
power led
add a comment |
I tried wiring one white LED to the 3.3V pin on a Pi Zero W with a 330 Ohm resistor but it's not as bright as I would like. If I wire it up without a resister I get a good amount of brightness. Is that a viable solution? Or should I try a smaller resistor?
If it matters, the power supply is a standard 5V 2.5A supply like this one. The LED is this one.
power led
1
I'd recommend 10Ohm resistor
– Jaromanda X
4 hours ago
add a comment |
I tried wiring one white LED to the 3.3V pin on a Pi Zero W with a 330 Ohm resistor but it's not as bright as I would like. If I wire it up without a resister I get a good amount of brightness. Is that a viable solution? Or should I try a smaller resistor?
If it matters, the power supply is a standard 5V 2.5A supply like this one. The LED is this one.
power led
I tried wiring one white LED to the 3.3V pin on a Pi Zero W with a 330 Ohm resistor but it's not as bright as I would like. If I wire it up without a resister I get a good amount of brightness. Is that a viable solution? Or should I try a smaller resistor?
If it matters, the power supply is a standard 5V 2.5A supply like this one. The LED is this one.
power led
power led
asked 4 hours ago
MichaelMichael
1554
1554
1
I'd recommend 10Ohm resistor
– Jaromanda X
4 hours ago
add a comment |
1
I'd recommend 10Ohm resistor
– Jaromanda X
4 hours ago
1
1
I'd recommend 10Ohm resistor
– Jaromanda X
4 hours ago
I'd recommend 10Ohm resistor
– Jaromanda X
4 hours ago
add a comment |
1 Answer
1
active
oldest
votes
You need to consider that the forward voltage of a white LED is likely in the range of 3.0 V to 3.2 V (according to the linked article). Assuming the best case of 3.0 V and a resistor of 330 Ohms and using Ohm's law R = U / I we find that the current is about 1 mA and thus the brightness of the LED is rather low. Decreasing the resistor will help to some degree but be aware that this is borderline in any case. Say 33 Ohms will get you about 10 mA which might be ok. Best bet is to use the 5 V instead and design the resistor in such a fashion that the current suits the safe operational range of the LED.
Connecting a LED to a voltage source without a current limiting resistor is not a safe way of operating a LED. It is therefore not advisable to do so.
Find a more elaborate description of the calculations here; even though it is aiming at GPIO pins the physics still apply.
Great input - thanks so much!
– Michael
4 hours ago
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("schematics", function () {
StackExchange.schematics.init();
});
}, "cicuitlab");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "447"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fraspberrypi.stackexchange.com%2fquestions%2f98051%2fpower-led-from-3-3v-power-pin-without-resistor%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You need to consider that the forward voltage of a white LED is likely in the range of 3.0 V to 3.2 V (according to the linked article). Assuming the best case of 3.0 V and a resistor of 330 Ohms and using Ohm's law R = U / I we find that the current is about 1 mA and thus the brightness of the LED is rather low. Decreasing the resistor will help to some degree but be aware that this is borderline in any case. Say 33 Ohms will get you about 10 mA which might be ok. Best bet is to use the 5 V instead and design the resistor in such a fashion that the current suits the safe operational range of the LED.
Connecting a LED to a voltage source without a current limiting resistor is not a safe way of operating a LED. It is therefore not advisable to do so.
Find a more elaborate description of the calculations here; even though it is aiming at GPIO pins the physics still apply.
Great input - thanks so much!
– Michael
4 hours ago
add a comment |
You need to consider that the forward voltage of a white LED is likely in the range of 3.0 V to 3.2 V (according to the linked article). Assuming the best case of 3.0 V and a resistor of 330 Ohms and using Ohm's law R = U / I we find that the current is about 1 mA and thus the brightness of the LED is rather low. Decreasing the resistor will help to some degree but be aware that this is borderline in any case. Say 33 Ohms will get you about 10 mA which might be ok. Best bet is to use the 5 V instead and design the resistor in such a fashion that the current suits the safe operational range of the LED.
Connecting a LED to a voltage source without a current limiting resistor is not a safe way of operating a LED. It is therefore not advisable to do so.
Find a more elaborate description of the calculations here; even though it is aiming at GPIO pins the physics still apply.
Great input - thanks so much!
– Michael
4 hours ago
add a comment |
You need to consider that the forward voltage of a white LED is likely in the range of 3.0 V to 3.2 V (according to the linked article). Assuming the best case of 3.0 V and a resistor of 330 Ohms and using Ohm's law R = U / I we find that the current is about 1 mA and thus the brightness of the LED is rather low. Decreasing the resistor will help to some degree but be aware that this is borderline in any case. Say 33 Ohms will get you about 10 mA which might be ok. Best bet is to use the 5 V instead and design the resistor in such a fashion that the current suits the safe operational range of the LED.
Connecting a LED to a voltage source without a current limiting resistor is not a safe way of operating a LED. It is therefore not advisable to do so.
Find a more elaborate description of the calculations here; even though it is aiming at GPIO pins the physics still apply.
You need to consider that the forward voltage of a white LED is likely in the range of 3.0 V to 3.2 V (according to the linked article). Assuming the best case of 3.0 V and a resistor of 330 Ohms and using Ohm's law R = U / I we find that the current is about 1 mA and thus the brightness of the LED is rather low. Decreasing the resistor will help to some degree but be aware that this is borderline in any case. Say 33 Ohms will get you about 10 mA which might be ok. Best bet is to use the 5 V instead and design the resistor in such a fashion that the current suits the safe operational range of the LED.
Connecting a LED to a voltage source without a current limiting resistor is not a safe way of operating a LED. It is therefore not advisable to do so.
Find a more elaborate description of the calculations here; even though it is aiming at GPIO pins the physics still apply.
answered 4 hours ago
Ghanima♦Ghanima
12.6k114080
12.6k114080
Great input - thanks so much!
– Michael
4 hours ago
add a comment |
Great input - thanks so much!
– Michael
4 hours ago
Great input - thanks so much!
– Michael
4 hours ago
Great input - thanks so much!
– Michael
4 hours ago
add a comment |
Thanks for contributing an answer to Raspberry Pi Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fraspberrypi.stackexchange.com%2fquestions%2f98051%2fpower-led-from-3-3v-power-pin-without-resistor%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
I'd recommend 10Ohm resistor
– Jaromanda X
4 hours ago